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本帖最后由 soso001 于 2014-12-17 14:53 编辑 4 t& r( S' X, e# G8 `1 Q6 [
) C& O# M2 o5 i9 P9 z$ B* h不好意思,打错了个字母,呵呵呵!
# g% w2 k6 P3 _, H8 v0 U大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示" }5 Q/ C( Z. ?: _# m3 I" @
“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!- A( V x* w4 `# a
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j,k,nstep,c, scheduleteps,mincomptime:integer;
' n5 Z% |" f8 p M:string;- ~ p8 f$ s' v' J- ^
selecTab:table[integer,integer,integer,string];/ q5 _' Y. ^6 ^! R
do: E- A/ @# G: w! K: c1 n6 x
initorders; G. ]4 _, S, s9 V
; N) j4 J1 @$ y scheduledorders.delete;9 _ X) w, k/ P& B3 ~9 c. A
seletTab.create;
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0 }% t( d6 M+ Z& O( G8 b/ q; I orders.initialize({2,1}..{2,*},0);
; |; A) q7 b' T5 z% Z orders.initialize({4,1}..{4,*},0);
. o% Q4 O* m' l. l for j:=1 to numorders loop4 S( P& R% S, W# s! o5 b
orders[5,j]:=orders[1,j][2,1];
, ~& L3 c! P5 ^" t3 L! Q6 t next;
6 ^& ~) F8 y1 X occres.initialize({1,1}..{1,*},0);" H* B" d. z4 i8 N; b( A B) K3 D
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--XUNHUAN2 R$ t" P1 n: {7 U' s7 X/ ~
for scheduledsteps:=1 to numsteps loop --3 I) y3 b5 y% e9 e% Q/ }1 b
selectab.delete;5 ~0 K2 p# g/ N4 ]1 z- x. j
k:=1;
4 k( I4 w1 d3 h/ x' H for j:=1 to numorders loop# o) Q* b/ C( Z- t) C
" E" s3 Z$ Z( b nstep:=orders[2,j]+1;
. [7 B) t5 j/ B9 @2 t p9 _ if nstep<=orders[3,j] then
+ Z7 t6 ?; y: h4 x5 P& R# L selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];3 U* S: ]5 {; L; o3 z L5 o9 D
k:=k+1;2 f% T6 P; n3 Z' @; t$ L
5 O$ `( e& `. P5 |8 u* }) N; w end;
* s- M7 s& _ m! s. w next;
; ]6 l2 i7 x9 U$ p/ I# X2 u/ Y mincomptime:=selecttab.min({3,1}..{3,*});5 C) _6 t. A7 C H
! f7 D# G" K/ I* e d2 j
from j:=1 until j>selectab.ydim loop; L/ E* D# s. a) {* ] L, X- K2 @6 S
' ^ h! a" f3 \, J% \8 H4 y if selectab[2,j]<mincomptime then
) H5 f# H! p5 U* b; q5 l$ p5 N j:=j+1;) F: N! o. H9 B2 b* t+ @
else% r% Q3 V, B' L0 s7 [# W$ u* n
selecttab.cutrow(j);- B3 h! y- H: K9 b: D, j- t
end;
: U g* [( S0 r3 W5 l q5 U: E end; ]% b7 b9 b/ z8 f' _ u$ }) V
: B2 j0 d" i, V- d9 o) ] j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
* U. z+ h& @- e) H. g orders[2,j]:=nstep;
4 s& ~5 [5 g) i2 ] m:=orders[1,j][1,nstep];
3 ^1 g! c3 G9 }$ ~. y; J c:=orders[5,j]
7 v/ y" N$ l8 P& x8 Q occres[1,m]:=c;
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--jieguo:start,end,res,job,step% ^& ?4 ^0 [- y+ l+ y
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
9 n- |1 B8 D9 A! o( x; o for k:=1 to numorders loop
0 y! `# C/ y" [ E7 d. } nstep:=orders[2,k]+1;% \5 u2 G& ~1 i+ a+ `
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m' g& u* M. T& @. s0 t2 \0 c
--- N5 i2 e2 ]; P6 \9 [. v0 o# J
then# r% I5 ?" C3 B: I: k# a
orders[4,k]:=max(c,orders[4,k]);
& T3 i4 F" |& d' t; L4 ~ --
9 V5 |0 a- i6 o& H0 H9 B) B orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];( \* ~# F" }# l: M ]: u3 |
--
, W) s+ v/ m0 I end;
4 ]4 `3 k. ~3 p6 |8 ~, o. G _ next;1 {- ?/ S# b! c ^, N$ ]
nstep:=orders[2,j]+1:
$ d9 y, c; @ G+ a+ N: W% _4 a if nstep<=orders[3,j]
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; X7 n! N" I3 C$ i/ ]) d then+ p! n$ c! a! F1 G$ b3 j3 {
orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);5 g9 [! i. C* I$ Z
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];6 ~& I* X4 w1 J" N7 R2 M1 r, K
end;* O Z& ~/ A7 Y7 |/ z+ R
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});
, l8 m0 F+ m) A# j6 p' b1 V mygantt;! Y E( q* d4 _# E9 P
ens;
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