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本帖最后由 soso001 于 2014-12-17 14:53 编辑 + d" a! j1 w1 g
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不好意思,打错了个字母,呵呵呵!+ W; y) v/ L# x6 Z9 }+ L a
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
6 ~; c' A, m9 |; I+ W6 U“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!- H+ Q( T2 t$ `# B( u
is
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M:string;
8 U/ b( l/ R: [8 F8 E5 N selecTab:table[integer,integer,integer,string];
. u+ g& u7 C r" A# {: A" A. b6 }, Jdo
# i5 ~$ U( j. E2 Q initorders;
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4 m4 p5 e1 ?% r$ f, L' K scheduledorders.delete; x8 n2 \' m7 `6 d
seletTab.create;# T# V3 Y- d% T/ J
% n: J9 Y/ p4 S) R3 _; K orders.initialize({2,1}..{2,*},0);
& B& f1 Q% u; q L- ]2 f2 M orders.initialize({4,1}..{4,*},0);
* h8 A8 h* l1 v3 e/ ^* S3 D+ J; P" Y' \ for j:=1 to numorders loop
3 d. l8 d* [0 i+ t. l3 ^$ [ orders[5,j]:=orders[1,j][2,1];
' D. k" n- J$ l) n next;
# T% \4 o. l. r; L3 N3 a( t0 t9 d occres.initialize({1,1}..{1,*},0); B/ I. I7 F$ a, `: c, z" u$ F
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--XUNHUAN
4 w; L7 \3 ^' L for scheduledsteps:=1 to numsteps loop --9 G& x1 b# w/ V( E& e: U) U! {
selectab.delete;
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for j:=1 to numorders loop; b2 k! v; F% e; j& j# J1 J" ?# b
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nstep:=orders[2,j]+1;' _; z, h% E5 y+ ?
if nstep<=orders[3,j] then% a+ V' D" e' t' H
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];, Y, I9 ^" X* j3 x" @1 ~
k:=k+1; F9 j0 S) E7 z3 z" \- W
' `! L% w4 p5 T$ V) q( K% j end;& i: y2 h7 K! ]3 I: Q1 ^! }
next;
% J& H1 J: u* @) m mincomptime:=selecttab.min({3,1}..{3,*});
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from j:=1 until j>selectab.ydim loop; O- }: c6 v; V' l
d% B0 i: ]/ i if selectab[2,j]<mincomptime then2 |2 U9 `5 Q0 g* j4 c2 g
j:=j+1;, D g6 J1 {! O3 D; N7 w
else2 ?. _! G% @6 A* N( X0 h
selecttab.cutrow(j);8 ?# E# m; `5 A, ?6 ^
end;7 X. x" e' Y8 F+ t
end;
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4 T$ p* `5 t% ]8 F. m4 y' Y. p. m j:=selectionrule(selecttab);
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* ^7 @1 o& v9 J" M nstep;+orders[2.j]+1;; h- j# ~% X% H0 j8 G
orders[2,j]:=nstep;
* E# y8 `# g# U# K' F& M7 W# W- d m:=orders[1,j][1,nstep];/ i5 h. a8 _2 R; x3 v# o
c:=orders[5,j]# j; a. d4 q# p! z
occres[1,m]:=c;$ j* R7 L+ t! F E: Y
1 Q4 R @4 |8 G0 z, S- | --jieguo:start,end,res,job,step
! q0 G. p$ Q$ D' h- c" _( F, V scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
; G# Q8 [! Q& O4 c3 _) L2 k7 ~) z, o for k:=1 to numorders loop# V" O5 |5 |$ |, E% H, o
nstep:=orders[2,k]+1;
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* w, N V0 u+ C: a# P9 X2 N. h6 E( W if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
$ Z- a, e1 V! Z' M' q3 j orders[4,k]:=max(c,orders[4,k]);
/ ^, g: b# q8 B I3 f --
4 B) K( T$ e% a' A orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];+ ]* v6 b' k! Z! n9 G8 j$ C
--: s( S9 l, w& i U* }
end;9 T/ g# C5 K* w* i {
next;) E- r9 c, _9 `3 r! w, e
nstep:=orders[2,j]+1:
* z+ a5 _8 M& u$ i- H7 @+ Q if nstep<=orders[3,j]2 Q/ Z2 L( B( L/ q9 p
% P3 J! d2 d. m( E% h
then0 S; e8 `5 {8 Y8 `% p) T5 H
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
8 S& q3 d# X1 U) I, u! _' h; v orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];! l9 P- J) }# q5 D6 y; c, `
end;2 X# H- o- ~4 U" Y5 d6 N
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*}); P n F) F+ r: M v* o8 Q
mygantt;
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