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本帖最后由 soso001 于 2014-12-17 14:53 编辑
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& t" ? c/ w; M" ?0 r5 i. d& D不好意思,打错了个字母,呵呵呵!
0 I, R4 n& ]7 ?大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
1 c$ N" s) w! a& Z“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
; s4 ^8 h9 |: [9 A M:string;
$ P; A7 ?& [2 j! l- @% f selecTab:table[integer,integer,integer,string];* m5 W0 M; I2 \( t+ s, i# V
do4 }: @- ]3 f4 u' I% |" p' x, ~
initorders;7 s. D) W6 Z' i; d/ ~ Z* P" S
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scheduledorders.delete;
: u. ?/ b* H' i: c seletTab.create;+ p2 X" N9 X0 @
3 H+ v' b ?8 b6 F. H orders.initialize({2,1}..{2,*},0);& G0 ~8 z$ G0 y3 s$ d8 P
orders.initialize({4,1}..{4,*},0);
5 F4 Q s- ?6 Y3 h9 d \1 V3 l( u for j:=1 to numorders loop
1 q* s/ R/ \" c orders[5,j]:=orders[1,j][2,1];
) K; N* \% Q$ M next;! J) R5 P6 L. {9 {* A4 K! M6 `
occres.initialize({1,1}..{1,*},0);
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--XUNHUAN& m9 Z7 p6 ]2 B$ o8 [: ?! `
for scheduledsteps:=1 to numsteps loop --
& \9 V# g' p8 B' S. \+ c selectab.delete;
4 J1 z2 K4 z( i k:=1;
& G9 o2 l# v; x# a$ x- H$ f8 A for j:=1 to numorders loop
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nstep:=orders[2,j]+1;* V- Z5 P5 O7 R+ ~7 ~- q
if nstep<=orders[3,j] then- U- P4 F9 h- S7 S! w; {
selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
# D/ _4 l; d2 J5 Q ` k:=k+1;
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end;
! ^( t* s9 A, n9 k2 n: P! u- Q d next;
0 s' v8 T& }. P) R" b* D4 f mincomptime:=selecttab.min({3,1}..{3,*});- c0 J/ V2 X- J
. L) l2 P5 X k, m8 S" D4 m! @& @ from j:=1 until j>selectab.ydim loop+ \5 E$ i3 M* T; |
! V$ ]% S3 ?' K2 C9 ~ if selectab[2,j]<mincomptime then
0 X( r, W: c* K+ b. ^ j:=j+1;) X7 | L. I) ?, m6 ~
else) B1 W9 t' b# s6 j8 m/ w
selecttab.cutrow(j);3 z" Q4 f& V& V. f
end;# r6 d; Y. v/ ~. d* e3 j& i; l
end;' w( }% J( y) ~, D
7 ^2 s- C1 E( Y0 k j:=selectionrule(selecttab);5 z2 |3 z- A; S. Y4 W! E
8 u( U2 o6 R, I nstep;+orders[2.j]+1;
) |+ x; p: v- O; p( z6 S$ y orders[2,j]:=nstep;4 [0 N# @, w8 y* r' K8 ~
m:=orders[1,j][1,nstep];7 p" Q' q5 F5 G1 ^
c:=orders[5,j]: l, ]* x( s$ f4 t0 I5 o
occres[1,m]:=c;
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! p; t% n, G4 H* F" l9 Y: ^ --jieguo:start,end,res,job,step
, {* j$ |8 c' ~* u. H4 F2 @4 S scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep); @$ C! _9 A- f& O7 }
for k:=1 to numorders loop" l8 a1 d; F' a) }- H
nstep:=orders[2,k]+1;. [1 i! d4 Q a+ g0 p
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if nstep<=orders[3,k] and orders[1,k][1,nstep]=m; L- x8 M' H+ K! m2 E3 R! N9 _
--* c" @* Z7 n3 f& C, s, G/ v# i- ~7 `
then
9 C" r% L4 E1 f" {9 ], R6 h2 V orders[4,k]:=max(c,orders[4,k]);. O/ r' \$ g' I o0 ^( p
--3 x% T% W( f0 u, D! A! W
orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];) `$ U9 Y- g: ]$ K4 Z
--
/ S! @. l) z* v. ^3 c end;
% X9 L" `9 L1 \# w; L+ [ next;! x8 ]( S& J. W: }( R7 b3 j1 z" ~
nstep:=orders[2,j]+1:& r4 F2 ]9 @) ^( D5 d4 E
if nstep<=orders[3,j]
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7 r# H7 `; ], ?: ^ then
3 D! N! ]2 U' `7 \( ]3 a+ L+ r8 | orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);6 i$ S$ I2 B% {* k+ n) d6 h$ p
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
0 S; s. W+ [! @3 {. j7 ~6 s end;! ~7 ~3 ?0 p1 `5 ?
next;
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print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});) x! ]# S. S0 u$ `
mygantt;
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