本帖最后由 GJM 于 2009-12-5 21:43 编辑 5 A, C3 Q8 t' }; E6 T3 r
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底下是小弟做AutoMOD里面PDF练习的(Exercise 5.9)逻辑文件但问题是,程序只Run到Machine A和Machine B就没继续下去
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& \( Z& |, S }3 C0 B不知道是哪里出错,另外这题和Exercise7.1的题型类似,请问若要符合Exercise7.1的题意又该如何修改呢?请各位先进指导,谢谢!
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begin P_something arriving
6 ~2 ^" E r$ h* [. k* A$ t( }9 V1 a move into Q_wait9 a9 F* y N- S: s& ]
move into nextof(Q_mA,Q_mB,Q_mC)& @6 D4 E. b Z
use nextof(R_mA,R_mB,R_mC) for normal 48, 5 min
0 G% i! u4 w/ f, Z1 |9 \: z send to nextof(P_mA_down,P_mB_down,P_mC_down,P_mA_clean,P_mB_clean,P_mC_clean)
8 S4 L8 U3 y5 q6 Z8 j7 Y( ^. C send to die
. ~9 S( P; E; L& j1 i" qend% }: R7 a7 k5 s# m/ q1 }. N
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begin P_mA_down arriving# o/ E9 Z' f, F; C; j* T) I8 s
while 1=1 do 9 ]; ?- ~' ?/ S0 G; m) j) t) {
begin- u$ v& C0 y8 m) Q3 H* ]! `: E8 ]
wait for e 110 min
7 l2 i; O8 \. z. a8 C6 B$ T9 {& d$ H" X take down R_mA* z' q" ]4 P$ \. \5 f* O# @, [8 p
wait for e 5 min
) r3 U( x5 e I0 G& r3 B" p bring up R_mA
+ ~( C& Y+ l1 y' c# L _2 @0 a4 f8 r end* y( R: @4 `- R2 R
end
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* |1 y3 S7 [# }$ u8 B% W* }7 X9 dbegin P_mB_down arriving7 i: R, ?2 |3 s. w0 {
while 1=1 do
/ A! w# i# P/ ?9 ~' A `5 @% j, T begin
9 u" \* L' E' \4 k; t wait for e 170 min
8 X n0 I: E9 R) E& B; t- k take down R_mB. G% c0 j! m# u% T. B
wait for e 10 min: @1 w6 I: [6 l: w' @+ R) [
bring up R_mB
2 `" o: }1 {1 J) \4 E9 k end: R( x& C/ j( m/ r4 y' L4 o
end' y2 F- F9 d9 [! X) Q, R8 ]
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begin P_mC_down arriving. }. F. P+ E( \) G* J
while 1=1 do
0 u1 b0 T* i- }9 C7 N: _; u begin$ J- \" ]0 G, x/ R9 B
wait for e 230 min
, h, Y3 K& m0 b5 {$ C take down R_mC
2 _4 o+ Q: A3 n4 F/ u: ] T( O wait for e 10 min
: W% j& Z9 ]0 K1 D- ~% K! {4 ~ bring up R_mC
7 D# f N9 M8 `% d& A. j end4 p9 R' |7 v2 L/ e9 W6 P; K
end. P& @+ m3 x4 X) B; S
. }! ~$ o( X; kbegin P_mA_clean arriving Z5 q5 E- k6 l c+ p# K# x% t0 \
while 1=1 do4 i0 h9 G! m5 ~
begin; g& p, o' ^2 J; h4 k8 V
wait for 90 min
6 k% z; W9 h" D take down R_mA3 B7 f# O. j; N% @3 k% w$ G
wait for 5 min
+ D& g5 W3 S, j8 I8 S( j bring up R_mA/ B ^4 `$ w O0 _1 ~
end; j; i2 W, a( a8 R
end
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1 E3 H6 B: J0 x wbegin P_mB_clean arriving3 Y2 E1 M! x0 b3 o1 X
while 1=1 do- ]& N- ~9 P+ c4 q; |+ G
begin
8 Y) w g, m P wait for 90 min
) i l3 ?& z# Z! e3 { take down R_mB
* x, w! H* U( D% h1 V wait for 5 min
1 C6 k9 `5 E5 O* V6 d( w: O bring up R_mB
4 A2 h* o. U' b2 p" q end
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begin P_mC_clean arriving1 d3 q2 ?/ I# a. q4 r7 T9 W& d
while 1=1 do6 A9 J* N" W& `: h. {( M
begin- V+ G! y; |0 \" f l9 `/ m
