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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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0 t& `& U/ V. w. W" K# q# f我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:" H- N& \. S) k5 ^ R( J, P4 f
begin P_in arriving
8 F& Y' \, y& g2 C) x move into Q_in
( W* h2 u3 ]7 _' W; E% `8 [ d use oper for 2 min
! F0 s" t3 O9 ^/ q send to oneof(0.95:P_in1,0.05:die)1 M; r: u/ Q6 `7 Z
end
& h& m$ r e/ T& x Wbegin P_in1 arriving7 X% Q" g* s( d3 s0 O% u- E2 r. B; K8 E$ j
if load type = load1 then
) [+ l" e+ z7 p! G begin
( |1 D0 t) B: i$ Y; `/ N+ G move into Q_m1. _ _7 y; ~" D8 ]0 j! Y, a2 K+ N
use M1 for u 5,1 min8 A2 l: s! M& R/ U2 A) R ]
move into Q_out1
8 K5 k M& U- S wait to be ordered on orderlist OL_1
; W! t# d7 ]5 R- C* S2 m+ T end
/ L7 W8 y! R% Y! y1 S if load type = load2 then
" W) [1 S# j" S2 L0 Z begin
$ U0 ~ T5 F$ w3 z/ _ move into Q_m2- |: I( G0 c: `! G2 q' \' @
use M2 for n 8,1 min0 k9 k2 t+ s& g5 S
move into Q_out2" Z# U3 m5 Y* M' {+ z6 W ?
wait to be ordered on orderlist OL_2
1 a/ w& J+ S/ ?' O/ A( y8 ] end$ \- t! O4 Y$ @1 V1 g/ o" l% X
end; ]4 u0 o4 m5 g8 J+ J; a) F
begin P_dunmy arriving/ q! S d' M2 j7 U
set i = 12 c4 v* X* Z; {" M0 X$ C; u( O3 d
while i > 0 do: k S" P: Q+ ^" s
begin 2 K8 Z) V$ D$ b
order 1 loads from OL_1 to die3 T. w" y- P7 p( ~# \! C. J3 t
in case order not filled backorder on OL_1! j3 c* o- O# W' o0 i
order 1 loads from OL_2 to continue
$ P' {. K* i, h in case order not filled backorder on OL_2' X7 a8 |0 u9 f7 U8 Z8 \! `0 h
move into Q_1
* V1 \( H9 u2 c2 d. H% T1 h# W: x, _0 w use Massm for n 5,1 min
; c% Z. D' E5 S; s7 i1 D) U2 ]+ i send to die
6 D+ j9 h$ M* i* O# a end
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这是我的报告& n Y% e: B1 Q9 u& Q
*** AutoMod 11.1 ***
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( R# m6 e0 H8 k$ kStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00) R! _- v+ u/ H5 E) O
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec( }. v4 e* a% }, W
Statistics for Process System "q"
1 d" y( Q6 t3 {8 e% G! Q3 ZProcess Statistics7 k1 p* y% v R1 N9 W
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
+ m& Y, M7 U1 [& T8 V# A/ l7 r========================================================================================9 \) Q7 y& E; U- U/ |' Q
P_in 222 1 0.32 -- 2 0 -- 126.04 --
- e/ J+ o' `) C1 C# ]P_in1 212 210 102.38 -- 210 0 -- 41725.92 --- t) C0 `" L' d4 H, a' p1 ]1 Q ]
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
+ ?3 i9 e+ b9 L/ K; a0 f. jP_in4 0 0 0.00 -- 0 0 -- 0.00 --
+ }' z( \& I" l2 {6 T1 MP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
& W1 A5 W/ ^ r0 |/ Q6 IProcess Traffic Limit Statistics
5 _2 K/ A! ^& D* HName Total Cur Average Capacity Max Min Util Av_Time Av_Wait m- @( a5 E) _: D: x1 h9 [
========================================================================================, Q: U/ X# V* V/ w
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --/ H4 Q, L: d3 r0 l# ^* w
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --$ H& ]: V8 o* v3 N8 R* \# p% _
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
. p4 k4 a' a+ \4 k/ \P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
6 H2 {5 \- `" P5 f6 r3 a) VP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --9 G' ~$ X- P" R/ q
Queue Statistics
0 O5 O }- O, PName Total Cur Average Capacity Max Min Util Av_Time Av_Wait6 T4 W, X. J* N! ]4 w
======================================================================================== M* f5 x. {3 c' c P6 t+ B
Space 223 0 0.00 Infinite 1 0 -- 0.00 --8 U9 c) J7 ]: Q9 `: U
Q_in 222 1 0.32 Infinite 2 0 -- 126.04 --1 C C1 _$ X+ g9 C
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --9 N. K4 x$ ?, _! }3 K3 h
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
2 O q, ]- s9 r& QQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --/ R* C2 y: K! u8 D9 P4 u& A
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --- B& J+ E. t5 H9 q; V
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00
# e4 ^% l6 o& O% m" w! eOrder List Statistics1 `" N5 e! }: b/ v2 }0 T
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered5 g' E: T0 M. b: g* [
================================================================================- i: E* ~3 Y& B3 Z% W$ d
OL_1 139 139 67.23 139 0 41789.43 1! B- s: L( s9 m2 L
OL_2 71 71 34.26 71 0 41693.20 1 a! ?' J4 z) B' O q
Resource Statistics
& ~+ Q N' y3 w0 L1 hName Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
) k; R" |9 t5 J0 o( h5 u" O====================================================================================================
( _, c: B9 b% K3 d: G! U8 zM1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
" c! o6 Y8 ]/ S0 PM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- $ j# J( I: y& u0 W$ Y5 c h3 p" o0 G
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- : l) d: |) a4 G& l! O/ v
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
; ?. w) t& V2 B7 T$ NRandom Number Streams
8 V9 a c1 G1 w! N" oName Total 4 b. S2 I+ T" L2 }' ?2 T
============================
; a' t7 m6 k) l5 d3 u, E* bstream0 455
4 _- H: l2 n3 y9 B0 ]+ nstream_M1_1 03 M2 W7 N3 d% a7 ^1 V
stream_M2_1 0
4 j6 M1 O8 q5 ^! r$ rstream_Massm_1 0
* E" m8 o, a5 x. T, gstream_oper_1 0
" n+ N1 t5 S! k: `1 l) h Xstream_load1_1 184: e- m6 N; l) P/ s q
stream_load2_1 76
3 l' W* f. A+ M0 A( I3 B3 @3 ^+ ystream_dummy_1 0
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请问我的错误在那里?我用的版本是11.1的学生版 |
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