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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!9 W2 U! \9 P" h: r% [0 ?
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
' e$ |2 l; A! y0 t) z; W“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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- `* \" a- k f2 z8 V4 Y ^ j,k,nstep,c, scheduleteps,mincomptime:integer;
- w9 a% M( T |2 W) f6 Y& v6 h M:string;5 V% h% S! ]# u! \# f
selecTab:table[integer,integer,integer,string];0 J8 e1 |1 K5 q, V: p4 ]9 _$ o, ?
do" l0 W2 N; H' \
initorders;
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2 i5 C4 |! U, \7 S scheduledorders.delete;
, R* |% M6 U5 Z seletTab.create;
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orders.initialize({2,1}..{2,*},0);
0 C4 p% G4 K, e) k$ z orders.initialize({4,1}..{4,*},0);
: F1 R0 T4 C+ z! l5 O3 N for j:=1 to numorders loop. c7 r+ Y n/ j0 g5 f+ U
orders[5,j]:=orders[1,j][2,1];: k. z7 y) O& c1 F; C) Z/ w
next;
5 M' f4 I. h) `) ?8 Y occres.initialize({1,1}..{1,*},0);$ M$ C" S) l1 E3 t! ]
' b0 Q4 N c9 I* L3 y/ v- E8 p N --XUNHUAN
}2 Z; ]! Q% E$ B for scheduledsteps:=1 to numsteps loop --
6 a( S! W* [% v; x' ~* @" ~; q selectab.delete;; R# G9 ` u- r1 c# z
k:=1;0 x A2 \7 Z+ y
for j:=1 to numorders loop
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nstep:=orders[2,j]+1;7 T- S& r8 y- v* S, k
if nstep<=orders[3,j] then- J) i0 d# O- j3 a( q
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];& @4 ]7 `4 u& [! H4 R
k:=k+1;5 ~" B0 y& r" L0 g" ~) ?
2 h! I# v0 p: w o9 }8 H% l end;
. U. Z! v% W& o0 F# m0 J' V next;
- _ y2 l- O A( U h' _- z$ b mincomptime:=selecttab.min({3,1}..{3,*});
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1 y7 c/ B( \0 a; @8 q- J: C+ c from j:=1 until j>selectab.ydim loop4 A1 P. W' ~& Z
; L6 U' G; A2 z$ x if selectab[2,j]<mincomptime then
% a7 M: R1 z# Z7 [4 a6 a- C8 Z6 c2 M j:=j+1;
% N/ b' R( @+ { ]8 t3 \ else
" \: ?# E6 k! ~' M- T/ c+ o& R0 k selecttab.cutrow(j);9 r! \0 t* l, K) {0 m
end;. \/ O% ^+ g6 X5 i6 p
end;
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; ^6 `/ V+ g9 F, H( ~ j:=selectionrule(selecttab);
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! }4 _0 k( \+ F% V4 b4 H nstep;+orders[2.j]+1;* D# x# y3 ~" r6 q" l9 E5 [
orders[2,j]:=nstep;% K3 {: A/ F4 s% D
m:=orders[1,j][1,nstep];, t" [: c/ X* f4 K) G
c:=orders[5,j]- Q3 G5 ]2 |( u) b! \; X4 n
occres[1,m]:=c;
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--jieguo:start,end,res,job,step
$ p" g6 `0 s% Y7 j' _# ~! v1 m scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
0 Y$ i$ v6 ~/ ?! K; Y" h+ H for k:=1 to numorders loop; r3 O- U Y. K- G2 w) F* l
nstep:=orders[2,k]+1;$ R' f& B) [6 }, f9 W
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m% _, q7 _" p* }
--. ^6 `2 ]2 T! o: o/ U
then
% [- V: k& U* F( b9 c; j& Z- Y orders[4,k]:=max(c,orders[4,k]);
' {% b) a( V( _. J1 V% [- l% B --
- C1 X0 P5 Y" ]( c9 a4 T3 N orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
* o3 t; c* U- |# U r5 P" d --
( Y8 J% P3 d; d% K, R1 S6 v t end;* I( l4 ]8 T# L! |
next;! I$ `5 x! e5 w0 o3 v& ?
nstep:=orders[2,j]+1:+ P, N% a' l9 A! R' w
if nstep<=orders[3,j]
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( M& s# F, x6 l0 C2 n6 A then
B; y/ U( z# u! z7 ]* L2 n) R7 t orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);4 O: {# f3 [# p: s+ F
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
% U% Z1 B. j8 O7 N% t( c- H* C1 D/ g end;0 n! a& P; _6 R# m
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});. t0 `8 r% t! M. l3 c5 _
mygantt;1 n! n& _8 _2 w) H6 z& y4 |6 P9 ?2 f' U9 M
ens;
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