wait for 90 min
0 @# W i {! e! B" e take down R_mC7 b; f3 W9 o6 T
wait for 10 min
% p! \5 o( Z5 _0 Q1 y) D: _4 h+ p bring up R_mC9 p: E$ @3 k3 s( H9 Y/ t
end9 \ {9 {7 W* X" h
end* S6 i8 A' a+ Z! w
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) g7 j6 u" B0 Z% n# A0 QExercise 5.9
8 f, ]* f M+ u6 J ~* c0 L8 f: P" P |* w
4 m& u" t4 g0 D2 ^( s; qCreate a new model to simulate the following system:
( e N! L% h7 U% Y' T6 PLoads are created with an interarrival time that is exponentially 9 T- U. A7 s2 Y% G; |9 e
distributed with a mean of 20 minutes. Loads wait in an infinite-! L" R- [, [, A& ~# l5 U
capacity queue to be processed by one of three single-capacity,
/ d3 R2 B, b7 ~( r* e5 Narrayed machines. Each machine has its own single-capacity queue
& l# u* J3 @. D3 r5 zwhere loads are processed. Waiting loads move into one of the three , L$ H- g5 W; k5 z6 R
queues in round-robin order. Each machine has a normally
# }' i3 i$ P4 t. q9 G( _$ c: @distributed processing time with a mean of 48 minutes and a standard " N( C8 h" K8 b7 H, Q
deviation of 5 minutes.
7 K) t! K- l- e. R% n2 _# tThe three machines were purchased at different times and have
6 S1 T0 u1 x% }different failure rates. The failure and repair times are exponentially
, ] H7 O6 h; J6 `8 Ndistributed with means as shown in the following table:
9 `8 m; t; F" }1 f4 o1 ?+ Q7 X5 E8 k9 GNote The solution for this assignment is required to complete
7 V( z0 B0 g% V8 f9 Wexercise 7.1 (see “Exercise 7.1” on page263); be sure to save a copy of
; d) u6 A0 m, k9 D* }4 H \' ~) {6 Xyour model. % j5 a9 E. C" X5 C6 z! c# x& F) ]
" @& y$ H( B+ M+ Y x: N3 Y: {MachineMean time to failMean time to repair
% I. i7 z# p* E3 {' G( } a% j; P6 GA110 minutes 5 minutes
3 ?" P5 I% n; h1 m4 ?) n8 K5 bB 170 minutes 10 minutes
. } m2 H6 d# HC230 minutes 10 minutes
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5 p+ L3 f7 `* t- qThe machines also must be cleaned according to the following
+ Q& a9 j2 O4 dschedule. All times are constant: 9 ]4 O) ~% B8 Z) I k6 ?& [
3 m M1 L9 s1 ~" gMachineTime between cleanings Time to clean
- L* s1 H+ Y6 y- E$ o' xA90 minutes 5 minutes
$ S9 {& R1 H4 M% |' k6 B+ q& o" nB 90 minutes 5 minutes
1 T6 ~1 ?) T. O; @C90 minutes 10 minutes
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Place the graphics for the queues and the resources. 6 e7 Q. C d! {9 \
Run the simulation for 100 days.2 ~9 x R! o0 d* {3 w, R$ M3 |6 S& F
Define all failure and cleaning times using logic (rather than resource
f8 P# G& s: V( P' ecycles). Answer the following questions:3 p. n' D; q4 u0 t
a.What was the average number of loads in the waiting queue?! m4 x0 N1 R( r4 k1 }
b.What were the current and average number of loads in Space? 5 r! v9 b/ n5 C6 @
How do you explain these values?
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