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发表于 2010-5-11 13:19:52
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用list吧* D* l S# v/ ~9 }$ N7 O; h
patches-own [wealth rank]
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ca
$ ^# x% [7 p; p C ask patches [set wealth random 100 set pcolor green ]: B: j/ }4 e/ N& L
end
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let mylist1 []5 d. S- |5 f* Y @6 h; L3 I
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
7 U- P, Y: r7 W" V3 ^6 S let mylist2 []
1 y3 R5 y7 L9 r" g* h0 \. ^5 B( T set mylist2 n-values count patches [? + 1]5 d' E9 A0 Y: k! l( V4 v8 B8 s
' U0 Y2 R7 ]& e4 V, t9 x9 I$ k ( foreach mylist1 mylist2' D! H) g7 C5 p, Y1 x
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2 X. L( P# s2 n* j/ I' ?# f6 ^ ask ?1[ set rank ?2]+ k0 j2 D7 {8 B# `
show [rank] of ?1
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let mylist3 []
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; u! N2 U; O: t set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
8 g3 I) W( O% j* F0 u4 U. B2 l show count patches" @% @0 d0 H2 _2 q, g9 g$ G" a3 e2 s: o
show mylist1 6 _% H# p) I1 G
show mylist33 C/ v, _. ^# {$ o( b
end `( C7 ?+ N9 ^4 J, _+ T
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这时的mylist1 和mylist3 应该是一样的 |
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