本帖最后由 GJM 于 2009-12-5 21:43 编辑
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2 Z* j! b" U6 T' e, `: t底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去) |) q' s# [ T
" m' p; S j8 [: L; b不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!
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begin P_something arriving! Q4 q) h+ T: f( Y; B# F3 }6 d
move into Q_wait" D- s: W5 z5 g9 h+ q! y' z. t
move into nextof(Q_mA,Q_mB,Q_mC)
( E& A3 @$ l9 J7 E/ Z# y3 }* C use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min; ~/ x! p7 b& |6 t* \. _( N
send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean); @* d8 q5 K" P- X( d
send to die
: c2 _2 p) Z9 b% i9 Pend
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) j& j$ Y0 z3 x9 s, _% O" obegin P_mA_down arriving
5 W% A R( d- J1 X while 1=1 do , f! N$ M, V2 z, ~: L5 r- K
begin; D- a8 C4 b0 X' E' M; a" y
wait for e 110 min3 m. F/ P. n5 O( N# [% m
take down R_mA
8 S( q3 a! v; T" T" V wait for e 5 min
8 ~0 P/ C" \3 A: S1 g) A! S bring up R_mA& k0 _0 v {0 A( ? C
end
3 F. Q [: ]2 s6 k+ k- L% `6 Qend2 I; ]- ]1 M N. N) {( N
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begin P_mB_down arriving
3 S1 S4 P. i+ F+ M8 ]0 }1 k while 1=1 do
# o3 O+ C7 Y& c4 n begin. L# U, j! D5 ^ O' Q. t8 L: J k
wait for e 170 min5 H* H) j- K$ e8 X% J% g
take down R_mB
$ B' E; d% P( M) U: \/ z1 ?" ~ wait for e 10 min4 E7 d- I! X7 q: a/ r
bring up R_mB
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end
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4 Q. n% t7 t6 L2 `0 y, t( ?" \begin P_mC_down arriving
/ d T/ ?5 ~! r3 n; ] while 1=1 do & D7 e5 U2 ^* A! @3 j4 \+ Y% K! {0 c
begin8 t: E; ^$ K/ X' J- u
wait for e 230 min
' \% W& b% }5 m8 A) [ take down R_mC
* d8 w6 t! U: M) D wait for e 10 min
* {$ j! p4 F `) W. } bring up R_mC
9 [& A" l1 z9 G( |8 m1 Q/ P, \ end' ?) V4 i- o$ H/ A- R
end% k2 U! w0 S; |" N1 b2 N4 T
9 R* O- Q& ^/ [( a: A7 ubegin P_mA_clean arriving0 ]; ?; T/ L3 _. e
while 1=1 do
# B1 j1 M. ?' E- O, w0 _! y; c- J begin
8 L; b: ?3 Z0 v wait for 90 min
4 J, [5 e$ [+ V7 Z, _ take down R_mA$ a9 ~* ~! @" z
wait for 5 min8 o, z, Q) M9 `( L0 W; V% Q. X
bring up R_mA9 V% b/ ?% B, l: L% J! {
end
4 s$ K& b. M* h1 }1 T8 j% xend
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i. _- j6 g2 ]' S% J( Hbegin P_mB_clean arriving4 W' Q# ~7 [$ Y+ m2 l
while 1=1 do
$ E9 _" y6 y! @4 s6 U9 u begin
. s5 G) l- H% a( q8 ^, a" u wait for 90 min, ?$ f2 Q/ N3 `
take down R_mB; K! Q ?: A% d5 T8 ~
wait for 5 min N. k1 c+ h* d3 J( X& w8 j
bring up R_mB/ k8 k8 L5 F* _/ K
end/ `( e4 G# M# a r3 ^: w9 B
end
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5 M+ H/ @7 K9 m/ ebegin P_mC_clean arriving: w# R" Z& S0 R
while 1=1 do
8 q3 @) k7 B+ @4 \. ]$ S begin+ r7 r) S0 R2 `5 C; P: R- Q( s6 K
wait for 90 min1 C0 F. m, g: Y! j1 J% f) O
take down R_mC; \) j1 P6 I+ D1 z
wait for 10 min
( E8 a1 j6 E0 E9 t, @ Z9 \1 }1 t bring up R_mC
- w1 d2 m: M% p9 X end. a7 F. t v+ N$ e
end; d: C5 Z* L! F7 S, f' U
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9 v9 V) X6 b2 D6 C3 `+ nExercise 5.95 h% v$ a1 N& q t
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% M, \6 k6 L P$ u/ h. x2 ]Create a new model to simulate the following system:
+ {. o8 U# w) T( T; w, t4 c F6 r/ bLoads are created with an interarrival time that is exponentially 9 _4 [1 I( {$ e5 L% p+ ]
distributed with a mean of 20 minutes. Loads wait in an infinite-' F8 I- [; w3 a6 `1 B1 Z( Q# L
capacity queue to be processed by one of three single-capacity,
1 U' W, E" l* Qarrayed machines. Each machine has its own single-capacity queue
[% _) T4 f7 f. c- I! P6 Lwhere loads are processed. Waiting loads move into one of the three
, ^% h' z9 j P1 A" ]queues in round-robin order. Each machine has a normally
. [1 ?% V$ Y% K* a7 G0 Rdistributed processing time with a mean of 48 minutes and a standard , I! A% x, y6 w# C! Y O" r
deviation of 5 minutes.+ ~$ z5 m8 L4 `6 s% f0 V3 A# N
The three machines were purchased at different times and have 8 P1 l: C5 Y# o* _- t/ Y r& a9 _
different failure rates. The failure and repair times are exponentially
) E4 e, g r8 T/ W0 d( y) J# udistributed with means as shown in the following table: - u9 n: A' P8 E% G5 S
Note The solution for this assignment is required to complete
* Y7 d3 O1 g, Y4 \exercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of
8 R0 N& `: b# M# Y5 q7 syour model.
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! p- A. k8 h( u7 c/ kMachineMean time to failMean time to repair
9 W; \% @7 e2 C) R9 TA110 minutes 5 minutes
; g. x, `0 H8 oB 170 minutes 10 minutes% P0 L0 u- `2 L
C230 minutes 10 minutes' s' s# O+ @8 i; {! `, M, @- |! t* ?
" l7 G! @7 D0 ~, EThe machines also must be cleaned according to the following 5 l# W- w( n) C) _& t
schedule. All times are constant:
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MachineTime between cleanings Time to clean
4 Q5 r( Q9 i7 V D9 P0 I" OA90 minutes 5 minutes: ^8 E# G; H+ _4 @, u q
B 90 minutes 5 minutes
5 B$ S( ?( g5 V# B; S# L, `% yC90 minutes 10 minutes
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Place the graphics for the queues and the resources. q% O# G# Z7 j' P2 A
Run the simulation for 100 days.
1 g+ L- X @* v2 o9 i! _. TDefine all failure and cleaning times using logic (rather than resource ! T7 C, V- w) Q9 l, c6 v4 f$ {
cycles). Answer the following questions:
( k* D# h2 B7 e8 @2 Ya.What was the average number of loads in the waiting queue?
1 Z9 O8 `0 Y: b9 H, D$ ^b.What were the current and average number of loads in Space?
9 {3 t3 M/ {4 w% }0 f, d2 zHow do you explain these values? 6 H) b, r% W- |$ s: M: D
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