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本帖最后由 soso001 于 2014-12-17 14:53 编辑 , [$ c1 N1 A2 k \
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不好意思,打错了个字母,呵呵呵!9 U/ b" e& B8 T. u0 E
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示; q' D9 S7 T' p$ S
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!- ~' ~) p5 Z1 [9 K8 B& | ^
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j,k,nstep,c, scheduleteps,mincomptime:integer;1 t Y! B j' L1 D6 |3 V7 U, m
M:string;# T# D5 f. ]6 v# x7 M/ P5 R( d$ g
selecTab:table[integer,integer,integer,string];
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initorders;- O: T: N; @# o) f
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scheduledorders.delete;) P; m+ ?" M% P5 ^
seletTab.create;! E) \) w q9 u4 \+ a4 o; c
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orders.initialize({2,1}..{2,*},0);& J& x0 d$ V; \$ I! t. _1 ?
orders.initialize({4,1}..{4,*},0);, z' e' z3 d) w8 R9 X1 H7 ^: K, `
for j:=1 to numorders loop
5 J3 V9 f4 z- \0 f orders[5,j]:=orders[1,j][2,1];% m: p7 v* o1 X8 F$ s2 j. M9 u
next;
3 ^ |5 t+ P# f: M G( e2 e occres.initialize({1,1}..{1,*},0);& v* E8 f8 F+ D- `3 t B
1 m0 x f1 _) d# u/ C x' o1 e --XUNHUAN# w$ H3 R7 k. f+ D) [+ C" Z
for scheduledsteps:=1 to numsteps loop --' m' C: E* \3 i @8 g. M
selectab.delete;
0 z: |) Q# @. a% s. S* w: v4 r' r k:=1;: ?6 p" \7 M: v# F- t; p: K
for j:=1 to numorders loop
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* @$ N) j }+ Y: R% X- {' F nstep:=orders[2,j]+1;
6 N* r; s* H) c6 T; _: K if nstep<=orders[3,j] then; V& G( @1 a3 x7 Y4 s. ~
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];) K' k I/ W$ b, v) }' X4 f0 f8 N
k:=k+1;# m* `/ A3 U! }' i
, u4 o( L! U1 N end;" C0 s( T& |/ n6 T
next;
: l) T% W. ]1 F' D3 E mincomptime:=selecttab.min({3,1}..{3,*});' \: l0 M5 j0 I2 H* d7 ~1 ]
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from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then( k& ^8 ? d+ q/ s- C$ ?0 m% }
j:=j+1;
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selecttab.cutrow(j);) r7 x" V C) l: v
end;3 x" q0 l9 s6 `% _7 Y( ^) k% `* c
end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
0 Y5 |# O% V' z% \' }( ? orders[2,j]:=nstep;/ W: D6 A3 {, J/ c ]/ y' y
m:=orders[1,j][1,nstep];1 L( w$ [* s1 o1 k
c:=orders[5,j]
8 j5 m% m2 O7 K; E occres[1,m]:=c;1 O O: ~/ \/ A) M8 D$ r3 @- _* ~
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--jieguo:start,end,res,job,step5 k* n; E8 ], Q5 d: H/ i
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
. ?& \ X% |. I4 v4 L3 o% K+ ~3 q for k:=1 to numorders loop
% _1 e0 ` S o nstep:=orders[2,k]+1;- Y% Y: Z7 ^5 I. [ |( ?
& g& X* Y3 P% @! H7 N if nstep<=orders[3,k] and orders[1,k][1,nstep]=m3 Z2 S- y' Q6 P$ U9 ?
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then4 J3 t& Z9 [5 x
orders[4,k]:=max(c,orders[4,k]);6 F- k3 T% r' P8 u9 s+ c
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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next;
7 B& l% q- l% L nstep:=orders[2,j]+1:9 Q4 c. M/ ~4 R4 ^
if nstep<=orders[3,j]+ [0 O+ s3 Y) A! h1 Y5 v
+ U$ u! W' d0 x+ _1 j then, [; s- _' y# C. t
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);" E0 L$ d' r N+ D& H
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];$ W, k( q% H* t) }: U7 B
end;
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3 s B& x( ?) a* l5 j print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
8 z% \- o- g$ h) S5 q. Y9 m9 E mygantt;8 ^5 y( ~, Z5 p. p5 j
ens;
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