我在试着编程，很简单的取随机数，可就这样也不对，我不知道哪里错了，编译时没问题，而且在Eclipse环境下运行JSimpleBug的例程也没出错，可为什么我这个简单的试验程序却出错了呢？帮帮忙吧。在Eclipse环境下。
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public class test {5 I- h3 `2 j- s. l H( H
/**
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public static void main(String[] args) {% F' O' a; T4 w. }* G! k( \
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int y=(int)(10*Math.random());
; z/ {- c" K/ H4 d; B+ \) l: ] System.out.println("result is "+y);) X# u$ }: E7 h; L
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double z=Globals.env.uniformDblRand.getDoubleWithMin$withMax(0.0, 1.0);, s5 b' E( e5 F& @( [1 I
System.out.print(z+" re");: d# H4 N3 t. o7 h* b" G
}
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结果是：/ I3 u7 F) b" T; h, V5 W: k0 Y
result is 21 G8 b2 N, W P( O: g( E
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# An unexpected error has been detected by Java Runtime Environment:5 [. Z7 e( a3 W, O8 [3 o7 _+ Q7 ]' o* n
#
2 o5 \$ T: |1 c8 I- t8 N8 \4 d# EXCEPTION_ACCESS_VIOLATION (0xc0000005) at pc=0x100b8305, pid=1064, tid=1068
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# Java VM: Java HotSpot(TM) Client VM (1.6.0_01-b06 mixed mode, sharing)
4 c- R# ?4 @0 a3 t; S3 j) s$ ]( o* h# Problematic frame:3 _% G, ]. I. V! u# \0 I5 h, X
# C [javaswarm.dll+0xb8305]
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# An error report file with more information is saved as hs_err_pid1064.log |
发表于 2010-1-27 11:16:30
楼主