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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 ' G4 n! } ?0 I+ D1 V+ z
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我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:
+ {% z8 V) @. G8 z3 ]! rbegin P_in arriving
9 ], I' Y' ~; Z, O move into Q_in
! M. k% v+ g0 }9 c# [1 Z use oper for 2 min
7 |8 {1 R" v# b: C# f) i, m4 s" \ send to oneof(0.95:P_in1,0.05:die)
/ D0 J& m6 v! Q" Eend7 b3 b5 g5 h+ X7 x6 u( s ^
begin P_in1 arriving7 F: t( m; r5 R7 H) i
if load type = load1 then/ _; C r! A8 w) z
begin" x6 b9 L4 i; K' r- l% Z
move into Q_m1; c0 W, p1 \6 K2 z) W
use M1 for u 5,1 min: G9 J& t; j7 r4 S" c% h9 o
move into Q_out1
& O; y' p9 a) s e wait to be ordered on orderlist OL_1
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if load type = load2 then) i& ^ S* I4 ?2 Q& c9 i
begin
3 g3 [4 l" Q( m) c! [& R6 x move into Q_m2+ R6 N( e4 `( g; i6 r
use M2 for n 8,1 min
& x3 ~5 N: v3 h/ z( K; z move into Q_out21 r' o- t8 H7 c7 u
wait to be ordered on orderlist OL_2- f1 e8 O# s+ o
end
- i! A) k" V* E% U) {! @end( C: H( x O q, @: k _& y: P
begin P_dunmy arriving2 b& z, P5 G8 [( X( O
set i = 18 k9 v( b* C8 [3 T) g- h- [" i. v
while i > 0 do
0 C8 ?6 n3 D! d" S% E) r% T begin
/ H, W: }* q+ H* r4 { order 1 loads from OL_1 to die( T: e4 j' M, P1 ~# b" G
in case order not filled backorder on OL_1
8 ~( Z" h6 i* G# P% r- K% J order 1 loads from OL_2 to continue8 y5 r+ Z3 w4 l) h$ U C. y# @) n
in case order not filled backorder on OL_2
7 O; ^/ A) Q& t' q move into Q_1
5 h. _( d! C: v2 Z: ^' }& M( T use Massm for n 5,1 min' ?# y) R, }2 j& J# _2 }
send to die8 z% T* ~' i% a- h5 K
end5 J# d' o+ f( T5 f
end
% ^# X" R2 w8 o, L: ]这是我的报告4 Q2 U. |7 W" a2 Z/ u
*** AutoMod 11.1 ***
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Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
0 w' W7 e1 H7 H) O0 l! \3 i" j% E! jCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
7 g1 {: `! q: F9 kStatistics for Process System "q"
" I4 r( _" O, J- FProcess Statistics- |% o: V: B4 z, V
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
% y8 [& T0 T% O- L( v8 L9 z- {0 y6 L========================================================================================
5 G+ c0 \/ x; {. f1 vP_in 222 1 0.32 -- 2 0 -- 126.04 --
- y+ E7 z4 v# I" RP_in1 212 210 102.38 -- 210 0 -- 41725.92 --1 Q1 V* M s& @& ]. b0 o
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
: s( c) t9 @, r3 y! S4 WP_in4 0 0 0.00 -- 0 0 -- 0.00 --
t: I6 x1 |8 U, p. i- m+ p$ g& aP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --. O# I) \" _4 ] r0 Y/ ` G+ m4 v
Process Traffic Limit Statistics; L! }% g% \" J2 F) h0 r1 i
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
. E# N3 a! S5 _7 C# W========================================================================================4 B4 x9 n( j7 M8 X9 N
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
0 a% a4 K2 `1 h' u5 ^0 B$ h7 FP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
! j8 g- f1 }/ |" O6 x: z# kP_in3 0 0 0.00 Infinite 0 0 -- 0.00 --! }; G7 i& T3 }( _, K1 A0 I& T
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
$ ?9 ]6 }) v% Y: X' q9 J* x1 ^P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --0 `+ `& |3 z3 |- b: g t
Queue Statistics
: T) ]/ h5 i$ t& qName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
- u b* c# w3 h V7 e* A ^========================================================================================* [5 W" Z8 G$ V6 ^6 i, E6 P
Space 223 0 0.00 Infinite 1 0 -- 0.00 --/ ?+ A& o; i; T' a8 w
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --) a1 Q9 g, V1 ^/ \2 C( l! f
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --: n2 X. E$ }5 y5 M% K* v
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --( U; n* K+ Z8 k
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --; c9 K: j' P5 {. s# ]3 n9 z
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --' [- | I- V8 C( o) W" @
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
L- T( L" c& bOrder List Statistics. F' K3 R+ n- R+ ^: z8 G* [
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
9 N: j: X& }/ v7 l3 _================================================================================
/ w9 t, P& {8 q7 g# i. K) w: [- n9 u( j, GOL_1 139 139 67.23 139 0 41789.43 1# l' R! `& M3 J R- S' r4 g4 Y
OL_2 71 71 34.26 71 0 41693.20 18 w$ y+ X7 N9 A; U' i. `% N
Resource Statistics
' Y' O- o) x' G& g- s' R3 X+ PName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State - H/ j Q- T1 i6 V. p4 Z: s' u
====================================================================================================2 {! Z \$ y x8 r: p0 c" C
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- u0 Y% [* ]! y6 _
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- . L/ ?8 k% f0 }3 v4 ?* \& B$ `
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- 1 C8 W3 ~& d3 g% j, \# O% y ~
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
/ t: T0 L/ c! L/ S8 N& dRandom Number Streams3 F1 `( c# X1 j7 @3 P- K" w
Name Total ( m% |* U- U% X6 Y
============================7 W0 B* w( I5 e, C7 g( i
stream0 455* I* u' C. S# a4 B J, `; F2 @
stream_M1_1 0, q2 O& y, r5 q a1 N7 c
stream_M2_1 0! Y- @2 g J; O1 p
stream_Massm_1 0
9 e& \3 N, k. ~" E0 H: ustream_oper_1 0
& N# T v( A8 N2 n Z' i) i/ `6 Xstream_load1_1 184. T& [0 }- f; y! D1 r
stream_load2_1 76
8 p' J2 ]# O, ^( [+ d9 D" g3 @+ Ustream_dummy_1 0
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请问我的错误在那里?我用的版本是11.1的学生版 |
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