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发表于 2010-5-11 13:19:52
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用list吧
* P8 k& e8 b Z( fpatches-own [wealth rank]: V, K# o) e8 p
to setup
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, x D$ a6 J" k* a5 x- \ ask patches [set wealth random 100 set pcolor green ]
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to go5 y1 O1 E' O' o# U ?; u4 V/ b' o
let mylist1 []
* S) P8 A& |9 Z5 h# a' l set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches; M6 ^' z) \! n* E+ Z
let mylist2 []
: V) G) G3 R _' S5 z# L( _! Q set mylist2 n-values count patches [? + 1]
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0 Y+ Z8 i* c& ^: C3 Y: w" C r ( foreach mylist1 mylist2& Q3 G6 Q" y/ @' j
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ask ?1[ set rank ?2]
# A$ H. w6 s! c& h- J show [rank] of ?17 @& ~& q6 p4 z! r
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2 D- a' H/ u) L' a* W/ z+ S4 L let mylist3 []
# B( Y7 l8 P( h4 ?
9 n0 P# D" }1 Y3 u5 |+ n set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches2 y0 A: P4 S: x1 E- C
show count patches; s% U/ X0 S( g. _# E
show mylist1
T2 U f( t7 V+ ]' C show mylist3
/ K6 z$ R) Q: _7 y1 ~! qend& C" u E+ ?9 C/ |
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这时的mylist1 和mylist3 应该是一样的 |
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