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发表于 2010-5-11 13:19:52
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用list吧
0 W% j7 Q$ l: n$ u# I3 c8 c" hpatches-own [wealth rank]
, t" V4 j3 B: Q" e( {$ gto setup$ `: C; W$ p- P# k6 w4 Z
ca
/ W1 ]. m; M6 O V: R% V2 h ask patches [set wealth random 100 set pcolor green ]& N3 t* U% ~" o- w# v: A2 ]. r
end- h* O, O1 u. U0 |! X5 V4 N
7 I: [6 B$ J% Y$ k% r. P! [
to go3 W8 \, J- ?$ L2 Y; p( a9 L. |
let mylist1 []
% f4 t4 o4 O# U: a( j9 a! m set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
' d9 d |# {$ U) G7 U' [ let mylist2 []
5 y+ T, b6 P, m/ H- G- x set mylist2 n-values count patches [? + 1]1 d. j* v& G6 h& M. e
3 P2 p8 Z9 B8 c4 ^! y0 @- [6 l ( foreach mylist1 mylist2
+ g. F+ v1 c0 s$ l% A0 I2 O6 P1 Q [
, C( P6 |6 Y. \+ l6 ^ ask ?1[ set rank ?2]
% B' l. u& L3 p! O. `0 ~ show [rank] of ?1
/ S: P! N" U% b& L) ^$ @" [ & b7 _# N9 U4 n; @& l
]0 k1 B5 [ W" x' {) G2 \
)3 ~# q; @. H/ E2 a$ g0 d
let mylist3 []' N! Y; M: L9 G& g+ A( B. A* r4 y* k
2 n$ w: q0 i+ q6 ~, f2 ^ set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches0 T# z" x4 @4 ]. h, E" k" i
show count patches
) t/ ?5 }8 R% K% z show mylist1 0 W- n+ c+ {' q/ d, {# ^& o4 ^2 P* d
show mylist3
- J3 B& D# ~0 e4 i9 aend
2 y$ M; k! }5 m' j& c; B- ?- }$ N) D: M j2 f
这时的mylist1 和mylist3 应该是一样的 |
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