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本帖最后由 soso001 于 2014-12-17 14:53 编辑 Y$ f4 v2 h' E) z: d, c& x# D
; g. H1 v9 E7 [/ T+ m7 Q不好意思,打错了个字母,呵呵呵!
1 N2 m/ k5 N H5 y6 H3 @# m大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
! P6 i) l( G v @" C, h6 ?. X% D“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;. _% e" n2 r8 o9 N' ~
M:string;9 t9 m; b- Z' @" X3 q
selecTab:table[integer,integer,integer,string];
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initorders;6 h3 L t- ?6 o- y& ]
& c0 S: a3 E" I7 w; t( \# k% j8 k scheduledorders.delete;
( F3 L3 o/ U' R7 j8 R" t seletTab.create;
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: W. R; [- E3 A3 e N4 o1 p orders.initialize({2,1}..{2,*},0);$ P. R# w$ t: o) A8 h1 y ~
orders.initialize({4,1}..{4,*},0);
. B$ x) h% {) m, k6 n for j:=1 to numorders loop4 g( M! y0 t, H" Q
orders[5,j]:=orders[1,j][2,1];6 |/ s* v9 b& j7 i, q
next;8 {2 U% s ~8 q# n. U
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN
) j0 j0 B0 Y" s) b for scheduledsteps:=1 to numsteps loop --
# \; d6 Q/ n% Z" e8 G- @( Y- d" O9 ^ selectab.delete;
/ ?3 A- S% \8 n) O k:=1;
$ M. ] W; s+ P5 A' u for j:=1 to numorders loop
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nstep:=orders[2,j]+1;" J0 N7 Q* q! Y: L$ [( z# D! c1 s% h
if nstep<=orders[3,j] then
/ ^3 R- @! t6 ?0 s selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep]; y' O' A0 s" c9 ~$ y% A
k:=k+1;
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end;
' h+ a( Q5 q: P( Q1 ^! u5 v next;
@: D/ o" `, [9 `% w mincomptime:=selecttab.min({3,1}..{3,*});6 P0 z: i( I4 e6 n
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from j:=1 until j>selectab.ydim loop
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6 R# Q: O6 R& R1 C if selectab[2,j]<mincomptime then
$ k8 o a1 x) K j:=j+1;
" @/ h+ i" E" M1 k8 O+ C else
. l% t5 j+ o/ D selecttab.cutrow(j);
' G- v+ t# i( j2 x( e5 X& o" Y end;. }! {: k$ d, J2 v. l
end;
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j:=selectionrule(selecttab);
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orders[2,j]:=nstep;; |6 o4 k3 h( N0 B- V4 _ \1 c/ Z
m:=orders[1,j][1,nstep];8 V5 v8 L) i5 T+ ]
c:=orders[5,j]
, D5 _6 V' t | occres[1,m]:=c;6 [# h) y7 h1 F1 g; T% r3 C
! C6 Z, Q. Y' V --jieguo:start,end,res,job,step
% P* F- h# k D: a1 \. s7 Q scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
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nstep:=orders[2,k]+1;
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/ |" ^: _, g6 M" ~' ~1 G- I if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
% Z0 r3 }! d$ |2 Z# ? orders[4,k]:=max(c,orders[4,k]);8 Q2 V% E; w' ^6 `
--
9 g. s- [" {0 I9 u0 K% l" D3 V6 [( s orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
% c+ e: s, o* @) P( ^ --
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next;
9 E4 G: V8 I; \! J) \% L nstep:=orders[2,j]+1:" I j3 b! J( ^& z; s
if nstep<=orders[3,j]
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);8 @. M: n4 z0 m' [4 e5 A
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];8 [: ~4 l- S) J# D, v! C
end;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;
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