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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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3 V- Z- Q+ u1 i, ] H" `0 t我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序： s' H* f2 w0 j/ K: p, u: l! v2 X
begin P_in arriving* [5 e% _3 ^0 O$ [
move into Q_in6 r6 h! B- e l, w9 r$ o
use oper for 2 min
/ c0 z0 P c, u$ n" N8 g+ Z! H send to oneof(0.95:P_in1,0.05:die)% O5 |2 e8 C$ V/ L/ a+ _
end4 y0 T+ F' X9 g; G
begin P_in1 arriving
- t( F. w' T2 n; O if load type = load1 then
4 ] y: S- b) i. x7 D8 p6 Z: v begin
9 H6 q5 [& ]; A. D2 D7 R- [ move into Q_m1
% }- V. T t& B$ U$ A use M1 for u 5,1 min5 D; n: o7 S V
move into Q_out1
( y( x" G/ n% o& R wait to be ordered on orderlist OL_1
( W4 J: Q" d: y. y/ q2 q; ?. T Q% { end% O# G: Z5 D- @8 F
if load type = load2 then
: ^- O. l, J& F' C; J2 w begin; e/ K) L& S5 |$ N. a
move into Q_m2! R2 g4 R+ s- F5 @" P
use M2 for n 8,1 min& U9 ` G: \9 v8 W- ~8 X8 _2 i
move into Q_out2
* H5 T, g! m s. N wait to be ordered on orderlist OL_2
/ ] Q8 R0 q8 G; P( V end, _2 i$ i9 C: Z, g
end0 c4 r( C5 N3 v
begin P_dunmy arriving- {+ C3 z- T4 k8 Z
set i = 1
" b2 W% r: n$ Y4 S2 Z. ^; U while i > 0 do
( J' ~: I( N7 v( ?) `" K; k begin 2 }* T3 `# P8 _
order 1 loads from OL_1 to die
8 m$ p! O% O- r- G6 [ in case order not filled backorder on OL_1
( b6 \% n% X, t6 }1 Q order 1 loads from OL_2 to continue# c/ Z( {5 `( B1 `8 e8 ~2 ?4 E* |: v
in case order not filled backorder on OL_24 a$ n8 c: w# u& n' Z: u+ t; w( j; d
move into Q_1( H) m4 m% A+ p0 G# L* g( h- m
use Massm for n 5,1 min, d9 Y" _: Z7 s* `1 t5 v0 n
send to die0 K6 K, _! S( }) n8 z
end' Y+ h2 Y# s/ N6 J# s8 n1 ^
end' k6 }2 Q7 d& l6 `6 ~$ M
这是我的报告
~3 R* o0 ]0 x/ J5 k4 k& X' e*** AutoMod 11.1 ***3 k* H$ x. |* [/ N, W- y7 j% X0 D
Model q
1 D; `9 K5 _: Q' `Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00* T3 n- b# L5 M9 R
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
5 `# Y! n, o, j; kStatistics for Process System "q"- ^. `' J% F3 N5 l8 f. t
Process Statistics2 i( d2 B" U p8 m# K+ W
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait/ F! j2 ~( x4 Q5 f0 b4 [
========================================================================================
6 g# k) @; s7 R3 @: Z: f1 V8 TP_in 222 1 0.32 -- 2 0 -- 126.04 --6 K6 z7 L9 t& [/ Q0 F
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
3 [9 }5 `' @+ E. {* iP_in3 0 0 0.00 -- 0 0 -- 0.00 --, x( D& B% @, X x" j8 B2 m
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
6 x5 Z0 E4 I4 { GP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --% m; P- z" T" Y4 D, _5 g5 r3 H; D) J
Process Traffic Limit Statistics
9 q2 M3 F! X) ZName Total Cur Average Capacity Max Min Util Av_Time Av_Wait( v* F1 x3 Z+ o5 K" k( h% p# B
========================================================================================6 f+ z! U* U* P/ A7 B3 r
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
7 ]( {0 r. B$ [1 b1 n6 AP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --
6 j; }* w9 H' s" E! o. |P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --5 s9 U- m/ u. [0 i9 j, \2 D; R
P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
( A' u3 f4 K+ _( Z) X/ e) KP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --) u; Y# m9 q0 ]
Queue Statistics
/ I+ p+ ~3 I+ w, g. @Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait4 j- ]3 ?- t$ B4 N& h9 h. P
========================================================================================
) ?+ e/ V E4 Q% U- A$ c! a+ {Space 223 0 0.00 Infinite 1 0 -- 0.00 --. a2 w# }) T7 e, B+ M% V
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --7 w+ e% O+ @5 P' n( u2 C' s' e
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
$ W. Q1 q$ Q0 e- d! rQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
% F/ E+ l" B' V# ~+ XQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --6 x8 |% }$ M, ^. H3 E7 L0 B( w3 i y
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
! `, h8 Q% i6 w3 j& f2 o1 D) G: dQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
& k! y3 o6 w/ [1 |2 U. WOrder List Statistics
8 j' Q! q7 F8 m7 u5 vName Total Cur Average Max Min Av_Time Tot_Back_Ordered
3 o! k# f* _ ~8 s1 f6 i================================================================================
+ a7 Y% c6 d5 k$ J3 }; C- hOL_1 139 139 67.23 139 0 41789.43 1$ P! K9 \. ?1 d. @: ?. N% U
OL_2 71 71 34.26 71 0 41693.20 1* L* e6 E4 h- ]. L
Resource Statistics
* ~7 i+ X' n9 ^+ L4 hName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
7 V2 l/ G) ?5 [- b# ]3 N0 A====================================================================================================: I' E" Y' Z, h& t
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- 5 w6 q& _+ y$ I3 }2 ~
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
( J+ C: w3 _& Z9 @ D. XMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
% g' t( q7 R- w6 ]+ m" toper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
3 E5 X. ?' o0 Y% O. PRandom Number Streams
$ I: S7 D& c8 f3 X' A0 CName Total 7 i2 ^ s1 q) a1 V( d' P* w: b: `4 @
============================, H& ]8 T% g5 O- x
stream0 455
: x% j0 B, o' r7 B' ~* estream_M1_1 0
3 G* t9 ]' P$ `5 C6 \4 j5 Qstream_M2_1 0
" G- ^( k+ p# a3 E! j5 ostream_Massm_1 0
# J _( N2 \1 Y: v9 Ostream_oper_1 09 P& u( }7 x! ^6 i
stream_load1_1 1849 d6 O, Q) @' A6 b7 O- X
stream_load2_1 76
: L/ p# W& J' u$ N# c Cstream_dummy_1 0
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& \8 A# F( L- O请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
