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发表于 2010-5-11 13:19:52
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用list吧) d# {1 Q/ s4 {6 P: `% V
patches-own [wealth rank]" `3 X; d% }( F9 e/ Y
to setup2 N' q/ T3 {" e+ D; q/ ^- j
ca
) [3 C& P( e2 ]7 T, r; t ask patches [set wealth random 100 set pcolor green ]3 _3 l( a( t% b8 g, x/ s6 u
end
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% R% E3 x$ ~5 ^, w/ A" v$ lto go
# _" D- k8 j. E- ]; r$ S0 Z let mylist1 []
, o, M/ [! H8 O4 t$ M( `. V set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches% ~; k/ v! ?7 c0 m
let mylist2 []
" [6 A% \. J4 p! W$ k set mylist2 n-values count patches [? + 1]
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& ^; S0 L B8 k4 y5 C ( foreach mylist1 mylist2
Z# o( f% l+ e2 u [
. H" O% r) v/ y# a. x5 M* e ask ?1[ set rank ?2]
4 v6 Z8 v8 ` N/ i show [rank] of ?1
) k1 I2 n9 n8 q6 q 9 T1 p% B5 M+ p: k/ B
]
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1 u4 r0 p- N, b$ Z" I, `& @ let mylist3 []4 _: Z8 |0 \* c) P% S3 K
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches" V- a- q' T {$ F" c: w
show count patches5 y6 O1 d/ m f/ G- [0 x. l
show mylist1 . y5 g w! v" H: \- u' x
show mylist3
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这时的mylist1 和mylist3 应该是一样的 |
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