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发表于 2010-5-11 13:19:52
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用list吧
8 M0 ^1 f1 e2 I7 {patches-own [wealth rank]
2 X9 O+ J9 C; K5 \: X' ^% ^3 n6 t& Tto setup2 \, j* B0 {2 d0 P6 E
ca2 h3 J6 B- M. N
ask patches [set wealth random 100 set pcolor green ]
0 y; @9 C( d# y1 wend
1 i3 ]! s6 z9 a- v' H) }7 T% }$ x
4 j4 J4 W" d* t$ Z n& ]to go1 z$ J8 d$ q* o" o- W+ J P
let mylist1 []
- j; g3 I/ K7 _8 S set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches) X+ b1 i9 b. X M, Q4 n0 _3 v# k
let mylist2 []
' T. G" [: z2 Z6 ]" c1 ^1 f4 m set mylist2 n-values count patches [? + 1]$ I9 u; C7 c6 L& ]8 R$ L, \
0 x: s$ u! U! c4 y& m ( foreach mylist1 mylist2
$ i9 X# v9 C6 Q( Q S$ C [ n: O6 j* [. p' S" H/ s4 l
ask ?1[ set rank ?2]. \2 N" |! j' `
show [rank] of ?1
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8 s" _; {1 f' l3 C# d+ p ]
/ Q5 W1 {( w9 D: g* T" M5 y )
4 p1 C- I' h# `( D6 d$ d let mylist3 []
- {0 T4 o# Y1 q4 f* q7 h6 W! Y9 {2 _
8 ^& T9 J7 i3 l5 e set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches4 y$ O9 |0 ^/ R$ M: ^! t( B0 `' A x
show count patches
+ F! R5 T2 Z( U- ` show mylist1
* y8 A5 H8 v- I3 m, j2 ` show mylist3
4 ? Q- l& \2 V, I S. M' Lend
0 G& s4 o) z7 {) M; N! ]0 V! s8 g# S' w. Q
这时的mylist1 和mylist3 应该是一样的 |
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