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本帖最后由 soso001 于 2014-12-17 14:53 编辑 # a- [* H6 i! r
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不好意思,打错了个字母,呵呵呵!
7 Y, J" e% N+ O大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示+ {- x! \. k) a' I7 z
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!2 J# [7 r3 n" O u/ K+ Y
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j,k,nstep,c, scheduleteps,mincomptime:integer;- I6 d/ T* ]4 C& |, S
M:string;
" X3 c" t6 [/ S' t* [% G) U selecTab:table[integer,integer,integer,string];
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initorders;
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scheduledorders.delete;
$ Z/ h' T; j9 O9 U4 V% K seletTab.create;2 Q; l6 o9 I6 s- O0 F" C) L
% X9 B: a% N' x9 U8 c" H1 q orders.initialize({2,1}..{2,*},0);
$ X Q7 U- m9 ~ i( G5 x; R orders.initialize({4,1}..{4,*},0);# q, t+ g+ h& y9 X; F; G
for j:=1 to numorders loop
) p7 a; l/ }) W% l/ C orders[5,j]:=orders[1,j][2,1];6 G# f# @( B- R% [9 l# J
next;
. H7 C" h8 D Y# h, E occres.initialize({1,1}..{1,*},0);
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for scheduledsteps:=1 to numsteps loop --
6 z: Y' [2 x) U: S# E& Q selectab.delete;
# Q8 W; a& @% B* l3 V k:=1;
+ u" F; w3 l8 A$ i* H$ W* W% w( U for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
; j) h; `' D/ d- q' e if nstep<=orders[3,j] then
) ?- X6 |! t/ r: l. q selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];# o: Z9 B% L. }$ h
k:=k+1;& p. k2 _, d2 v* `9 [" C
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end;
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mincomptime:=selecttab.min({3,1}..{3,*});
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3 g$ T2 X P ]" _* } from j:=1 until j>selectab.ydim loop: W$ r3 N" m7 L' z1 D+ x
' T2 m7 I' M. @5 J if selectab[2,j]<mincomptime then0 M3 J, Y7 c# D/ a8 `, u+ q) K! y
j:=j+1;) E: \: \+ O v; \. c
else" W" B' H5 T& Y( C; n& N
selecttab.cutrow(j);
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end;
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j:=selectionrule(selecttab);' j- e3 e( P3 b" E7 o0 ^5 d
" R9 I% l4 f( B4 {4 U* @3 N nstep;+orders[2.j]+1;: H$ V- I1 F0 O0 ?' s
orders[2,j]:=nstep;
( o* W; o% x7 g9 H m:=orders[1,j][1,nstep];! R) G( j; Y4 r4 q' _- p
c:=orders[5,j]& }) P L; W$ u+ ?/ B8 C" L2 P
occres[1,m]:=c;
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$ O U; E1 c7 `" ~4 ` --jieguo:start,end,res,job,step
3 }3 ] m) z) P/ j scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
- A( S" L9 X( B4 I for k:=1 to numorders loop
7 d5 a+ p1 Y9 L2 o9 h nstep:=orders[2,k]+1;5 m' [1 f/ j) v* z7 \
+ p# a( Q" F+ ` if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then- q# D, S9 b& H! b: w0 P; O
orders[4,k]:=max(c,orders[4,k]);% T9 \% W+ t0 K) m R
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;5 ~4 Y2 {3 K& j' ^2 J8 L
next;
# Y4 T) U2 L& b3 {" x4 \5 }' } nstep:=orders[2,j]+1:
. d# P* x: F! V+ } if nstep<=orders[3,j]' N5 ~- P/ T3 M# r
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then
& ^ S1 s! C2 e$ T1 x7 {: r8 _ orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);, g* ]; u3 J4 z' Q- `. {& ~
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
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next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;
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