本帖最后由 GJM 于 2009-12-5 21:43 编辑
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/ c5 m, o6 ?0 z5 k底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去
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不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!9 E' R ?/ {6 R* I% C' }8 o) ?
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begin P_something arriving
2 B9 K) ^( W" E' T q move into Q_wait4 k! x% M3 b- G. c/ m# X w
move into nextof(Q_mA,Q_mB,Q_mC)
$ K+ d0 E" `7 S$ Y use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min
/ k5 I1 p' @% N' ~# F/ ? send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)9 W* d' |4 C3 c5 w1 n- w- m+ r) [ w
send to die
9 j+ `2 r+ `7 \+ C8 i: z7 C/ ?end$ m5 d1 q/ m, ]1 p
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begin P_mA_down arriving
; C) w, [* W0 d) \+ k- v( I while 1=1 do % ]- V7 x" F+ h2 P5 ] m6 ?
begin
; h- x" O4 s K0 R wait for e 110 min* X' h. c ]. L7 r: ?- ~" ~7 X
take down R_mA
' ?& K7 Y, u7 y/ p2 y) j! | wait for e 5 min
$ L. s& R/ B4 R1 c0 T& t( g7 \, o bring up R_mA" p; [7 |$ o, Q7 D& |, _3 Y0 V
end! K2 G+ e' ^5 ~
end9 u% \* ^" W6 v. E7 ]7 J
$ c) }* a L; R# k0 `6 A) s+ `1 qbegin P_mB_down arriving0 c2 a H" ]# {
while 1=1 do
+ T7 |4 x% T* \+ Q$ x% H begin
. Z a8 {; N/ x3 l6 Q wait for e 170 min
4 z0 `- @% T$ [8 |/ [7 h take down R_mB& j! }$ w# J. |, o
wait for e 10 min
0 Q/ B# p- K6 |4 {" ? bring up R_mB6 U! d5 w- E7 H7 k$ |
end
( t2 y! a k% tend
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; {4 N$ n' i+ s7 a, N; Z j6 hbegin P_mC_down arriving7 X# }: b- d% C e" f
while 1=1 do ) b9 B) J! J0 R# N1 |
begin) y2 L" v% j2 n$ ?5 ?
wait for e 230 min
& v# m7 ], z, {, b- ?4 w# V8 P# ^ take down R_mC
" s. C, H$ M( u, W wait for e 10 min
5 k+ A3 h8 l! I, X R$ a bring up R_mC
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end: s6 O; y, X v' t& k3 V% z+ f
3 M9 s0 x4 P; O V) |" q' y3 kbegin P_mA_clean arriving
Q" ]8 C) T7 L# t$ J while 1=1 do- Y6 I# ?' i1 c$ D" U/ a& r( w
begin
/ ^# ~8 x* _0 W a l( O1 D- [ wait for 90 min
+ `7 f" t3 O5 R3 l8 g _3 C take down R_mA! q7 _" h: G \5 X/ Z0 K
wait for 5 min& f. K7 @0 a0 \ i# l7 F' V- P, A
bring up R_mA1 S7 E6 v* S( g. |1 t
end
: M, \0 y1 |% w& k* B0 a) wend
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3 A$ G) C1 Y. X' ]" i- `begin P_mB_clean arriving
$ W0 f, `% w, l& R0 ~% T while 1=1 do2 Y( n9 l0 S8 A" u+ Z4 j5 O
begin
; M/ \/ i$ a! v# @) g4 X* d wait for 90 min) V3 k. h* b/ y/ C4 n7 | c, T! M
take down R_mB* H! u E0 U3 r6 i) w
wait for 5 min
3 f3 p0 i; v1 ~. ?$ ] bring up R_mB
. O! x! Q0 w& X: M$ n4 D4 g end+ v+ V) z( {. U
end/ h7 _! R* a1 S; J6 k
' [6 g0 f! X( p$ s: Vbegin P_mC_clean arriving
; P, S2 b, ]3 n) X) p" l$ [ while 1=1 do
/ f/ i4 i: ~7 E begin
( V( m. s& U z# `& E wait for 90 min8 D; B8 X! e/ L* \/ U7 l
take down R_mC& U6 g3 X# H6 T9 ?
wait for 10 min
2 `! {) o) Q% I F bring up R_mC
- ~3 D' _0 W. ?9 E2 J- L5 n end# B4 G/ ^2 u! p. x4 r- G, j
end9 q" i* A( P5 g) W
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Exercise 5.9
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8 z/ k& R) W! ^. P
" n! t, P9 k) @+ X5 H5 kCreate a new model to simulate the following system:
# g1 E4 ?! j' d* E% VLoads are created with an interarrival time that is exponentially
7 F+ S/ M w+ W) m( ydistributed with a mean of 20 minutes. Loads wait in an infinite-
% j! {; i: \" mcapacity queue to be processed by one of three single-capacity,
2 H, j. L* u: v2 Parrayed machines. Each machine has its own single-capacity queue
* s+ F" C6 }8 w& A% \+ b0 f, d' Kwhere loads are processed. Waiting loads move into one of the three * ]/ y( B4 T' h Y1 R9 e) r
queues in round-robin order. Each machine has a normally - O5 b' }' I5 a. p$ w! f% C* n5 m
distributed processing time with a mean of 48 minutes and a standard
2 r% b& k7 w7 ?6 k; mdeviation of 5 minutes./ j8 A1 d" Q8 r& h2 d
The three machines were purchased at different times and have , g! l. ]6 [& r/ E
different failure rates. The failure and repair times are exponentially
0 q( o) ~* z H+ u1 L# H9 Ydistributed with means as shown in the following table:
! n! m& l" z4 t' YNote The solution for this assignment is required to complete
! `; P% C. G% u1 R) n4 `exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of + B8 |4 e/ z- V% c. Z
your model. $ m0 D$ p: P% a6 v6 f
* K0 y% ~. R; { D' `: Y1 WMachineMean time to failMean time to repair
* W6 E9 N5 f1 _A110 minutes 5 minutes
+ V* L* V; Q! S+ y# kB 170 minutes 10 minutes5 u% G: H) w+ {7 ^0 p- q% W
C230 minutes 10 minutes
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The machines also must be cleaned according to the following 8 n3 U" Z! m0 i/ d, x" k
schedule. All times are constant: 0 z+ s# h9 }9 z# W/ ^8 m
0 C3 Q2 R$ m( Q; B$ I# rMachineTime between cleanings Time to clean
3 w( X6 v$ y+ z/ ]. ZA90 minutes 5 minutes
1 H4 X9 R) ^' L' V# d |' A: sB 90 minutes 5 minutes1 y5 y/ B/ J R! m) \4 X
C90 minutes 10 minutes+ H" V: H% o2 [" [( i3 q: j$ J
8 I4 ^% l& \* O7 ?Place the graphics for the queues and the resources. 9 x4 Y3 e# Y4 r& @ m
Run the simulation for 100 days.
* Q7 [9 j9 S9 s% vDefine all failure and cleaning times using logic (rather than resource
; x' U' o; ?0 `) m$ }& acycles). Answer the following questions:& ]+ V1 a, t; @% ]
a.What was the average number of loads in the waiting queue?
. S2 c0 \# ~: s- l, qb.What were the current and average number of loads in Space?
; e8 o" J& d: U6 A m9 j) nHow do you explain these values?
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