|
|
本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 * m' m# b; m8 f% B
n9 ~' X, p. {5 R我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:* E: ? d8 z+ i' j. k/ H: O: `% L
begin P_in arriving
# q: d9 R$ e* a6 Z) ~" R# | move into Q_in
0 P% ?+ o4 r0 B use oper for 2 min
) d9 r3 k) h+ A1 i2 v) s; P send to oneof(0.95:P_in1,0.05:die)
, ?. Z+ v @) i0 |' T" y6 aend
" { Q7 t0 K$ D0 ?# |begin P_in1 arriving
3 r) e+ e3 z" A o- m. C if load type = load1 then
7 r: _2 a! O! ^3 b5 c begin; g# s, p' b; |8 X
move into Q_m1
% Y* n: ]+ ~ }, y0 X use M1 for u 5,1 min$ F" g, J3 R, Z+ R
move into Q_out12 w q- T1 B+ K
wait to be ordered on orderlist OL_1
! j- P- ^2 H2 j/ Q- K- } end" J& e+ P3 p4 l& ]
if load type = load2 then- N8 s% V6 b- \4 P% Z( l
begin
" _% C5 P" f4 A move into Q_m2
4 T7 Q. w9 \- W+ i1 @ use M2 for n 8,1 min( v2 f4 p5 B0 I% A ?; N
move into Q_out2
7 ^7 {! N, O! P wait to be ordered on orderlist OL_2
+ _* r' b" v- O3 i6 A6 D! [ end7 s( c% Y8 k/ Q+ V( Y4 H2 F
end# ^% X- E' Z" m" Q: U! g [- V) X
begin P_dunmy arriving
, F. B" V& N; R5 Z4 L set i = 1
. Z" I+ V0 o1 r# h P" P3 {8 | while i > 0 do
" C0 a. ?" k1 O- q* G/ v: w begin # T. p0 Z* |& I2 [1 G; l/ @
order 1 loads from OL_1 to die/ p) U5 E0 @4 m
in case order not filled backorder on OL_1
, K" j, }* y i+ a- S6 k+ p m, p order 1 loads from OL_2 to continue! p/ K5 p: P* U, e: m& C9 y2 f
in case order not filled backorder on OL_2
7 s' H( E4 y6 H/ W7 r0 Y move into Q_1
; J$ N& k9 A8 D0 H) }2 U3 s$ X use Massm for n 5,1 min8 R- ?) r2 m. O% M2 D
send to die
Q" s' m# L6 z/ w; U end
7 B% f0 E# ]) M! N. Hend* ^# c& K, l% m) F% k
这是我的报告0 \9 ^9 y( S" k9 H) u* x$ ~+ I
*** AutoMod 11.1 ***
1 E0 L9 ~, E* k: |2 j- ~Model q/ B( _. T& ]* W4 E6 ]) b4 X1 t
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.009 n+ K( A% o+ ? \6 l4 g- B
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
+ q* m' I9 @1 D. J3 B' {2 _Statistics for Process System "q"& v8 {% o4 |* ]5 r2 H: k
Process Statistics7 R8 [0 }' @+ L
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait) R$ t1 g m0 `5 P" p" v1 H
========================================================================================
9 C7 H+ w3 L6 s6 S; R1 @) D" eP_in 222 1 0.32 -- 2 0 -- 126.04 --
" F7 X: w. m% n) q( U8 w9 _P_in1 212 210 102.38 -- 210 0 -- 41725.92 --7 Y) k0 u% {' M( N7 U& {7 _( J) r
P_in3 0 0 0.00 -- 0 0 -- 0.00 --5 K0 S R: t, x* G/ t1 q
P_in4 0 0 0.00 -- 0 0 -- 0.00 --6 E* A' `$ O1 X1 f
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
& t# X2 i* K. g$ @1 k0 w7 PProcess Traffic Limit Statistics( @' O% G7 d. \( a
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
& b" R# d. b% h F. I========================================================================================( N1 B0 G+ i/ D% T3 G# V
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
' |/ G z- T: R- u) tP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --9 c( ] @5 D7 w+ N4 Q# {% G
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
3 _' L$ ?4 j% CP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
0 U; v; p" O9 u/ tP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
. C' `7 Z: {( `9 J, zQueue Statistics
/ v+ T8 b5 U: C9 Q3 ^8 hName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
0 ~' k+ U: h' H========================================================================================
7 ~3 O, ~4 ]5 [8 g4 N) g8 ~Space 223 0 0.00 Infinite 1 0 -- 0.00 --
* R' x! p& ] ^. ~, TQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
! x2 ~$ c6 W9 n1 I- zQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
3 |9 y8 N: j7 `1 S B. oQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
+ }8 ]+ v: ?( h& O6 o+ D. q9 u8 EQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
; J% p K. \2 V) KQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
& L2 I8 c5 u) vQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
% f7 E$ Q- _1 c8 G# jOrder List Statistics% W+ G2 V0 E/ F2 m$ h6 l7 I1 p
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
8 P' {5 {8 [! x================================================================================
9 Q" r' j" ?3 pOL_1 139 139 67.23 139 0 41789.43 14 {9 B0 Z4 F2 i9 h- C1 e0 D- G4 @
OL_2 71 71 34.26 71 0 41693.20 1/ N; B# ?- U9 Z' l# k
Resource Statistics
: h& w& i9 h C J% f/ KName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
: f s% `8 ]4 }$ R; S$ j/ T====================================================================================================& ~! C8 R6 X% g4 E I1 G; n
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
" e% _/ f2 H- [% @* wM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- ) T( L0 |/ ^' _/ a y5 j: A
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- ' [9 q e* w* U. Z" C7 V9 \5 S
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- # p4 y! J; E% J6 V. T
Random Number Streams
+ z- D# i$ F, E1 ?/ x8 oName Total # H' P. n, f- r
============================
. b) {1 Y$ e0 Lstream0 455( Q# [" J' j* ?/ f7 B* \
stream_M1_1 0
' k3 a7 H1 R3 z0 @ wstream_M2_1 0& e" g/ q+ a& {/ h
stream_Massm_1 0
% K6 v1 {$ g: @+ {# Ostream_oper_1 05 f$ W" I: P0 H+ [
stream_load1_1 184( T \) X% _+ y( g
stream_load2_1 76. V# U& |1 P( H5 O8 ~
stream_dummy_1 06 @' p" C! }$ R
B* p, t D2 Y请问我的错误在那里?我用的版本是11.1的学生版 |
本帖子中包含更多资源
您需要 登录 才可以下载或查看,没有帐号?注册
x
|