本帖最后由 GJM 于 2009-12-5 21:43 编辑 * v$ z9 ? N: D2 l4 w! w
1 L0 z- k0 V* u, K; c1 K底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去" {% N- G+ x @% \7 ^& b. ~
, s$ q2 I# b# _3 i: s- s2 u4 |不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!
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% x% g+ U# S7 U# b+ Z) ] ?--------------------------------------------
4 }/ X' O) I) O% M: U5 D1 H$ L1 jbegin P_something arriving
! y7 f# p; k M& D. a1 L0 W6 M move into Q_wait
% y# `8 p& G1 Z% u: E3 f2 Y move into nextof(Q_mA,Q_mB,Q_mC)& F, Q/ q" u: y( M% b( P/ G
use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min
$ }7 e; j# `% c* x% e0 Z send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)$ w0 e! o7 |0 Z5 s
send to die
: T/ U3 \# d1 b3 J, Jend
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begin P_mA_down arriving1 S3 Q! c2 x6 c4 G$ Y+ N) a
while 1=1 do . C+ J5 ?% G2 _1 T
begin
+ w- b( `6 B0 Y/ x: { wait for e 110 min! b+ I$ s) m M/ L
take down R_mA% @8 g7 a% D; _
wait for e 5 min: i4 J4 l: H/ A4 C0 T. A# ~
bring up R_mA$ x) H! ?. ?" C1 ]9 D8 M5 F5 l
end( D9 Y3 p% |: n% P$ o5 B) X
end
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begin P_mB_down arriving9 c! E! o( s: P4 v. F
while 1=1 do
% S$ b2 F8 n h begin* y: o3 H0 S1 J/ O* _
wait for e 170 min3 y5 W$ I' }% z2 v9 B" X8 L7 h
take down R_mB
7 Z1 L5 v8 g# a8 a7 z0 h- l wait for e 10 min8 f8 _/ c) Z# Q
bring up R_mB& a! n0 z' `5 ^
end8 O8 L+ Y3 H5 i4 w! {9 {
end" e# \) J5 U# e! E
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begin P_mC_down arriving/ d, r J9 {3 H, ?9 v" @! E$ z
while 1=1 do " {3 i7 F7 o7 N* U# d7 J
begin
5 @) _6 L5 H3 G8 w2 k* W wait for e 230 min
" s9 W9 X1 s/ A% A7 b take down R_mC
1 f: M- h8 G' U' L/ u: o- T8 D wait for e 10 min
) l8 ]9 j! t" T# c# j bring up R_mC. D1 M9 I2 e) K9 K0 n& a
end
3 l, I* |3 x% q, G2 `* kend- @& g7 K1 [$ B# M
- T7 ?# ?/ m4 y$ P; K4 c7 k+ u! Ybegin P_mA_clean arriving6 r# A5 }) ?# C9 Y. K- d
while 1=1 do
G* [- X3 b( a e4 A0 G q begin
# N, z) }' p5 M# e$ a# ] wait for 90 min% [5 q: D8 G+ Y) d* N
take down R_mA
2 w6 Y1 m+ _4 }5 @- B wait for 5 min- o) W0 r) T7 {5 t) `8 O
bring up R_mA! c3 N. c( I- G1 z3 i
end
5 N" o- ]9 }) [ d2 P7 F" Lend
% A6 S* l( H* n5 F( N, @5 T5 J6 ` ; a0 @3 D* A! a- c7 L; n
begin P_mB_clean arriving
4 p6 l( I, a( \5 v4 Z$ Y5 H, C) s while 1=1 do$ s* J9 O3 K5 |% {# b8 l
begin. M! G: r8 y4 d+ V
wait for 90 min
( ~* G& n6 }4 S5 [2 E take down R_mB9 M/ H! X( z- `* j5 J$ Y
wait for 5 min5 l9 D- f) \9 P- O
bring up R_mB
1 o4 r/ V6 |! i+ M. g4 V end2 a ]: |, G7 `( ^& y: v a
end
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begin P_mC_clean arriving
$ Q9 p, |/ J: z3 K2 n while 1=1 do
1 @2 V3 I2 j: A" V begin
, w/ f8 s% E$ o9 ?9 a# ~+ R, O wait for 90 min4 @8 ?% m. c7 k' m) J/ {* E
take down R_mC1 `8 x" N) Y% T0 G3 x
wait for 10 min
$ x5 Z& V- c0 P7 j9 J bring up R_mC
) |' ~8 M& r; S$ m- a end+ O q/ c( e& G; E! k5 R
end7 R! Q4 X4 B, D9 H" ^3 C+ V
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: R9 M; F& K7 A k- X; C' R8 `Exercise 5.9) M$ q+ B0 v; M' I" Z- t
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Create a new model to simulate the following system:, W& M3 T* ^# L8 s+ q
Loads are created with an interarrival time that is exponentially
+ u- q' @& [2 x% D" A; fdistributed with a mean of 20 minutes. Loads wait in an infinite-
" u8 K9 V" Z9 S; }- t# Hcapacity queue to be processed by one of three single-capacity,
/ P& Q7 k/ ]. j6 a% O8 Rarrayed machines. Each machine has its own single-capacity queue
! i# E( Q2 _" b+ }. j, @* F- _where loads are processed. Waiting loads move into one of the three
' o+ ^; U7 q3 N7 Equeues in round-robin order. Each machine has a normally
. O6 _: d, J; D w7 i# r; b$ K. qdistributed processing time with a mean of 48 minutes and a standard
$ C9 ~5 N+ i* @deviation of 5 minutes.
) B5 `9 ?. ^+ KThe three machines were purchased at different times and have 9 B' Y8 l6 a! o, h. a1 Q: q
different failure rates. The failure and repair times are exponentially . H: x4 j- H/ J, Q
distributed with means as shown in the following table:
; ]7 S, w D0 q/ v0 B* D& M+ f& ONote The solution for this assignment is required to complete
$ A6 C5 ` }) K1 r! Zexercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of
' t5 ]3 G. p: L5 `, } _your model.
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) v: F7 H: n" S5 c8 {$ o! Z- ~MachineMean time to failMean time to repair% t+ t1 q+ _+ u; N' s7 K
A110 minutes 5 minutes
- I9 W8 M2 G0 [6 }% ~' M6 J4 cB 170 minutes 10 minutes
" j7 M/ T' H7 t9 ~0 nC230 minutes 10 minutes4 N% |8 i. j) p) S, x
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The machines also must be cleaned according to the following , f6 }, |/ ~" d
schedule. All times are constant:
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( T4 H# e) [5 g' t3 e1 @1 z; g1 PMachineTime between cleanings Time to clean
/ i+ P; p1 p8 E& t- m# jA90 minutes 5 minutes
! U" ?% H3 ~; g2 [B 90 minutes 5 minutes
0 q) Q; M! [, d5 ^* ^$ CC90 minutes 10 minutes! Z; k; M0 l" k- a# M; `
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Place the graphics for the queues and the resources.
8 z0 _ v4 s! b2 M% C8 d) URun the simulation for 100 days.; l: P- c9 x" t$ l( _
Define all failure and cleaning times using logic (rather than resource
: y4 A( L- |3 acycles). Answer the following questions:; U7 R. r' @8 c# D W$ y' C
a.What was the average number of loads in the waiting queue?3 T3 C5 E* x. v, J0 X- k! \4 @7 S
b.What were the current and average number of loads in Space? . _7 v M$ P, o! ` m' Z) i. {
How do you explain these values?
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