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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 / y* }5 m8 J1 O; w: p5 A2 U
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
. m& k3 s! V/ |) T& M t# qbegin P_in arriving
. e- w5 H9 \( Y3 C8 w) z move into Q_in4 X8 q" {/ g: _4 J
use oper for 2 min2 Z% s0 z u6 u. g0 @
send to oneof(0.95:P_in1,0.05:die)
% e. Z0 m; A, r& I- Tend
8 j! i: l* P1 M$ e% `begin P_in1 arriving: ?) c/ w' I$ ?' X, Q
if load type = load1 then+ W L% p. {7 E0 Y
begin! k% @3 n/ E5 s8 e+ r" l% A
move into Q_m1
- O( c: w U! Y! I* N2 w) Y use M1 for u 5,1 min
# M: C0 _) G7 M0 n5 _2 G6 T( M move into Q_out18 C" @$ P6 P% }2 T% Q: S U
wait to be ordered on orderlist OL_1# P# m# a! i' [7 j
end
, d! ^ G: d, _1 w9 R2 D& ^ if load type = load2 then) U( e2 ^/ S. m1 V2 E
begin9 p0 ]9 |( U h% Z: m- [2 D
move into Q_m2
* O$ v8 Q" t5 G L2 S use M2 for n 8,1 min
# T% I+ X7 ^' X1 D% F move into Q_out2" v9 f$ K. v$ ]0 K/ K& _( D: _. d. U
wait to be ordered on orderlist OL_2
+ e$ k8 p: K8 X) ^2 _8 y end
3 e1 f! I# `6 {& N- t! ^5 I* Eend# \0 Z! ?$ b4 H9 m/ e- M
begin P_dunmy arriving$ S6 q8 [( |; y2 r m3 g
set i = 1/ g4 s7 i. H6 _
while i > 0 do7 H. R( A, H+ S0 H0 G
begin ! Q/ t% ~2 U6 k: m
order 1 loads from OL_1 to die
$ n( A# \ O4 ? in case order not filled backorder on OL_1
8 _2 w4 t" k! z* q+ ] order 1 loads from OL_2 to continue' E8 N7 ?; V5 D! @( h% ^8 A' Y8 u @% \
in case order not filled backorder on OL_2
! P$ ^3 X! \! u! H0 w5 F move into Q_1
9 {3 W6 J+ R! U use Massm for n 5,1 min. p8 K) ?( ~) b& u7 v6 j$ R
send to die
! @7 t" K2 A+ e- f3 S end
, M0 F- u8 y' F$ v" C0 Mend
) ?" K) E6 b- t+ d% f' t$ l+ [这是我的报告
5 t- W7 D7 i( h*** AutoMod 11.1 ***! M4 E, v; v+ |, Y ?% z
Model q1 S' }# S* ^4 v7 L8 d' K
Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
. v8 z& x, X) W+ R, tCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
9 x/ t% @( J# M4 @: {( s3 TStatistics for Process System "q", P- Q7 f7 ^7 o. Y
Process Statistics
$ W" a7 X. R! h0 c/ NName Total Cur Average Capacity Max Min Util Av_Time Av_Wait
4 |- e* r- i& d% h========================================================================================) O7 j6 z& x% v0 b9 S7 G% I. `
P_in 222 1 0.32 -- 2 0 -- 126.04 --
: Z& G' W4 J& _. ^P_in1 212 210 102.38 -- 210 0 -- 41725.92 --# ^4 P+ ^2 K- j
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
0 D6 s9 ]! m. v% P& QP_in4 0 0 0.00 -- 0 0 -- 0.00 --" m6 M& G( ~# u( ?: B
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
% C5 _6 j2 t; ~* y, B: XProcess Traffic Limit Statistics
; Q+ i3 p* @6 O' m+ ?) @, {. d h6 CName Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 J. S) ]: j: z5 Q F: ^% Z) e
========================================================================================
9 E; `" h$ r( p" s# j" U1 lP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
! N/ {/ }6 r9 Z( \. X, EP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --. k# o' j' A6 n' k$ C7 P
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
9 [; T; A" a9 X: n6 `. r; p" e) @P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --7 h7 [% d/ ^2 b0 T# E4 a
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 -- m2 B) _- Y- ]6 C; q
Queue Statistics' c8 s) w* I% l$ F& y. Y/ k8 ]: a
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
5 ]5 n. J/ Q# D6 U7 C; \========================================================================================+ {$ k. U' C1 }7 o: [
Space 223 0 0.00 Infinite 1 0 -- 0.00 --) Z( p8 E2 J, U, e' Y) v& c5 [
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --
! B" S" v' N& w( B/ LQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --/ D2 z6 V+ C5 w* G) z8 V
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
9 h9 x1 ?. V- U3 H3 ~Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --% y( I* F& D/ n
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --% |9 I( x5 r) U' u7 P4 P7 R7 ?; F
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00$ ^' ^7 h& z5 l: R* I- u# m" } X
Order List Statistics7 t$ T4 c( N( x6 }: e
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
) i# y5 b- G# i================================================================================0 g0 |/ ]% b( G. b8 @5 b/ l
OL_1 139 139 67.23 139 0 41789.43 12 d3 L, b" U$ h& g8 v. L/ }" v6 j
OL_2 71 71 34.26 71 0 41693.20 1- r1 Y' j- V& ^% D% D' G' X
Resource Statistics
& Z( k5 f9 ^" T1 H4 o- a6 hName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
1 ?3 o+ B! o4 t, i, D# B====================================================================================================
- O) q7 b, w% ?& c1 q- d' e9 m$ `- U6 dM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
2 ~% X; @% O6 ^8 R1 c3 |/ QM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
; R) d. f3 f4 s8 uMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- . M- ~" x$ h$ w" N; O! ?
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
9 }$ u/ ]4 G+ A4 ^8 RRandom Number Streams
0 r5 F& ?, {, I' ]5 _4 Q% @Name Total
$ _" \4 ?! h6 l d: w============================' l+ ~5 g+ B: y# m" |% ]
stream0 455; K1 n& Q) n8 D/ j: W* a
stream_M1_1 0
+ s+ L: A G0 w6 ~$ Lstream_M2_1 0
3 N8 Y; K5 ]1 ~9 F/ E$ i+ Astream_Massm_1 0
2 H O) K9 v2 E, M: [stream_oper_1 0
& k$ Z" O8 j1 s+ W8 tstream_load1_1 184
8 j2 A3 ]/ `4 ~stream_load2_1 76
$ ]8 n( i5 V4 d, }$ s& rstream_dummy_1 0, Q/ X) m# n( N
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
