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发表于 2010-5-11 13:19:52
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用list吧2 Y$ k6 o6 u5 K# f: ]& S a
patches-own [wealth rank] C/ S' Z- e; U
to setup
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h8 K, ]. v" h) e7 o3 O ask patches [set wealth random 100 set pcolor green ]* u8 Z9 m( D6 G' K# f2 b: f
end* i/ e" M6 W1 V w5 _ w* I
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to go6 m- h I! O* t6 Z. V* t
let mylist1 []8 C: j: Q8 J( j, \ X0 w
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
8 m/ |' m. O9 Q let mylist2 [], ^% b0 U1 G& d( l$ Y1 J
set mylist2 n-values count patches [? + 1]: _! `. ]$ ]2 k: \) M1 p" H
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( foreach mylist1 mylist2
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ask ?1[ set rank ?2]
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let mylist3 [], m: t2 X" s9 p- O# `: z
9 B& P, `: [ Y2 h, C$ @ set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
3 p) ^7 V7 F. ^0 V! V8 i show count patches4 `5 o) i; G, R' R. E- @. @
show mylist1 ( S4 M' b5 }/ C6 Y _9 J
show mylist3" _# o6 i, v7 M7 W. ~& {
end- O! \! R" X. P! T" @5 x6 w
5 Q/ H; N9 R$ x$ ~# T这时的mylist1 和mylist3 应该是一样的 |
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