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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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! s7 g" I8 G- V7 W- A% T6 O不好意思,打错了个字母,呵呵呵!$ L/ o. f( d: z$ M
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
& L6 g' x7 |# A1 A0 B3 W“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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8 k8 ~) p8 Z5 A: @' C j,k,nstep,c, scheduleteps,mincomptime:integer;
l8 ?2 z# a. T: f' ~$ ~- |- W' e; e M:string;" m1 w" h" s, V1 W7 `
selecTab:table[integer,integer,integer,string];0 \/ t$ @6 u( _( F9 C
do4 y# }/ h+ W/ D& W0 F$ O; v
initorders;% Q" y* p5 o( U9 D5 h. K
3 f* |: k/ K* ?0 ~4 I9 @+ m scheduledorders.delete;; _8 u# I6 `! W5 Q2 L* f
seletTab.create;
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orders.initialize({2,1}..{2,*},0);2 b( M+ V# X' B- U1 D ]& }
orders.initialize({4,1}..{4,*},0);
5 |% B2 H9 _* ] for j:=1 to numorders loop" g$ E) C( ~2 ]1 Y& l$ U; \
orders[5,j]:=orders[1,j][2,1];
H+ Q; O( y" w! a: u next;
2 W# m( Z/ D9 h4 \ occres.initialize({1,1}..{1,*},0);9 `# L. D" E: w1 w" C6 a
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for scheduledsteps:=1 to numsteps loop --
# `* m) T& `! t1 P selectab.delete;
! ]0 j. |& }. R5 q% i k:=1;
4 ^; h% q! Y8 f- t for j:=1 to numorders loop
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nstep:=orders[2,j]+1;. c- `. ^/ @; T, B$ i2 y0 H
if nstep<=orders[3,j] then+ B; C" y- {% ~/ h# {
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
9 f! }" G3 @, ^+ P k:=k+1;+ T( J# ] u! z! ]6 A9 b
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end;
# e$ F, P# A( A. f7 L' P% a1 h) N next;. C1 H$ t2 \6 a! b
mincomptime:=selecttab.min({3,1}..{3,*});% d$ ]; z+ k, W1 v0 V
: W" E0 }$ A" R% O$ m! A% h from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then( }; u1 v9 K8 [3 f; b0 n! V
j:=j+1;
1 A" A0 S5 j& J0 r# G0 M5 @ else
* K. P( [ o% `& L" M& ]2 g selecttab.cutrow(j);- t' ~% H( T' u! X q
end;7 c7 U# {+ r, ^; L6 i4 O8 Y
end;* s4 P, f3 t' `6 u3 t" h; R
9 W7 E6 H& R9 I2 ~$ | j:=selectionrule(selecttab);/ _( x5 F3 W: T# |0 v* U
. I# W3 D. v1 D( e# s nstep;+orders[2.j]+1;* U/ h: E6 @: j7 m% M( y& {
orders[2,j]:=nstep;( K' U; C0 a& V7 S4 ]: g) J
m:=orders[1,j][1,nstep];4 V; ?% T, e4 c+ {5 c! H* T" f0 t# v
c:=orders[5,j]) Y$ X* g# [& g d6 _& N2 t- Z
occres[1,m]:=c;
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--jieguo:start,end,res,job,step
$ S% ~* `$ t1 b- ^1 v& ^' H scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
, B! I. j3 K9 m# c2 z3 d3 ? for k:=1 to numorders loop0 N0 V6 A/ Y1 n1 g
nstep:=orders[2,k]+1;
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then3 u X5 o4 }8 V9 J# O4 v
orders[4,k]:=max(c,orders[4,k]);
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];$ X2 a0 K$ J2 ~7 r5 U0 B
--( a8 D4 {5 z. ^- \7 f3 j+ w
end;6 M3 O6 E4 \, J: G- t( D) Z
next;4 L0 G/ ~# D% P {. _/ \
nstep:=orders[2,j]+1: A! i9 f4 T7 u- K
if nstep<=orders[3,j]
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then
7 B# G7 s! Y- p( G orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
2 `# q1 @2 n* |8 B. Y orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];5 u; V1 k1 A0 g( y+ t) {
end;
$ p2 a7 l+ L: h! v. Y& X next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});( H; R. _# n. h9 i8 W7 M! A4 V6 u
mygantt;" F+ ^* z: ?( H1 c2 Y' d
ens;! |: O! A5 F- A/ w' l6 c4 s4 C
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