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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!
! b3 i5 F/ M+ D3 f" a, c大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
: x2 Y9 |5 | j3 d3 p" @5 i“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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: J" | N) {) q0 W! V' X4 F; N8 c j,k,nstep,c, scheduleteps,mincomptime:integer;8 @& s/ I# R$ e* E- u; r
M:string;9 o$ l3 R3 G0 ?1 I
selecTab:table[integer,integer,integer,string];5 ?' w% X# c* j' y2 |1 k
do
5 t# }) d0 e4 c6 t initorders;" Z6 O9 i9 `, l5 c0 \7 @
; B: R; t. d) R2 y* O) } scheduledorders.delete;& T( B5 o. C4 w) n
seletTab.create;
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% V/ F7 \7 P9 J" ?1 ` orders.initialize({2,1}..{2,*},0);
* X1 l/ E4 L3 z' L1 ?& E* m, ~5 z( D orders.initialize({4,1}..{4,*},0);
4 z F& d( e# T' o b for j:=1 to numorders loop2 M' d# W1 O/ `; q1 @+ |. a0 r
orders[5,j]:=orders[1,j][2,1];
0 |9 B0 _: f0 t: b; r6 z next;2 @2 \4 T. B( F( C
occres.initialize({1,1}..{1,*},0);
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for scheduledsteps:=1 to numsteps loop --
; g3 X- \/ I9 s) V) p1 w0 P, J selectab.delete;
- ~, s0 L0 `7 Y6 U$ \ k:=1;
5 P! c! `: q3 r/ ]8 m" c& C; L for j:=1 to numorders loop) _+ x# Y) l) L# L! K" g5 [/ S+ i
& z7 g' O. P$ I8 Q) r: p nstep:=orders[2,j]+1;. L+ d% @" P6 q& j# ^ ?
if nstep<=orders[3,j] then
9 i* ~9 v& s* u9 E* R4 i7 G selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];# z+ N9 b: Z9 ^4 Y4 R
k:=k+1;' _4 r& F3 z9 c6 y
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end;
0 M' A- I% z) w, o* y- ] next;
% T& _: f$ F* ?+ ~$ F mincomptime:=selecttab.min({3,1}..{3,*});3 m! B$ a: a9 j3 F* ?7 Q
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from j:=1 until j>selectab.ydim loop% e" a ~& ?& c7 A8 B. B4 y) o
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if selectab[2,j]<mincomptime then( ?4 f* K# J( U' [1 \
j:=j+1;/ c# R. \+ N5 J/ X
else
& Z& j2 D3 K* _/ ]7 C selecttab.cutrow(j);
1 h/ b0 v- N$ D* \5 H9 ^) N end;- {; t# d9 }$ i$ W
end;
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7 m0 I; I H+ C* q j:=selectionrule(selecttab);! A% f& n) ^3 t" W; \& t4 }8 v
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nstep;+orders[2.j]+1;$ Z1 d+ I. ^) r0 D
orders[2,j]:=nstep;
* o# K9 X4 ] J7 B) o/ f m:=orders[1,j][1,nstep];
- d5 A3 b% O, ?1 ?0 | c:=orders[5,j]
5 ^, r! e4 Z, T8 G' S, O' a/ o occres[1,m]:=c;# m0 R. n% C6 ^7 O+ m5 l0 Q
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--jieguo:start,end,res,job,step+ U9 V) k% l/ f
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
; u: \3 Q0 t) F! D for k:=1 to numorders loop
9 V# [3 Q4 \9 ^- @, f. \) O' m: ] nstep:=orders[2,k]+1;4 ?) E: t |2 G5 _- {
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
3 @# x7 U% z! u7 A1 b --
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orders[4,k]:=max(c,orders[4,k]);
# v5 @1 w% Z. q4 z- Y# |) s --
3 n& h( G* Z: H, \) t" a orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
; s8 ?1 U* w2 j/ a --
6 X4 m! y1 o! Y) o end;
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nstep:=orders[2,j]+1:
3 V, x3 [! ?1 N/ @ if nstep<=orders[3,j]7 J2 N; l# V. ^! ~4 T
4 Z, C( W( P/ n# U then
- m7 W( l# F7 \ ]1 S* Y7 H orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
/ Y5 v% U& @% B% J1 W3 ` orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];' D, u; _+ P. k2 T1 o( P
end;
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" |) T' {7 p3 w0 I! e2 c print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
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ens;4 S) j! j% X0 ?$ m
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