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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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不好意思,打错了个字母,呵呵呵!
" l# E- o: ?" H( w; l) w# F大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
( t, h5 p9 H, i6 w% D“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;! k% p Q( T4 c) A; a
M:string;% N7 L7 W- g9 Q6 p2 q4 Y& l$ b
selecTab:table[integer,integer,integer,string];
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initorders;
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5 m- z) I# [& o# Z W! d scheduledorders.delete;
% q T$ T. y) i1 n+ n% o seletTab.create;. w( v) a3 t* Z$ V3 `# i' d
; X2 ?4 I" c- K, v9 Y! ` orders.initialize({2,1}..{2,*},0);
5 U- d6 g/ g9 Q& s- ^" G/ e orders.initialize({4,1}..{4,*},0);
0 R' O3 S2 I) l for j:=1 to numorders loop
3 l& Q! ?7 U- e9 f- a* @ orders[5,j]:=orders[1,j][2,1];7 d, u( z/ Y1 k% x( q
next;2 d9 R& {1 W! j( N% q8 S- G
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN
7 ?2 X& j/ x, K8 w: D for scheduledsteps:=1 to numsteps loop --/ L9 J+ G8 J2 P: \ }
selectab.delete;( `) X- {( d2 p* j, s
k:=1;; h2 L O/ d2 j+ p- ?2 Q0 A
for j:=1 to numorders loop+ d5 @4 H# { {, A
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nstep:=orders[2,j]+1;
" k5 v8 D% r, F+ `. y b if nstep<=orders[3,j] then
& \* W8 O2 c2 c# v2 m! ~; O9 ~3 z selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];2 ?2 n" @( S: P0 N# H' u5 W
k:=k+1;0 d: N/ _( t: O8 m5 o
) w1 N; m/ q7 K# G# y" g end;
5 u- N4 h; |( Y+ | next;5 u7 \, G5 k! B* ^
mincomptime:=selecttab.min({3,1}..{3,*});# N& G0 Q$ H) p0 S F" j
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from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
) T! L4 w5 M7 {; f' u j:=j+1;
( W4 h# f, P* r2 n/ [. u else
- r( ~6 {5 N+ R n, U; z, J; C selecttab.cutrow(j);
4 G, S) K! `/ H8 w$ G7 F end;
# y n( L& m/ d$ ?. ], x end;6 J! n9 ^. e; m# b
4 i' J0 G& b6 y+ s j:=selectionrule(selecttab);
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4 S9 r- P0 l1 @& a G nstep;+orders[2.j]+1;
" O+ I: k5 o, E orders[2,j]:=nstep;0 _: H& ^+ k0 q
m:=orders[1,j][1,nstep];
4 _5 s8 `' }2 U+ `# Z t+ K c:=orders[5,j]
" Z: P( h q: [ occres[1,m]:=c;
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--jieguo:start,end,res,job,step& o# r/ K! {* Y) W4 z$ l, F0 C6 l
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);" D" }4 ~' y; ~0 a/ C
for k:=1 to numorders loop) z* }" x0 j1 m
nstep:=orders[2,k]+1;% g8 Z$ G6 |0 L( h5 }% y, Y5 e
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
& t1 @. | c/ {: b/ C" A) ~, h orders[4,k]:=max(c,orders[4,k]);& l% K5 V1 n! E& V' f% J! e6 S& V
--5 I7 X; ^( [3 N1 L) u I
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];6 u* i7 ~ B$ h) ~7 ?- @/ ~8 Q8 V
--
1 r/ g; p; S$ r/ Y) T end;5 ]0 c& E4 i8 E [- j
next;
$ N# H- h0 _: p5 i9 \ l/ H nstep:=orders[2,j]+1:
$ G' C8 r+ h" Q5 N if nstep<=orders[3,j]0 f/ h" J# R; m2 i+ ^+ K9 B
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then" ^. Y* ^/ l8 ^, d/ q! \
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
2 \; T N+ R# L2 ^' Z orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];# c0 w! E5 Z4 T1 Z8 G" d/ g
end;9 c" k3 L, G" l" |4 f. \
next;
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5 j' Z+ m; b" I1 ? print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});8 c$ j- Y) |; E* Q2 R
mygantt;! U* J; R0 G _ q
ens;
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