|
|
本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 ( ?# O, {" y( y" Q' U. U
4 r8 {! [+ y8 T- [1 g! ^4 S. I
我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：5 R h! Q0 D1 \% g7 ~
begin P_in arriving
0 \* k0 q* O$ r. W move into Q_in5 K5 f+ b9 w/ {
use oper for 2 min
% f& {: U6 c7 Y$ N3 r* L send to oneof(0.95:P_in1,0.05:die)- X R" l0 x" E5 u4 {- m
end
& A1 q0 `' C, Y) k! U2 }0 ~begin P_in1 arriving
. \2 |9 ^1 j% z) F# w6 M if load type = load1 then3 h9 l6 _! t6 {. y3 [' K
begin% r, D& m2 D2 Q; x+ H; U
move into Q_m1, W3 \4 T( J$ G( N9 t
use M1 for u 5,1 min
: J4 r5 C H8 k5 e9 u; u1 L% D8 ^( w move into Q_out1
/ k& @) W r% Y# w6 C. E2 c wait to be ordered on orderlist OL_1( M6 a! A9 ?: r1 E& M! R6 `4 e1 O
end" w4 G8 r! j) Y% y( w( K6 O$ s/ a: w
if load type = load2 then" I- ]5 e' q1 S+ h2 J& o# z
begin
% A! ?5 Y% y4 R) q) \ move into Q_m2- n3 G0 _) p, @# Y/ p, i
use M2 for n 8,1 min+ m4 {, i# c. E/ f }) @/ I
move into Q_out2, y5 f0 H3 D! {7 z
wait to be ordered on orderlist OL_2; {# l" R% K7 u; r+ k
end
; l* b! l1 I1 |9 F* ?& w- Kend' M. I" l) ^6 `) ? W
begin P_dunmy arriving
! z9 U* M) M5 e) a set i = 1! b& Q/ h7 W9 j; ^ Y' N
while i > 0 do4 V& V" C* I9 \
begin " j& A8 Y9 f; S( |
order 1 loads from OL_1 to die5 k3 T7 d4 o. D0 r2 o \. f
in case order not filled backorder on OL_1
% p/ X6 `3 a) r: ^* `6 U: b order 1 loads from OL_2 to continue
% y% L/ p' o9 m5 m2 s4 [. a: c in case order not filled backorder on OL_28 d" i# D7 r: \* f" v; b1 ~
move into Q_1
8 @& n$ ]' T% V! H. ~ w5 k7 T use Massm for n 5,1 min! ^2 W1 i$ V. ]$ e" t6 p% |
send to die
& C! R- |' S4 L; t6 s- U8 v1 k* W end
1 g& F' E0 P! ?7 u; eend
: g2 `8 t& }* D, D4 k. J, u' U这是我的报告
; Y, ]4 |# Z# x8 F*** AutoMod 11.1 ***2 ^" H3 d9 \$ p2 N" w+ c* J+ @& x
Model q! _3 h' o* a7 ]- Q. t
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00, s& L) n. P( Q4 t& }& e$ Z
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
: a4 y5 W) F- I2 M- oStatistics for Process System "q"
?% }- l% I: I" F2 v7 [' }Process Statistics. n( P6 c Q. v
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait4 L( ?( n2 M2 y! ]6 h+ g
========================================================================================
7 w- v; g, G6 |& K- kP_in 222 1 0.32 -- 2 0 -- 126.04 --
$ Z t% p$ ~( l( {5 _+ PP_in1 212 210 102.38 -- 210 0 -- 41725.92 --& b* T! j( Q( U2 ~" ^
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
4 v0 Q* B9 M B7 N: |2 y6 lP_in4 0 0 0.00 -- 0 0 -- 0.00 --: m" m8 w6 @2 B5 p4 P' x; t
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --! h/ X" l( B1 V0 h0 j
Process Traffic Limit Statistics
( L4 i( O! A( c) B) RName Total Cur Average Capacity Max Min Util Av_Time Av_Wait7 {" g0 j! ^/ H/ t' H7 P
========================================================================================0 L6 M- n. q" X+ P9 K, K
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --: j+ w2 Q- r% G; p( t: x0 z1 ^6 n
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --9 C s. G9 ^" U7 R8 ]
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
* Y. ^' A: ~. y2 vP_in4 0 0 0.00 Infinite 0 0 -- 0.00 -- G" z! h9 b$ e; V! p: O7 m# Z
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
2 }- g o; T \, W- c( QQueue Statistics' D; f0 r. }" t
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
* v. L& _+ Z1 v; Q========================================================================================
% ?- m" `0 r: HSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
# Q& [' w, Q7 _. E+ T: t4 Z5 D% iQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
; F! l8 L* _* S- U- D. A5 m1 YQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
0 U: C6 P9 t: }% B4 m5 p( ^8 X# DQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --( H4 G9 }! _& ]
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
' s( g0 n# V: |5 h3 U5 A* ^Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
0 E* \; \% z5 w1 A4 F7 wQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00* h E4 j6 _) H" H7 }
Order List Statistics/ e( z: L7 r) k- S
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered$ r" E4 S8 P2 R% J: q! c
================================================================================
. L' P2 Y) J. H* |$ vOL_1 139 139 67.23 139 0 41789.43 1
" x5 b8 D$ m, h$ T% g1 JOL_2 71 71 34.26 71 0 41693.20 1% W) I5 \3 _% p6 @
Resource Statistics
! L5 x: ?$ Z# o! z7 LName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
2 W9 p, z5 ?9 G$ l1 q====================================================================================================: S- U/ d# W" s+ m
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- ( j& }7 O" n: W1 r2 Q
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
4 {0 n3 R" M ZMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- + ~1 j* D- C0 I0 H5 j
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
6 p( q0 U- a( _: ^( Y) zRandom Number Streams+ l$ C' M, Q+ G) b4 X7 S* ]
Name Total
" W2 q8 J$ T( u0 G* r. _============================6 b8 ]' V0 u. f/ s
stream0 455" v8 e, Z* d+ c& }" L" N
stream_M1_1 0& h" B5 I+ j# P% D2 f
stream_M2_1 0
: `" ^, }* q) s3 n1 _stream_Massm_1 0
" N& J A6 s+ ystream_oper_1 06 h! ]1 ~! r1 [/ K8 _. F l
stream_load1_1 184, _) s- {' g) u5 f, s1 t! P
stream_load2_1 76
0 x" E- ?! D) O2 K3 A2 zstream_dummy_1 0( p9 j, @+ I* A g
( ? E8 F b9 @ V3 E
请问我的错误在那里？我用的版本是11.1的学生版 |
本帖子中包含更多资源
您需要 登录 才可以下载或查看，没有帐号？注册
x
|
发表于 2009-12-7 19:14:35
