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发表于 2010-5-11 13:19:52
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用list吧5 J* y$ e5 N( j& T) f Z
patches-own [wealth rank]1 N h; I; g. @; Q. X
to setup
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% E5 d; b6 [8 B ask patches [set wealth random 100 set pcolor green ]
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let mylist1 []( |) _4 m6 f2 w3 o* O
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
& R4 l& G3 ~5 C. k) q let mylist2 [] [# n9 ?+ h. t; |# F' A0 I" n
set mylist2 n-values count patches [? + 1]3 n& ]9 p% A0 ^$ T9 V- ?
2 s! d( w) d9 Z1 U7 T! g2 } ( foreach mylist1 mylist2
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/ W7 @* c6 m l4 N5 n# x, I/ M; y ask ?1[ set rank ?2]
; Z' F; G0 _/ }7 Z1 @ show [rank] of ?14 n5 N( Z$ f. X- `9 _ Z
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let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
6 v7 _9 B) [0 y. G show count patches1 u5 x2 o0 I* Q& d _: R
show mylist1
* m9 v, \" L( K/ k! w9 Z* o show mylist3, V' J" E2 a" U0 A% Z/ b8 r+ R
end
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/ N! j# t3 R; V* }* r# U这时的mylist1 和mylist3 应该是一样的 |
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