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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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! M. g6 R' g+ y3 `- G我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
; ^3 Q1 ^! U. k0 j; `* @& jbegin P_in arriving G4 e* J1 ]2 } B- E+ p4 `
move into Q_in9 f7 K' W( k- x% G: S
use oper for 2 min, @& P1 A1 W X/ S7 i% `0 Q/ c/ v; Y. y
send to oneof(0.95:P_in1,0.05:die)! |) ^# ^) ~4 O$ l$ T, }
end
/ Z2 m" \4 U5 l# u+ C1 J. l, Kbegin P_in1 arriving
, Z& U, w4 O# r4 ?% ], {/ F& ? if load type = load1 then
" E. @- E/ y. _. s begin
+ _7 b9 f- w g9 F" J0 ~ move into Q_m1, F6 j6 S# `2 I' f1 l
use M1 for u 5,1 min' a0 R3 F2 h- R/ T- j
move into Q_out1+ r r/ N4 ~+ @5 a
wait to be ordered on orderlist OL_1
3 J' ]3 y1 P4 n) y/ k; p3 f end$ Z7 w( f6 R+ u. Y, _
if load type = load2 then8 `4 [5 k+ }6 ~, K
begin G0 ~# m" m* F. s7 M1 I
move into Q_m2
1 F' \# y }& x! W, M. A use M2 for n 8,1 min
5 B+ J1 t8 T0 g7 X/ w7 v move into Q_out2+ u* ?0 h, }& g( C$ b
wait to be ordered on orderlist OL_2' V. b& J+ K# w6 Q
end
. j( w4 x# n- R6 jend8 U" Y. ?' d6 {
begin P_dunmy arriving" c3 |+ j5 l7 _5 g
set i = 1' `* h' t; w1 Q$ V. y6 n
while i > 0 do
4 i5 o+ J- P) O% r# {9 |1 }: L begin
( ?# @' {8 x; X; R- X2 R! e order 1 loads from OL_1 to die8 u2 W( a( t: }4 U6 T
in case order not filled backorder on OL_1 |4 p+ U' l) _7 @- X" m
order 1 loads from OL_2 to continue
1 _7 G/ g; p* Z& D" ?# i. i in case order not filled backorder on OL_2
; u w8 m% c1 b1 e move into Q_1
/ k4 n* r( N4 c use Massm for n 5,1 min
/ q2 J1 N0 `/ l$ k+ \- v( b. i+ G+ [ send to die
4 q: l6 g7 w) i: | end' \3 e7 l7 Y7 |
end- X! h9 j7 j B- Q1 R
这是我的报告! F, {4 c5 f J( y$ e2 U4 f
*** AutoMod 11.1 ***1 @+ [; M) W; ~
Model q
! m. M6 V& P/ y q2 i: RStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00& u- y% l- N" e2 w4 u$ O
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec. `: N6 U- |, k) X
Statistics for Process System "q"
! X1 S' h# V( j4 P K- i3 v" G, \: lProcess Statistics: Q y7 V4 B$ `. `
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
9 m X j. y% g ?7 F6 V+ ?" ^) l/ U========================================================================================, C( y5 q, _$ C# q0 h
P_in 222 1 0.32 -- 2 0 -- 126.04 --
& H% s' g; [# b/ w1 y! T0 CP_in1 212 210 102.38 -- 210 0 -- 41725.92 --4 j" @( M, w8 i' K
P_in3 0 0 0.00 -- 0 0 -- 0.00 --) \ H. g O& z$ u1 L9 Q
P_in4 0 0 0.00 -- 0 0 -- 0.00 --+ d$ n& M9 f( C( N
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --; j4 b; y! b. R' {% E# a9 t1 _
Process Traffic Limit Statistics0 d5 Z7 h2 c5 ^1 h8 g. T3 @ @0 X
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait6 |% c* \; ~% \5 {! F
========================================================================================- ?% x( d% F; l
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
$ l) n9 j7 k* l* m @6 j/ d3 GP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --2 b3 {4 @4 s& w% W
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --& i' w* n5 P6 J( }+ b9 n# p7 y
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
% Y1 k( q) p) i+ HP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --7 o1 F7 o) @- a4 |' w% r, r- j
Queue Statistics+ V( d: D! O5 Y! D" C* T6 W
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait- O6 ~3 S3 }. q3 O3 H& g% ~, d
========================================================================================/ ?% e( N5 K" k! @# _* \' V$ z& o$ q
Space 223 0 0.00 Infinite 1 0 -- 0.00 --' H3 { r+ W! V0 i6 I( t6 ]
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
" L" i+ D* X& Q6 |- _1 nQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
9 V- i' v4 v9 M$ N, cQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 -- N; {, ^) r6 s# m
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --- }- n1 A9 `" O+ N! O) g" t" a
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
/ r" ]$ g8 ~( s. TQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
: X) b& A) u& ^. k" h. xOrder List Statistics* `" ]6 @ y8 m+ O6 ~
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered2 @. U. X3 G. e% C
================================================================================
1 J* H5 ^' _$ K/ e0 @2 ]OL_1 139 139 67.23 139 0 41789.43 1
( [; F/ w& w: n5 x1 {, z8 {6 ZOL_2 71 71 34.26 71 0 41693.20 1) F( N3 q2 q* Y$ ^
Resource Statistics$ j# W6 M0 p: b% `. y. l# Q* W5 D, E
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
9 f/ ~$ z& p" F3 n====================================================================================================
9 k) W$ ?( x8 cM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- ' ]1 O$ H/ P/ z- ~* ~3 V
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
% a, ?% Z; E+ Q1 mMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- . i( v' Q! Y, c2 {, m, P- q
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- . p5 t# d+ e* c8 T9 W% ~
Random Number Streams
" l: x8 J" p/ OName Total
2 L L: o* |" W, a4 f5 r7 Z) r============================: ]* O! w% |& Z3 [) @7 V
stream0 4550 P$ s, L: A$ j# u
stream_M1_1 02 ]& x4 r' i8 J- g/ f4 V7 O
stream_M2_1 09 M# m( {. Z' z \7 d- B, I8 v
stream_Massm_1 0
3 i& c( i' i- W- Nstream_oper_1 09 }- L: k( e# M. }
stream_load1_1 184
+ c$ A i1 q/ pstream_load2_1 76
' \& i3 s* _- e4 G0 Z4 X' z" Vstream_dummy_1 0) ~! [9 c) Y& V
: S: T+ ^' h A! `8 v) n请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
