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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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; G8 s" p: K/ `+ P" n) \( i不好意思,打错了个字母,呵呵呵!
$ W+ d- F$ w( z& F' {2 x& u. G大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
8 p+ z0 c" Z0 o, V( r0 \“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!; T0 O2 y1 ]) n! T0 \% h
is
- D* S: @& H7 b2 B3 E1 V$ \ j,k,nstep,c, scheduleteps,mincomptime:integer;3 N" F1 Q0 c/ f# W
M:string;' V$ p* v( A, u2 H& H
selecTab:table[integer,integer,integer,string];4 a( D5 R8 X+ P L$ A6 W% i
do' M/ M9 F( I3 P; N) t
initorders;: w! g+ k T, c$ w1 g
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scheduledorders.delete;
# [! n! K7 w: d X; b4 X) t, g# J o seletTab.create;
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orders.initialize({2,1}..{2,*},0);
0 f7 k8 E, I# k orders.initialize({4,1}..{4,*},0);/ c- z( d9 R% y, ~
for j:=1 to numorders loop8 O. ~, V& W& B) Z R
orders[5,j]:=orders[1,j][2,1];1 F0 G5 t0 n# b3 ]& r) j
next;
9 v5 j8 @! h( [ occres.initialize({1,1}..{1,*},0);
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; J& l5 M7 t9 l3 t --XUNHUAN
4 R$ A" }& A; E for scheduledsteps:=1 to numsteps loop --
; H1 p- E1 p7 c8 C% S selectab.delete;" }/ b$ X% P/ G0 q
k:=1;* P8 G) S3 Y+ a E0 \6 [
for j:=1 to numorders loop
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! F' d4 S9 M+ H. A- N- Y nstep:=orders[2,j]+1;
3 d# F: k0 c: M @ if nstep<=orders[3,j] then& J5 M. F7 w+ |: Z0 c( T( \/ ]
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
$ }4 S* {$ w. |4 a k:=k+1;
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' J, ^9 z+ S' W end;
( `0 |- D( g0 O8 x6 x; t2 p next;
$ O, Y" Y, s, \1 N mincomptime:=selecttab.min({3,1}..{3,*});
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2 S a1 z, ~, ?& K: Q from j:=1 until j>selectab.ydim loop
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2 \# z5 {8 y0 M$ C* G" Y) S if selectab[2,j]<mincomptime then
5 N5 r2 q6 k1 ^# x ` j:=j+1;8 k- {6 M( A# Y. p
else
' \( _* |9 ?" d selecttab.cutrow(j);$ w n0 n+ v% Y* p4 J9 p
end;
! X9 \+ a {, Q4 g+ s+ x end;- g; a2 A5 p. M; E+ {1 o9 S
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j:=selectionrule(selecttab);! ^4 @- \& `( |/ j1 b
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nstep;+orders[2.j]+1;
[7 @+ Q% [! e5 x( t8 y orders[2,j]:=nstep;- Y% e" `3 I: t7 K+ @
m:=orders[1,j][1,nstep];
0 c2 h7 @: z. b; [ x5 \ c:=orders[5,j]
0 D; }" J4 t$ T% ~" K8 F% w1 M occres[1,m]:=c;
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( F/ A, u9 u* b# {. I) X --jieguo:start,end,res,job,step: j# h" S0 ^% Y# L$ |
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
: l& J6 {+ E- @/ e for k:=1 to numorders loop
7 A; d0 K/ L5 w- Q0 D5 \ nstep:=orders[2,k]+1;# r3 \3 T0 f( B7 \0 W! X5 @8 Q( g
; j8 ~2 `1 }6 p ^. S$ _4 ? if nstep<=orders[3,k] and orders[1,k][1,nstep]=m8 D* X F5 K! ?) W# c+ R
--! z) E9 Q- V! X/ q6 G S: z8 D: x8 }
then
9 q$ K6 A7 D' C3 O( w. _7 I orders[4,k]:=max(c,orders[4,k]);* w5 k* S+ m p+ W+ n0 j
--
6 V* r7 X( Q. l5 |! t+ k5 u# Z orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
3 G4 L# t. U( G0 J2 x' L next;
, {$ b& ^$ ~# N6 N- q1 m6 }0 c nstep:=orders[2,j]+1:
! H2 u8 Q" R2 s( }3 x if nstep<=orders[3,j]
: k$ D! A1 J+ {# m- a
2 ^' s( l+ K' L6 e8 C2 _ then
6 i/ a; ?/ A& w M# M+ z orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);( ~8 d4 r. m! N. ]# _+ E
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];+ [# I- r* E# P5 j
end;
8 ?2 n. |* U0 Y4 E% Z next; X! l m9 s4 J4 q4 C
- ? G3 U* B" ?/ X print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
$ w# u' v5 a; i5 u/ z mygantt; v5 k2 [. X. o% U. ?0 F, d
ens;) z( P, x0 k+ N2 j6 X+ H( G* {
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