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发表于 2010-5-11 13:19:52
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用list吧" r S, d; d% D
patches-own [wealth rank]
6 S; G7 Q7 A7 V" J3 vto setup
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& d' O4 t1 R& _ |0 F. b, q# t& j( c ask patches [set wealth random 100 set pcolor green ]8 p# A" C+ ~) i: H y) m
end
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let mylist1 []
+ n+ m" h; P- D" w set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches- Q, i0 A. p" g# b, `* z% a! d7 P
let mylist2 []$ L3 H4 z3 j8 F @
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2) A+ v* J$ Y: n! J+ Q
[
4 s, a1 ~1 k, @' u! s ask ?1[ set rank ?2]
# |! j1 s, y2 I show [rank] of ?1* n( }$ @* x5 ]3 w0 z
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]
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let mylist3 []5 I7 X' x7 r$ l' Q6 {
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches/ c1 z: o# E/ b, b- \* ^
show count patches. T* l( I* V4 J
show mylist1
* d: V6 [ ^! {5 {* _5 |+ [+ P show mylist3 m& a2 c+ T) }
end
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+ Q9 E7 i# ] p7 ^6 ~* c这时的mylist1 和mylist3 应该是一样的 |
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