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本帖最后由 soso001 于 2014-12-17 14:53 编辑 8 H3 H: v, J/ {) l
! t6 J5 w1 |9 p% a) p4 ?不好意思,打错了个字母,呵呵呵!
& ?9 X+ C9 r0 P$ L" p3 y: Z, R大家好,本人em-plant新人,在看《生产系统仿真》第六章时,按书上的例子,写了段method,和书上是一样的,但总是提示
0 B! `+ R/ l0 a" F“行19中错误,循环计数器必须为整数类型的局部变量”,但我的全局变量是 integer 类型啊,不知道怎么回事,求帮助!
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j,k,nstep,c, scheduleteps,mincomptime:integer;
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selecTab:table[integer,integer,integer,string];
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initorders;9 I7 d! ]5 S+ }7 s5 E) c; m
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scheduledorders.delete;
1 D& b9 N! \9 J [2 e6 S& t _ seletTab.create;) f* j5 V' b+ z5 ?8 P. {
9 c" {2 k& W! L* s ^0 h8 x orders.initialize({2,1}..{2,*},0);1 z1 A+ q3 l) c2 r. N
orders.initialize({4,1}..{4,*},0);+ ^+ o; u, _. a
for j:=1 to numorders loop3 D4 `, r" h" H
orders[5,j]:=orders[1,j][2,1];
: A9 }2 m1 I) w6 _& O9 Y next;+ f! A7 z5 [2 I1 u/ |+ |
occres.initialize({1,1}..{1,*},0);/ Y( b4 |6 D+ m3 K% x0 l) ]8 ^
( ^5 A& y& u3 K/ w --XUNHUAN5 H% g- V7 J# b8 \: c/ [/ d* x" ^
for scheduledsteps:=1 to numsteps loop --5 r* {, a5 j+ D. z" `, l0 J2 }
selectab.delete;
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for j:=1 to numorders loop
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nstep:=orders[2,j]+1;- O5 O' ]3 G, \- R5 V7 O' K
if nstep<=orders[3,j] then
% Y, ^& ?: I {: c selectab.writerow(1,k,j orders[4,j],orders[5,j],orders[1,j][1,nstep];
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end;
4 E& D& e: a- O% H( a) t" J next;
- r: O: F9 h, E8 o# g0 Z5 U1 D h mincomptime:=selecttab.min({3,1}..{3,*});: @8 R! m$ m( K: Z! K9 b
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from j:=1 until j>selectab.ydim loop% I( f) L$ S5 J
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if selectab[2,j]<mincomptime then
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else# I" H; o! d% z3 Z @: H2 n
selecttab.cutrow(j);# w" ^9 g4 D" q& U
end;
; ~9 d& H+ E: [! r end;. s- v4 j& A3 a5 L
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j:=selectionrule(selecttab);
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nstep;+orders[2.j]+1;
% b) Y/ h4 w$ L3 Y* H orders[2,j]:=nstep;0 W- t5 ^1 Y6 D+ i0 B9 {4 ^/ ~
m:=orders[1,j][1,nstep];5 P( O( m1 @6 `% e$ F
c:=orders[5,j]" B" P q. I9 b; C& p1 a& l/ ]! o
occres[1,m]:=c;
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2 A Z/ @ x# g" z --jieguo:start,end,res,job,step! M4 N* G8 `* E2 K: Y) m
scheduledorders.writerow(1,scheduledorders,orders[4,j],c,m,j,nstep);
I) m8 }: G# b* u2 A6 N for k:=1 to numorders loop
3 v# x; j T" i2 `+ ? nstep:=orders[2,k]+1;; Z9 i. @1 [2 E
+ ^. n# N0 O( {8 j if nstep<=orders[3,k] and orders[1,k][1,nstep]=m: l5 [- P D7 z+ w4 i
--
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9 h0 t( t% |' r w1 a5 a orders[4,k]:=max(c,orders[4,k]);+ g+ \) S) v8 g! U C. ]0 D
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orders[5,k]:=orders[4,k]+orders[1,k][s,nstep];) ^- J: A* t9 P# p( d9 I
--
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next;6 E" E0 T6 c E8 B& m. ?
nstep:=orders[2,j]+1:! g. J0 w, N6 Z) J2 \
if nstep<=orders[3,j]
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orders[4,j]:=max(c,occres[1,orders[1,j][1,nstep]]);* ]; j @) t% h9 p* _) `$ c
orders[5,j]:=orders[4,j]+orders[1,j][2,nstep];
$ b6 M; N( z' e0 U# P8 Z end;
Q+ J6 a7 G) w: W next;
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' ]) T! P: U. r# P' B: O1 S7 w& p print"ready.duration of the schedule:",scheduledorders.max({2,1}..{2,*});. ]7 t4 S9 N, @: a
mygantt;% i* v/ ~/ Q8 W1 s+ r, R
ens;
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