|
本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
+ I( @8 J5 }+ k0 z
1 B3 s( I0 B/ g5 O& Z我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:+ u( B# T- Y/ J1 e
begin P_in arriving
. Q, v- B7 ~% b6 L, B9 }! A move into Q_in
& X8 q* K! n6 _( G3 C3 K5 O& R use oper for 2 min
$ T q, o" [) a: f% i; B" l- H: o send to oneof(0.95:P_in1,0.05:die)
& Z2 i! y& z [$ s' wend# }) ]! `; ], ~, `$ Z! q
begin P_in1 arriving* G% }5 z( o( _4 `% `
if load type = load1 then
/ \6 `0 q* |- z begin! H& T6 }& J Y: ^* d$ _: A" c
move into Q_m1
0 a# h' W q, X) a# l1 z use M1 for u 5,1 min
8 c3 X) e. w2 w! D/ r: q5 K6 x3 E. P% m move into Q_out1
; T& o7 t6 z- N0 O: P4 m4 w% \ wait to be ordered on orderlist OL_1
) S: g& d. S( Z+ ~; n end/ G$ O7 f6 e7 P+ u; o: k, ^7 ?
if load type = load2 then
) I, K' J/ |& u, ]! @7 ?) f; } begin
4 G2 U8 m+ E) `5 ?5 P. z$ ~. ~2 F8 @2 ? move into Q_m2
$ y. s) f0 g8 W) p O) Q, T& n use M2 for n 8,1 min
+ b; D$ Z, z0 P- }3 d) L move into Q_out23 \% j; `5 @; I
wait to be ordered on orderlist OL_2
, x, W) p- z7 [4 N! y6 E end
# d {1 g( R" J- x( a% Kend6 Y+ s9 `) h3 U- A" j. Q
begin P_dunmy arriving0 v* _# ^" O8 M6 F, ^7 ~* B
set i = 1
- [3 F- O* v n. w: T4 L* l while i > 0 do
/ V6 X6 T/ E+ M begin % V6 z# O9 f5 f% ~7 K5 r+ I4 q
order 1 loads from OL_1 to die$ p! S$ |. c9 `& b |+ s
in case order not filled backorder on OL_17 G- ^4 m1 x ~$ R
order 1 loads from OL_2 to continue
$ ~1 h6 [1 w2 q5 D& [ in case order not filled backorder on OL_2
3 M- V& W6 Q9 N move into Q_1
5 q* l) c" e1 a8 t use Massm for n 5,1 min
0 j m( L5 j; W1 W3 t send to die
; {, s, d+ q* A4 W$ e' J end
& X2 w2 M4 f5 ]end E H% ^* A) q2 [' p4 H
这是我的报告
& d7 V/ O) r- K% E. m: T*** AutoMod 11.1 ***
1 }/ r' K0 t( B1 l- rModel q
/ j7 n1 d! U1 U3 Q! OStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00( e ?: ?& b8 a( u
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec o7 H1 v K( g# c
Statistics for Process System "q"& W+ W2 l9 s% \. l+ t& o
Process Statistics
. r: x' A7 K. f' ~) j' n8 dName Total Cur Average Capacity Max Min Util Av_Time Av_Wait6 \. N* X( W9 N
========================================================================================
- @: C5 W: d/ ^! t/ K, e' _/ HP_in 222 1 0.32 -- 2 0 -- 126.04 --
4 E! o, M) f; g# _! WP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
7 B/ `$ z, F" UP_in3 0 0 0.00 -- 0 0 -- 0.00 --
8 |: U! g3 S! [1 qP_in4 0 0 0.00 -- 0 0 -- 0.00 --
0 i, i# ^) I2 B# I4 W% ~P_dunmy 1 0 0.00 -- 1 0 -- 277.31 -- V6 p( K: R4 E h& Q: t: Q
Process Traffic Limit Statistics( z; Z' b, ?# E0 h
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 e) `: \+ w) ]7 G
======================================================================================== P' D+ `( e/ a& `
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
* x+ U! U) t" h: YP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
5 V3 o; j# Q- j/ d2 uP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
( n- B' E% e) e% B, [; q# hP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
^: u e9 A# i$ ?2 J3 |' jP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 -- p% Z* D j. [) [
Queue Statistics( t: s# V) @& k: O9 _3 t
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait2 y! [1 x2 q0 h3 J
========================================================================================
8 t0 W3 C0 C/ m$ ?Space 223 0 0.00 Infinite 1 0 -- 0.00 --4 F% T# S6 K: x5 T* v
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
+ s/ H5 f+ I A5 R& {9 jQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --( H" H; I1 Z9 d/ i, k$ H
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
, E- j* p) {8 hQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --4 U A# I4 ]3 v. u- x+ c" p: j
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --2 I |6 A9 c; j" z* R9 m0 s' M
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00% b' p, p8 ]7 w( ]( D; c9 w
Order List Statistics
6 z7 w. E" H B: C% i3 ]Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
5 \4 b0 X5 M. R/ |+ H* X0 _================================================================================
" n4 W1 J$ w" v; B) L1 n' X9 O) D( GOL_1 139 139 67.23 139 0 41789.43 1
% e. C, w. x! S4 dOL_2 71 71 34.26 71 0 41693.20 1, U V5 h) A$ q9 u1 q P
Resource Statistics" E/ \, X. j9 s. ]/ {4 L
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 7 a: {- E/ I( F0 v& O1 j
====================================================================================================
8 q/ y$ [& i, ~9 c SM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- $ P1 a+ y0 x& r9 c; a3 E* x
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- ) P& X% d* f+ w8 F
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- * s X( ~5 Q; v) m- F
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
0 g+ M- {- f. ]% S( A: T& dRandom Number Streams' \& q, q# _3 ~! c, ]4 ]# A0 ]. ]
Name Total
& Z. v( L: A: E============================
9 G! Q& t' R; u: B- |9 }" lstream0 455
4 g1 q% x* F9 C* L s* V7 c. astream_M1_1 0
/ }) `! i' _: L5 S/ X4 h$ {: v! sstream_M2_1 0
* o% `" E9 M; g f. a; ustream_Massm_1 0
- q: n: B5 ?+ s" I" j, lstream_oper_1 0" P1 q6 d# `$ ^$ D" P+ o
stream_load1_1 184+ x/ B7 p e% e0 {- m
stream_load2_1 760 |+ Y* l. ]0 B5 _
stream_dummy_1 0& }0 N* d( v5 H, r+ C
4 X- S5 _, X# k/ C% ^5 R请问我的错误在那里?我用的版本是11.1的学生版 |
本帖子中包含更多资源
您需要 登录 才可以下载或查看,没有帐号?注册
x
|