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发表于 2010-5-11 13:19:52
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用list吧0 k1 J1 N: H5 o. W' |# C; s& f
patches-own [wealth rank]/ L6 o0 L& w* \. m6 ]- ]
to setup
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ask patches [set wealth random 100 set pcolor green ]
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to go
( C3 z: t1 a0 V, x0 { let mylist1 []; j0 Z) C6 o+ W; I7 S* A
set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches5 }+ D8 J1 m6 C& Q
let mylist2 []5 H* g5 K7 I1 u" A3 G3 ~& b
set mylist2 n-values count patches [? + 1]
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( foreach mylist1 mylist2# Y9 z r! y8 Q0 X; _* {: f/ M3 E
[+ Y3 G- B0 f b6 @, r0 C
ask ?1[ set rank ?2]* d1 N9 t: O) A9 K: b1 Q
show [rank] of ?1
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]
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c3 h3 x! t" i" G let mylist3 []/ K* T4 u! i' j# J$ v
6 s! P g) z4 m set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches" A) v2 j1 X- ~$ ^7 w( ~
show count patches6 G/ e. A# k7 f
show mylist1
6 t) W) R- a: R& n# d! [/ y show mylist34 |7 A0 y4 z" E9 d, i! A$ Y
end+ {9 p! u! d D7 P$ T
}, X* P8 a) F+ m, l* W. u这时的mylist1 和mylist3 应该是一样的 |
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