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发表于 2010-5-11 13:19:52
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用list吧
% G, q, @7 W$ }) _3 |" s A& ppatches-own [wealth rank]4 p; q; U0 o4 {, ?* o+ @. I. p. a
to setup/ R# e6 v: z* w W: y
ca
' _5 O% h9 e/ \& T ask patches [set wealth random 100 set pcolor green ]7 X& B$ p8 L3 f
end( }2 V1 h8 A5 ^6 y8 u- o' z) c5 _
( @1 O4 q. @6 f2 B% [
to go
( C* }6 u% E; y( y6 e let mylist1 []
, d: }# o! ]5 d! G; ~2 R set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
' [: |: ^! {. j) a- R$ P j let mylist2 []" N' m% P% d( }) j( Q3 Q
set mylist2 n-values count patches [? + 1]7 j& e$ ~4 i+ d+ N8 ^ ]# |
m. {) V/ c6 _; l1 O ( foreach mylist1 mylist2
+ e/ ]) f" Z% @ [
$ R6 e8 r* I) [$ [. [0 l ask ?1[ set rank ?2]
9 {1 |3 y4 ^8 R Z7 Z: @% Z" K8 z1 { show [rank] of ?1( v/ E/ f7 m7 J' x. x& h1 P
/ U8 \/ L1 U- {1 x: p) z5 E* G6 z
]
5 f" c& j: K" P9 n: q )
; F1 _# U' @! M9 `% ~" s8 z2 r% z; \ let mylist3 []
+ w3 \" p6 S! n! S* H$ v( G: T: q4 J+ L
" w6 D+ z0 N; q2 m; e set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
: P. v) Q5 C% A" H- ~2 @+ A show count patches- `; E2 Y7 i2 ]
show mylist1
3 y# R0 o5 v& z show mylist3
" K0 E% Z3 H. s2 Pend0 V. n! V& S0 T
# w2 |1 F, \8 r5 e# u1 X% s这时的mylist1 和mylist3 应该是一样的 |
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