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发表于 2010-5-11 13:19:52
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用list吧4 b% {* h/ T% W/ N3 L
patches-own [wealth rank]
6 {1 L1 D$ o3 ~7 ato setup8 ^$ q2 t9 A7 t
ca
, v1 b" ^/ _8 `! C. z+ h ask patches [set wealth random 100 set pcolor green ]
! w/ \' U( G6 J7 nend
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to go, j( q$ R" a& ?$ T
let mylist1 []: A( z0 R$ t ] X$ J- l3 b
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
+ N( V0 o/ W% F, L5 O8 m let mylist2 []
, f5 L# {7 `& J, Q set mylist2 n-values count patches [? + 1]+ a$ o* S+ g' @3 @
n7 ~$ t( p, d. q' j: D ( foreach mylist1 mylist2
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; T& R; |" g9 s$ P( f, r ask ?1[ set rank ?2]: C! |6 z' X1 ?. s; ]
show [rank] of ?1
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let mylist3 []
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3 N/ `4 Y( u6 K/ B, J# R j set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches- q% o( S1 N$ P. V5 g1 i
show count patches5 a8 ?8 D4 E8 {9 J) P( ~
show mylist1 ( Q, ?/ u9 X* l1 e% p$ A/ ?
show mylist37 r( p7 g; F( z% s/ }# S6 A
end' @6 z6 m# L% [9 |) W' d& U
8 i! w3 l$ U" [, P( T" n这时的mylist1 和mylist3 应该是一样的 |
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