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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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, ~% F6 a+ e1 {不好意思,打错了个字母,呵呵呵!
. a9 B! F8 @. a* c7 [! O* M大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示6 R. R3 K5 N" p+ b) K1 U3 F" c
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
& t' L2 j; j* j7 e3 h! I M:string;
5 d0 X& m3 f) {! A selecTab:table[integer,integer,integer,string];
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initorders;
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scheduledorders.delete;
& }3 ? k; y+ r% f8 B& ~ seletTab.create;
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orders.initialize({2,1}..{2,*},0);
' R a t0 _; E1 r5 ^- Y orders.initialize({4,1}..{4,*},0);
0 B2 B8 x1 ^: R7 N' `' C8 o for j:=1 to numorders loop
# p% s7 } _* `9 N' @0 S" a" r) z orders[5,j]:=orders[1,j][2,1];
! X# E4 N0 Z5 h4 c/ V) f next;
1 j' |$ j' j( ] occres.initialize({1,1}..{1,*},0);
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* q1 v9 |/ J5 \" |/ o) R- h --XUNHUAN
7 F3 V2 y/ {: H% t7 \, X for scheduledsteps:=1 to numsteps loop --
' H% K! e1 U' F selectab.delete;$ y, U" t0 l: x* O0 ]6 P9 a0 n/ P B0 Z
k:=1;
3 w5 }# I$ m$ W. H0 \; ?& x for j:=1 to numorders loop
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nstep:=orders[2,j]+1;
, F; v! C' D5 ]' }: { if nstep<=orders[3,j] then
4 D3 H, v( l+ ? selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];; G8 L" n; s6 Y! Z2 \: o
k:=k+1;
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next;
6 H. Z. b, N A. Q mincomptime:=selecttab.min({3,1}..{3,*});
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; r, B; ~0 H3 e# C: I( w! \ from j:=1 until j>selectab.ydim loop
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if selectab[2,j]<mincomptime then
/ p8 n% o9 O4 s j:=j+1;$ I6 I. N" W7 p
else
+ r+ U3 K1 ]' D. c; Q selecttab.cutrow(j);) Q% u$ F* `- r/ u
end;
. z, j$ [& o& d3 j) f end;
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, j/ ]3 g: s- q$ @+ F% h j:=selectionrule(selecttab);. n% ^# w: a) E k6 V
' O; J$ o0 _/ b8 a! \3 q1 h3 R nstep;+orders[2.j]+1;
! L/ a5 z$ m% I. p) N, R* Q orders[2,j]:=nstep;, c$ o6 Q: P y% q: s0 G8 ^& |, A
m:=orders[1,j][1,nstep];
! w, T$ f3 T) _ c:=orders[5,j]' c, o5 l( [8 X
occres[1,m]:=c;& R3 c" i8 }* \" ?
4 A" `: N' J" u& l0 `. f7 Q --jieguo:start,end,res,job,step' |, |, e% _( j
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
1 J& L, F6 U0 ]! Q a2 f2 K for k:=1 to numorders loop
; w' P5 b. Q- _9 s; ? nstep:=orders[2,k]+1;4 ^+ Q' ?) l; d
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m
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then
' h9 p' V" C3 N4 b: a& i orders[4,k]:=max(c,orders[4,k]);4 `) y% W6 R: W9 f
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;% h5 a, \2 i8 V# U! {" h
next;9 y B" I# b$ S- G1 Z6 `6 y' D
nstep:=orders[2,j]+1:
1 S5 D5 L1 ?* W! F if nstep<=orders[3,j]
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then
$ u' k2 r% `$ A orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);0 G6 F% e. m+ [6 n9 M# k9 `
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];* c8 D8 D6 D p6 I9 r5 J" ]
end;+ K7 |; ]3 z, [! Q
next;* `- p* L$ y" ^& F/ i, C
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
6 F7 S, H6 y* ~, c2 M8 i mygantt;
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