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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
! t$ G: }. x. b- u1 ?' }begin P_in arriving
# |0 M3 ?5 ]6 G! i& u move into Q_in* O: ]7 E% n1 h
use oper for 2 min
6 |! y( E2 W: K( [% V+ a$ M& O- w send to oneof(0.95:P_in1,0.05:die)9 e J0 @2 d' o2 T, C
end
, l8 a- T/ a+ K8 U& T7 f, ?begin P_in1 arriving
0 D0 M. n* }- h" q9 [ if load type = load1 then
# Y, Q3 T/ X m' t3 M! g begin
9 t; P+ F$ j5 D2 A5 y; F7 y' {' r$ M move into Q_m1$ O A1 z3 t6 s7 o
use M1 for u 5,1 min" @ k% }3 `6 h; ]/ u( S6 C
move into Q_out1% G2 {! R+ O" K
wait to be ordered on orderlist OL_1
$ N0 b' q7 n: Z! _+ |9 F9 X end& Q# j7 I' L+ P/ L% U3 @
if load type = load2 then
$ W! T* G) n1 t5 Z0 W( H begin
- `8 z+ b2 r* M5 R f1 l move into Q_m2
) i- [# `- ]6 J! I) O7 ~ use M2 for n 8,1 min
- i+ L9 P0 z, f9 i2 Z$ A" d move into Q_out2
& w8 O4 Q: X/ c+ U' c wait to be ordered on orderlist OL_2+ ]; F( j9 x- {1 d A. l
end
$ V7 z. z2 b! ~" Rend
* Y4 M% a; t H8 B" bbegin P_dunmy arriving3 E {( n3 Y r
set i = 1
1 s& Q0 d5 S8 b8 a: @9 }7 C$ F while i > 0 do1 E* _0 T8 ~# {9 u ^; r/ O9 M
begin / {) r6 s( U4 c5 x
order 1 loads from OL_1 to die
+ D1 v" S0 f3 N6 b8 W7 f; g in case order not filled backorder on OL_10 R3 O( {! \+ p! Z! P2 C
order 1 loads from OL_2 to continue1 y4 l6 a7 h8 i; a
in case order not filled backorder on OL_2
( G! y: _$ s/ W8 w$ `9 | move into Q_1
5 Q) n) w- b# o1 P- |3 |9 a use Massm for n 5,1 min
6 L/ @; Z' ?* [0 r+ ~" q$ D send to die: v' L6 p: H6 u' @# {
end
/ q8 D7 L( s" _' }' cend
% u, v1 `, j7 O8 S" E0 n这是我的报告) z9 g7 L' A6 J& T: B) y
*** AutoMod 11.1 ***7 w0 M) E' b4 g7 Q
Model q
3 o/ M3 K2 ~$ @2 |" T$ WStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
7 V! x1 k y/ F3 Z7 C; D9 SCPU time: Absolute: 42.859 sec, Relative: 42.859 sec
. R/ x% l* j: P9 H& T7 KStatistics for Process System "q"
% m9 f/ \ Q' `% t, m" z: ]0 MProcess Statistics; c% z/ m. ]# N7 [2 N% L7 d
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 m4 o1 `# l4 F
========================================================================================! T: W. N' B/ R1 T# Q' b
P_in 222 1 0.32 -- 2 0 -- 126.04 --
2 q) P0 l6 C; E9 H# v( {. sP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
9 A( {/ _6 h$ {5 H9 ?9 }P_in3 0 0 0.00 -- 0 0 -- 0.00 --
1 N! @4 W7 Q& i& H" _P_in4 0 0 0.00 -- 0 0 -- 0.00 --! J0 N, X$ d# e
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
0 K. T; ^ o2 s5 x( E* w0 \+ dProcess Traffic Limit Statistics
$ P. P/ X. t0 p+ n1 B3 Q$ hName Total Cur Average Capacity Max Min Util Av_Time Av_Wait( R; ~6 }3 R5 s5 _% p! d0 {. M
========================================================================================
) o+ U) A4 L/ b! u# o6 CP_in 222 1 0.32 Infinite 2 0 -- 126.04 --" y+ G9 N7 y/ `0 k# ~4 Z0 A
P_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --# Q: P2 _9 J& L }2 w
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
+ L" |; H4 D+ e+ t T. aP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
+ e2 u+ h$ Q* e: _' E, p6 rP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
3 u2 ]% v$ n7 o6 L2 W2 [Queue Statistics
: `; d% M7 c' K/ sName Total Cur Average Capacity Max Min Util Av_Time Av_Wait m& M4 S# @/ q8 l; z' p/ d2 F
========================================================================================
b3 a( Y( L0 TSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
# {0 I; `( Y+ I' g+ U" JQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --: l ~% A- S$ k4 \9 z9 [
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
* q6 H, C) f8 b" n" j7 i' s" M5 I- MQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
+ @) M, C2 D; D9 ~( LQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
4 b8 i* O, Y' FQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
# W3 T5 j+ |" m" h; TQ_1 1 0 0.00 1 1 0 0.003 277.31 0.003 X# l+ i, s9 K* q
Order List Statistics
& p$ F; i9 v5 s- _8 L9 fName Total Cur Average Max Min Av_Time Tot_Back_Ordered
* o' D- w5 K6 {/ T+ Y. h/ }================================================================================
; T, I2 A$ n. Q; i& KOL_1 139 139 67.23 139 0 41789.43 1
: Q2 S) d7 ^) i" }% Z4 QOL_2 71 71 34.26 71 0 41693.20 1( k+ I/ M% v" E6 W
Resource Statistics7 k# Q$ B$ L. l% L+ N+ n
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State 1 D4 [9 ~6 P* C. m3 J
====================================================================================================- O) X% s6 k7 g. P
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
' \4 B" k* K9 E# ~M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- ) T% u& ^. u& l! a9 `
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
, ^% N3 B8 C3 W$ [5 u( ooper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
# j% @! `9 d# f& q7 d1 [Random Number Streams
! U/ J; O; H: H: I* j5 M3 QName Total 5 U: `+ }) X6 P; w
============================# J5 Z1 i R8 G2 b5 w+ y& S2 Q9 J
stream0 455! p+ N( j* y& J
stream_M1_1 0
% y% R- B( c# m: T! q Zstream_M2_1 0 @' q, m: [7 [' ]+ f
stream_Massm_1 08 `/ F$ ~! }' n6 j
stream_oper_1 0
9 T1 P0 S* F( ]stream_load1_1 184
$ L A3 D3 A( D& ]stream_load2_1 767 O& U2 e+ [& S
stream_dummy_1 06 I, B( f8 K9 P, U# ?' F* |( T
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请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
