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本帖最后由 soso001 于 2014-12-17 14:53 编辑 ) B: T; S8 s5 [* x, k# ^
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不好意思,打错了个字母,呵呵呵!
, ~ z- @! j& J1 w" k0 o大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
9 p; ~9 |, B. y# l. x“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
' \0 V. I3 K ~ M:string;
% |5 B, w' n/ m& t$ G0 z& q selecTab:table[integer,integer,integer,string];
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initorders;
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) \( B. N# Y* Q scheduledorders.delete;
" A% k* R/ V, j5 Z; s seletTab.create;
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8 {4 [4 L9 P2 A; h& S orders.initialize({2,1}..{2,*},0);
B" X6 F+ r4 L: t! e4 @ orders.initialize({4,1}..{4,*},0);
1 g8 ~& v, H6 Z8 F. b! |3 ? for j:=1 to numorders loop
1 I+ Z/ X+ w' O* b. H; V orders[5,j]:=orders[1,j][2,1];. d5 g* s: e8 X7 T* A3 U
next;
" q$ N/ t* o7 o3 Y. k occres.initialize({1,1}..{1,*},0);
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8 R' X0 Q* @9 G0 c2 B. D --XUNHUAN- ~3 ~' p" {' l5 ~* S2 y
for scheduledsteps:=1 to numsteps loop --
& H' N1 ]' m) i' P/ {* X selectab.delete;6 A6 ]4 w3 \* m( r/ h
k:=1;$ j" }" P. r1 V" [) G
for j:=1 to numorders loop
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; X( _5 P: V+ H$ {. g/ R nstep:=orders[2,j]+1;3 T s$ {2 q. Y; y6 B& q
if nstep<=orders[3,j] then7 |" e. k8 s6 C9 c' s6 @/ c9 D
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
q$ `5 [, X. P: V k:=k+1;
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end;
( z, _! Y) F" X" ^+ i" p next;
3 T7 ]3 l S& m7 |. G* v mincomptime:=selecttab.min({3,1}..{3,*});
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: s/ {" H9 h2 N- Q8 G) ? from j:=1 until j>selectab.ydim loop: v0 r' e" Z+ t6 D' a" V
1 ]1 |9 o, U1 M! Y1 a, T8 C8 m if selectab[2,j]<mincomptime then0 p9 p$ E2 W* O* D; b
j:=j+1;) G8 N" y/ R( l& u1 U
else2 d/ N2 {/ N% z6 e2 q. K
selecttab.cutrow(j);
2 u3 }5 C- o0 Z5 O end;
, X' g0 {) v h* K end;! ~( d/ |4 C; w) y1 ~
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j:=selectionrule(selecttab);" h) S5 }" n8 Q/ ~ J
2 U/ M+ T- G, T( S1 V nstep;+orders[2.j]+1;
$ t: d/ |1 `7 Z% z% l8 E+ n) Y" W( @9 z orders[2,j]:=nstep;
$ m* I) { E0 r$ L m:=orders[1,j][1,nstep];
4 i1 y; c# E2 \5 @2 w c:=orders[5,j]
, p" O7 M) ?/ P4 @6 {' ? occres[1,m]:=c;6 E# v$ B, b' p9 w0 D8 ^" z
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--jieguo:start,end,res,job,step
; `& t. Z, ?: K& l c2 S scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);2 s$ S: J" k( ~+ X
for k:=1 to numorders loop
" R& [2 I* d0 Q6 {, v0 B nstep:=orders[2,k]+1;
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. D. z8 E' ? q if nstep<=orders[3,k] and orders[1,k][1,nstep]=m. r/ |, n# `& }3 i; @
--
: E. f9 B* L& F5 @9 D% H/ `- X then
% u$ w! X. z/ g3 | orders[4,k]:=max(c,orders[4,k]);
8 u/ [+ g! u4 n. T" l --
M! ?$ F% L* Y$ c I& S) v) o% U; Q2 | orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
# G' |9 M( a; @4 ` --
6 U% q- V4 L$ J2 d! `' V4 K end;
6 w+ l; s1 G* V8 e" N4 w next;. o6 v1 t0 h( k; F/ S( ~$ T3 D& v
nstep:=orders[2,j]+1:
' U( [( u8 S9 E" X) o E& Q if nstep<=orders[3,j]" |9 Y# o8 |( Q3 s
( q, u- n. i8 m. c# T+ G then
9 ]) T- f/ x; Y, w- d orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);
) z# L' L# [7 B( y7 i: r& {3 { orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
; o8 b9 |# W0 s, P end;, O1 a a, E8 ]& Y2 H- n* M
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});5 N5 q- j5 Y' I7 S6 a8 h" \
mygantt;
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