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发表于 2010-5-11 13:19:52
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用list吧8 n2 }1 j7 f; I+ z5 E
patches-own [wealth rank]
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ask patches [set wealth random 100 set pcolor green ]" X: n, Z C3 `1 Q% l! u
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let mylist1 []
" G" y( L3 s5 s% Q2 } set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches1 _# s6 A% p: M$ R |: N9 w* b
let mylist2 []
) `; x. Y7 o- u set mylist2 n-values count patches [? + 1]. m+ e1 s4 q1 l6 N) q, T4 F
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( foreach mylist1 mylist2
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1 p+ S7 U" Z2 ?8 h ask ?1[ set rank ?2]
) W5 H8 h0 t9 j) w4 y show [rank] of ?1
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]
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let mylist3 []
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4 R8 X# M: i7 e; j9 d set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches3 Z. C$ \4 y3 i2 ?. f9 \, H4 F) B# }
show count patches" R6 n: C; ^: u$ L: B# O
show mylist1
7 k: ~0 @( i' c( [ Z show mylist38 h- n" u3 c7 N# U; D- w
end
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这时的mylist1 和mylist3 应该是一样的 |
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