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发表于 2010-5-11 13:19:52
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用list吧% p2 `7 t6 H9 U9 M. j
patches-own [wealth rank]
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ca
$ @+ x4 M) O- n; S; T ask patches [set wealth random 100 set pcolor green ]
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to go/ a( `: i# h3 H+ i
let mylist1 []% k, @1 ^% ]* N5 w4 g9 L
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
$ k$ Q4 U2 c' V$ f. t+ j let mylist2 []$ _5 \. V$ [# K; C) o
set mylist2 n-values count patches [? + 1]6 ~. C8 z( }+ N- A$ @' S- [
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( foreach mylist1 mylist2* X; j) V) h3 F1 z
[
7 \4 m8 v# _: ^# o2 W7 W) A/ C ask ?1[ set rank ?2]8 X" o0 V4 Z! r& e6 l
show [rank] of ?1/ G* R/ B+ i2 G: E: I: @
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2 f( q# W' J4 F, k let mylist3 []
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q0 W- q8 p0 L( n+ d set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches" y6 p; g6 Q7 H- d
show count patches
) h: a# ?6 g/ j0 H6 @ show mylist1
; Y- |5 e5 W5 } a' V: a show mylist3* G" _; Y9 e* I! Q7 m" O K+ N
end
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这时的mylist1 和mylist3 应该是一样的 |
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