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本帖最后由 soso001 于 2014-12-17 14:53 编辑 , N* t8 R7 a$ Z; H& P
& e8 l0 \& F& r1 [3 t$ S不好意思,打错了个字母,呵呵呵!. z) l, ~0 l0 U
大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
. t* I0 N$ m( {+ `“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!: j$ ?# D1 Q7 _' _) |
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j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];; b( n- R+ P" _% ]1 K; o: a) I
do
) f7 g5 y4 }/ R( y initorders;
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! U" h: Q$ N8 I$ F+ n scheduledorders.delete;
* p$ k. E# ~' A' [! Z6 {) @ seletTab.create;
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, b7 c4 G1 h6 u orders.initialize({2,1}..{2,*},0);
% I' @; C* M4 j$ u( ` A1 ? orders.initialize({4,1}..{4,*},0);! C9 f" d5 Z9 J+ ~" ]( x' d
for j:=1 to numorders loop) ?( E- ]4 g' ?, \+ \
orders[5,j]:=orders[1,j][2,1];- N& R/ d* v, f9 U5 ^
next;
7 G0 H3 ]4 G6 G4 ^& A occres.initialize({1,1}..{1,*},0);. Q) ~' ~3 h' C; q' Q7 j
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--XUNHUAN3 J4 y1 t; T1 o# O
for scheduledsteps:=1 to numsteps loop --
2 }" _" x# s1 ~; k- H) p& t selectab.delete;' G/ g' W% d$ [3 G4 @
k:=1;9 ?6 ^- f- c. ~; c* U+ m6 V
for j:=1 to numorders loop
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nstep:=orders[2,j]+1;' S* r% P/ n& j; s( O/ L
if nstep<=orders[3,j] then4 r% m4 s4 I7 G; S0 @9 t
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];" ?/ z% R, G* t H2 f7 a
k:=k+1;
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end;
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mincomptime:=selecttab.min({3,1}..{3,*}); W! E. x2 ?% `% {* c" ^" J; @
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from j:=1 until j>selectab.ydim loop2 r& F6 H ~8 P; q, X
% P9 k% x% w8 j+ j3 o9 r if selectab[2,j]<mincomptime then
# v9 _8 H* v% j j:=j+1;/ X; s* a9 B3 r0 a6 k) B' ^: M5 |
else
8 R) D7 m0 R* g) l3 R selecttab.cutrow(j);
, ]! k) A/ I! }2 D4 ]7 K& N& a0 {! j end;
7 G2 [7 P! Q$ `. \1 h u end;, F% R1 B) h. }
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;7 k4 [: _/ _ k
orders[2,j]:=nstep;
% J+ l4 v3 @$ X# \ m:=orders[1,j][1,nstep];
/ P* n, r; D6 K$ [! {7 z c:=orders[5,j]
7 L% N g: F4 p9 N* n occres[1,m]:=c; C% h& f0 b3 s
% m; P0 @3 c: |$ @; a --jieguo:start,end,res,job,step
; c' N8 ]. ?# M) w# Z* H$ H+ ~# J; U. J scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
6 f7 K+ f- g" J6 F! b4 g* r% y for k:=1 to numorders loop
9 c% F3 I" |3 B5 h nstep:=orders[2,k]+1;( A: c$ r9 I/ A0 Z$ g. w7 r
$ F* s b/ i6 e9 [ if nstep<=orders[3,k] and orders[1,k][1,nstep]=m, p9 X0 d. s1 z0 O* A
--
! u& U+ @# @; m then
5 f8 k- V) _ P orders[4,k]:=max(c,orders[4,k]);; N/ U% |5 s# s1 ~6 ^
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];
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end;
8 G* H h) f9 r next;. _9 q9 i2 e" `" B4 U& R
nstep:=orders[2,j]+1:
' V/ E# d; P3 T7 H! o if nstep<=orders[3,j]; H3 y3 r# Y2 \: e- X" e
; o2 i7 v7 ]% ~4 L5 A; G* l; x then
) T" [( M6 A5 ?' Y) I2 O orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);6 k$ A0 S9 v: x5 Z& ^
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];- ~- T( ^0 v' ^" j1 l6 n
end;0 s$ s! `/ @4 `$ t" L7 ] ^
next;9 I% t8 ` K+ `! }1 I
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});) Q, Z9 O& l) p- M5 H4 n/ p
mygantt;
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