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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 4 D% j3 |' q) [$ q1 t. N
+ v5 B! M7 s' B; Z g" W/ K" B. t/ y我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
/ t: H% _" Q8 @3 E* H4 I, Cbegin P_in arriving
$ Z: A. r+ q- I/ ?# F! T move into Q_in
# \2 i" D* F* J( o: v use oper for 2 min5 I- O# Y% j# _- ^# W
send to oneof(0.95:P_in1,0.05:die)
I! J# m; S! T# Tend
; H& _( {' B( Y7 }begin P_in1 arriving
7 g: r8 c7 E- F( L3 W' j0 O. ] if load type = load1 then$ [+ B% B( W$ |( D# s
begin
2 q, ^- P9 N8 Q/ I4 F5 V move into Q_m1
3 t( T1 |; H3 q( g9 q4 e- J2 M use M1 for u 5,1 min
4 W& i: L& x1 A3 \# Z1 _: r: _ move into Q_out16 k; N$ }. |* [, F% N& V
wait to be ordered on orderlist OL_1
3 i+ s- d4 e) Q end
% M- v( _9 C! P/ l* s if load type = load2 then: ^ L( E- D: V! `7 q) Q
begin
. g( j+ N, h6 i' H move into Q_m28 n' ^% R% [; w4 ]: I/ C5 p6 c
use M2 for n 8,1 min, d6 p& T- u6 d$ h% [, s' w
move into Q_out2) h2 d, K5 ^; B4 E+ O" M
wait to be ordered on orderlist OL_2
2 c y5 D1 |5 L2 d- o2 b end& w& P& C2 k! }# F' L9 j" S
end
' U4 }2 q6 \2 K% _begin P_dunmy arriving
+ Q" }% q2 m5 L. B2 f8 L3 f set i = 1* A1 Z% r+ B! R' ]2 L; T
while i > 0 do m' @0 u( \' w. v
begin
$ L* C/ o: Q0 n7 u) p5 @$ t" ?* U order 1 loads from OL_1 to die+ T& l+ i( X; E' w2 g4 D+ j
in case order not filled backorder on OL_1
" B0 R: I) H) u* v- X order 1 loads from OL_2 to continue1 ~5 [0 B! @6 o* Y3 _
in case order not filled backorder on OL_28 |' b- o) }% W* z) J& j, l3 J* D7 {
move into Q_14 |3 ?" Q8 U# P/ h7 a
use Massm for n 5,1 min3 i; k( n( v' {8 H) `* o
send to die! F' v! i' b3 s) {
end
' E& |& a: T- i7 n' T, _end/ x1 ?$ f; l6 x5 c; l3 f
这是我的报告% G2 |4 v) |$ V" M" F2 s: c% b
*** AutoMod 11.1 ***. T: ?7 ~2 D/ i* u2 f
Model q
6 e$ q w# r! l1 `1 CStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00. j! ^$ w) P1 w% C, \' |1 t8 V5 P" }: O
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec* B! ^: b& t/ v# q: M
Statistics for Process System "q"
9 U, X; n& K6 @1 TProcess Statistics
2 {' y8 |) ]5 k) WName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
! l# E+ N! m& r5 N; r! T' _========================================================================================
. H, C, \7 c3 E9 @) vP_in 222 1 0.32 -- 2 0 -- 126.04 --6 V0 U# V& j' V" a# o
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --; B0 X! _# |1 Q& N
P_in3 0 0 0.00 -- 0 0 -- 0.00 --0 b" @# Y8 r% ?7 y( ^
P_in4 0 0 0.00 -- 0 0 -- 0.00 --! G' j8 _4 W. K/ D; o6 M2 s2 ]$ Z$ N
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
/ ]4 o4 Q" ~6 V Z, _7 rProcess Traffic Limit Statistics
( L! F( `$ I, k% }& c/ tName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
" Q8 Y- o2 J- W$ C* A========================================================================================& s! D& b9 S0 A2 M) p0 C
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --( @6 m: d% p" M- ^( n
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
6 a$ m- U$ ?' `! xP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
. F9 c8 H: ^7 bP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
' V1 R+ i2 V A @9 n$ aP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
8 M ~. k# b% e7 W. _& AQueue Statistics7 @/ f, n- O$ U7 z- G& s3 k i
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
$ h+ x3 d" ~ j6 `+ O+ e========================================================================================! M1 n+ F4 Y& }2 I3 }6 [
Space 223 0 0.00 Infinite 1 0 -- 0.00 --2 j2 r" a) F$ a1 {
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
* u3 b: x- B1 m: Z5 i! ?" aQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
; U* b. F1 T9 H0 L+ e0 W/ l& kQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --% L, w6 |6 @; i; L: P4 o+ b
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
, Y5 Y A! s3 eQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
& A, M' t3 |) x: f" @/ oQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
0 T$ N0 ]. X4 v1 L8 UOrder List Statistics
/ H* \9 K) B+ d6 Z# y. w7 i: c& gName Total Cur Average Max Min Av_Time Tot_Back_Ordered: I* r+ N4 {4 U# w3 }" l8 G- }" ?) d
================================================================================
5 y7 W) A' S' N& nOL_1 139 139 67.23 139 0 41789.43 1
) A$ c2 i5 s) h& u6 i+ o+ }' wOL_2 71 71 34.26 71 0 41693.20 1) {6 j8 g) w8 Q" q& _' e
Resource Statistics) U+ f. Z; u) }# L4 D
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
: c7 H* |/ Y1 j' J4 D+ B9 e0 I. P====================================================================================================
6 `- _% D* z. N& vM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- : W5 }: X# C9 E+ |; _; w
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- % O6 E8 b b: Z2 d2 ~
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
! g2 |9 c( N. d& R; k! B( toper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ---- ( X/ `- s* d% I4 K
Random Number Streams
" L. a' p, ^+ X2 g* R/ \4 C4 S6 sName Total
$ o0 w4 m& I* ~5 v; p% {) L============================
. G1 R7 h! E ystream0 455
6 x/ Q4 G6 z- {# Zstream_M1_1 0- T6 R; N2 k) q' y
stream_M2_1 0. S4 N0 }1 u% C
stream_Massm_1 02 a" P1 [5 \! {; ~0 {; U3 \/ L
stream_oper_1 0, v# b6 g6 [6 B7 w8 }
stream_load1_1 184
6 s( @! K9 J+ bstream_load2_1 769 l4 s! d x7 @9 T) i
stream_dummy_1 0
- b( X L5 V7 J3 C
. W6 Y1 ~6 `' B R请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
