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本帖最后由 soso001 于 2014-12-17 14:53 编辑 3 {3 N" d& X, b; U
' y* s u1 A7 L( x7 L; {不好意思,打错了个字母,呵呵呵!
, X5 O# @4 a$ _) d3 f大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示" M. e2 b& @3 y; Z) Z
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!3 f& Z9 E1 s+ V1 U- J
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j,k,nstep,c, scheduleteps,mincomptime:integer;7 D& {* i% i0 D Y+ q" D
M:string;
, {. k- b- s* }' L selecTab:table[integer,integer,integer,string];; [2 N9 ^ m% ]- N6 W+ n
do
/ L, P7 R" C7 N. m, {6 L2 x2 w: ? initorders;
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scheduledorders.delete;+ \( ^- B( V0 r |
seletTab.create;
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orders.initialize({2,1}..{2,*},0);6 [: \* F$ Z0 r( v) [8 {
orders.initialize({4,1}..{4,*},0);
9 [( q* O6 J* N& Z) i, t: F for j:=1 to numorders loop: y% ]% p3 N! }8 L. x h' q
orders[5,j]:=orders[1,j][2,1];3 K* r5 N9 n. b5 {
next;' I3 B% t& R7 S9 O
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN4 y- }1 m$ ^" Y$ m/ l# S2 ]
for scheduledsteps:=1 to numsteps loop --
2 g. j/ ?9 F- ` selectab.delete;
! U1 {% ` d0 [. E& W k:=1;. V$ |( y0 p2 X+ E. q* L5 o7 \
for j:=1 to numorders loop0 Z; R% d% v' e' n
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nstep:=orders[2,j]+1;
) [9 H J B% b/ C8 G. h1 z if nstep<=orders[3,j] then9 G/ q* V& P$ e9 ^, A: g
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
( E: z7 J& `+ G: {5 F3 q/ f } k:=k+1;
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4 `. |) M* B7 z end;/ B! G7 n( C- |7 T- I) T
next;2 L8 t1 R- [ P$ M# a
mincomptime:=selecttab.min({3,1}..{3,*});
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0 `3 d( J0 \' Y' N3 n$ y; F from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then# o3 P# v C- Z6 [
j:=j+1;) a) L& `; T; ^8 v( Q- g8 K. u6 {
else( {2 S5 T2 v! k/ j( O1 R
selecttab.cutrow(j);- F5 z9 P( H D& m4 h
end;
7 [5 l7 E) M3 k2 p+ X1 A: `9 i end;
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j:=selectionrule(selecttab);
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, Z5 e3 p/ ?8 L nstep;+orders[2.j]+1;# A/ N$ ^) Z$ m7 }$ k. i+ f
orders[2,j]:=nstep;
8 {/ F4 S* ~% x; m9 \8 A/ c m:=orders[1,j][1,nstep];2 g& f G2 }; }* y! K
c:=orders[5,j]
8 i4 w. i2 ?( u; e e6 x occres[1,m]:=c;7 {3 Z9 [" K y# C" B v: E P( H
" ~! W- }, A/ l' s' o- g --jieguo:start,end,res,job,step
: ~: y) e) x, z. I! h" u: ?7 @ scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
; G) T7 f/ m5 K/ Z for k:=1 to numorders loop4 P0 N' L5 m+ [. E- F c
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
8 l5 H/ D7 t, q; D orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
( y* C! q E+ I --6 `5 m! c3 C1 c% `( l
end;1 ~3 |* b, _* A' W
next;
5 i0 B! s @& r3 D) r- N- p. _, z nstep:=orders[2,j]+1:
8 M' }6 J/ o# I0 P4 \ if nstep<=orders[3,j]& c3 k7 P& g- n/ D" `9 e2 O- y
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then
5 |: |, j$ `/ w/ U; G orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
' A- D. r5 C3 x orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
1 _ r- b- }9 a: X' h end;- Y i( E8 T( u; x* l0 l7 \, ~6 r+ X7 F
next;
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/ J' y7 D+ u4 u. Y, h8 R: | B4 ^6 a print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});5 s/ V" K9 |9 d: t$ a3 J/ ]. i
mygantt;0 M2 ?4 H" r5 R! @
ens;
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