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楼主 |
发表于 2008-4-19 16:11:18
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好像可以了
to go
0 L, x& E. \1 J! Q+ J* D set t t + 1
" Z( ^1 ?0 H e; L9 b* h grow5 Z! |; f! w# A9 p% n: B* Q2 Y* m
update-list-of-m, O0 i# j( l @, N
do-plots
$ P( B4 ^( t8 x _/ J tick
0 A& V x3 Q2 k ifelse t > 87 l2 l" |! M6 @+ e* h6 p5 k, Z, \
[if abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)))< 0.01 and+ T+ J7 o5 ?6 Z/ K
abs( mean (list (item 3 list-of-m) (item 4 list-of-m) (item 5 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 and9 f; l/ T/ B: W5 a! m. @1 {
abs( mean (list (item 0 list-of-m) (item 1 list-of-m) (item 2 list-of-m)) - mean (list (item 6 list-of-m) (item 7 list-of-m) (item 8 list-of-m)))< 0.01 2 p) p0 N6 }4 a. c; Z( o7 b
[stop]]
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各位大虾帮忙看看,这样好像可以了。以前用while之所以不行,是不是因为如果报告为true,那么就会反复运行后面的命令导致死循环啊?2 ?4 S3 \; v' h
还有就是[ ]是不是意味着不执行任何操作,返回set t t + 1,然后再grow,再 update-list-of-m,再 do-plots,再 tick ..........这样一直按这种顺序循环直到停止。+ K/ Z M" n* ?$ v5 W, e
/ b7 `1 ~, v F* J$ R[ 本帖最后由 wjcpcahu 于 2008-4-19 16:19 编辑 ] |
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