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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!
. J$ p3 S; P# x* n大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
- w- n. d( i! F) z1 @; t& @; r o“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!' L. A: v D: y6 `) F% Y' E
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j,k,nstep,c, scheduleteps,mincomptime:integer;
5 P6 K- d/ S6 r1 s M:string;, c8 n- S; ^! }" M h0 k
selecTab:table[integer,integer,integer,string];
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initorders;: o5 E' h. l% [+ x4 o: E" c. Y
) r/ F9 P* I0 e( S. c8 A; {0 y scheduledorders.delete;0 ]" t+ Z0 T+ c1 S5 @% Y
seletTab.create;
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orders.initialize({2,1}..{2,*},0);% b/ [4 I0 }- L5 p v' P9 t% y% m
orders.initialize({4,1}..{4,*},0);
( f- @2 q% @, t/ t for j:=1 to numorders loop$ w3 K# A9 K6 W3 b: `, c# u
orders[5,j]:=orders[1,j][2,1];
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occres.initialize({1,1}..{1,*},0);
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--XUNHUAN8 K+ J9 H! u% l2 L; {2 M% |
for scheduledsteps:=1 to numsteps loop --. l+ s, \ T: r. Y. ^/ V& ?
selectab.delete;
* ^; M) O) c. f6 `5 F2 F& F k:=1;7 r; f' n5 [8 m2 R }
for j:=1 to numorders loop* ~1 F1 C) Q0 i2 Q/ M
2 X; A5 ]% }, k* {4 }6 @9 C- a nstep:=orders[2,j]+1;0 s7 P' | I( O$ q2 V6 M
if nstep<=orders[3,j] then2 c$ }" _+ m9 F6 h, U% P; Q0 X! }
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
# n' i% C' r% ~( C/ k2 G3 M k:=k+1;7 `1 g+ G7 |% ~5 Y1 Q! s
5 g" l6 g6 B& p- z0 h7 F' Z end;
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mincomptime:=selecttab.min({3,1}..{3,*});! q* C2 z- `. D: P
/ g. S c. H: u from j:=1 until j>selectab.ydim loop3 W- l( h8 x9 _( k. d: \7 l
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if selectab[2,j]<mincomptime then
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selecttab.cutrow(j);
. I+ i' `" ^! a* i* W end;
6 U2 ?0 G% L0 ?7 G0 H end;
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;6 w; b! t# T5 D; J$ Q
orders[2,j]:=nstep;
) [' W& g6 d8 j1 }, z: v m:=orders[1,j][1,nstep];
! ]( c' F' w. a c:=orders[5,j]
" z, t) g' G, o* D- x occres[1,m]:=c;
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' T* e- g6 C, f4 L* f o --jieguo:start,end,res,job,step( Q* u3 u: O# N
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);! E1 |" W# t1 E3 H+ N$ [6 l
for k:=1 to numorders loop
# v# m: V6 `) W' @+ x" I/ K( ? ] nstep:=orders[2,k]+1;6 Z4 ?1 j8 l6 }7 @; }8 B
9 U( G: T, D; g0 @" M2 B* d, J/ I if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
* e2 q( {* t d0 K --
" f) Q% U/ N- I then
) \# q) ^( f+ g- g" a orders[4,k]:=max(c,orders[4,k]);
+ ~3 z3 {5 X2 h4 }6 x* e --' {) `4 ~9 C: ]0 ?1 ~
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
: j$ G9 i1 j9 Y+ V, n) {) ?) C. } --
8 P% F1 G- v4 J: M3 ?, V4 R end;
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nstep:=orders[2,j]+1:
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
( h( k. A: J# b m, M. i orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
4 ^ u, L8 R/ G end;
, U" X: o, a% n% S next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
$ `) f k) V0 Z. U mygantt;
! N- E& t" e: `% K! L" z( T/ r ens;
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