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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
2 }( |! f' X& s- Z
! ]4 B0 l8 B$ j我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：
" j) n; E: G: K2 r! Q3 @' `& e4 Obegin P_in arriving
0 g# y2 G$ U" |0 @7 v/ V move into Q_in4 y5 L6 d+ Z$ R) t7 L, @
use oper for 2 min/ J1 C) G( b+ F! x5 p# q) [
send to oneof(0.95:P_in1,0.05:die)9 X1 [$ ^, u7 Y8 p- q
end& V# E- M' {: I& c* u$ f2 O
begin P_in1 arriving) _# P1 ?5 c2 Y' L' C0 ^* z
if load type = load1 then3 E u& T1 B" \2 H
begin
0 t8 m- ^4 M7 o& P% Z/ r- g4 w move into Q_m19 t. \2 G$ g- l% d$ c! f
use M1 for u 5,1 min
; v4 }" q3 T. l- I9 x move into Q_out14 d" z% o; h" E1 O& C5 z! E6 n
wait to be ordered on orderlist OL_1
+ c( j! _7 d5 N( g3 a) G end, n5 ]" C' y6 o w
if load type = load2 then
7 n# _* ]- C; _- f begin
* y/ z" q! \" S# Z# Q6 C4 F7 o0 D move into Q_m2( J/ O: M- l) n+ X. m( e- ?, q
use M2 for n 8,1 min( S5 y( ]" _4 p
move into Q_out2
% P5 C) L b+ }$ G) | wait to be ordered on orderlist OL_2
- o9 M, ?$ \' {- w: q" L end, f1 q3 w1 O9 _* \! K0 f# S5 U. Z6 M
end2 x3 e; R/ M5 f- N9 h% j4 z
begin P_dunmy arriving
! y+ e3 ?, w" e set i = 1
' j* e! `3 [7 q while i > 0 do
* l2 I# e* `: S' ?3 {- P! m' h begin
( @) ~8 j1 L5 }/ | order 1 loads from OL_1 to die7 M6 ]1 w! r# N9 |! I/ r8 b
in case order not filled backorder on OL_1& @# }, ^& P3 a% |8 I
order 1 loads from OL_2 to continue1 p9 G( ^% j$ M1 L# N) W9 ~
in case order not filled backorder on OL_2: d8 o9 H' a; Q! h% ^
move into Q_1+ c6 t* Z& E0 A3 o6 Q \
use Massm for n 5,1 min3 d6 G) ]; Y$ _( x- _- b, V
send to die
7 F" d. f$ }8 G9 C7 ]- J end4 w# f. V! N- n
end/ U/ T! O1 I! J2 D& v
这是我的报告2 q6 i3 t9 o9 h, n9 g& F
*** AutoMod 11.1 ***
: k4 t) v6 \9 C3 v2 sModel q
! [$ g1 t8 d+ ^: x2 R- KStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00
9 b$ {' c! n. R* L8 t/ ^" ACPU time: Absolute: 42.859 sec, Relative: 42.859 sec4 a) ^9 F: J- o3 C, p/ v
Statistics for Process System "q"* V5 w% C+ @5 H9 A" m8 a
Process Statistics
8 y: o2 p; D' l% h6 h; B0 h) [# nName Total Cur Average Capacity Max Min Util Av_Time Av_Wait! B& m6 I9 c" x5 p" X* V
========================================================================================
) z5 S2 i3 w/ v9 q. x6 w! dP_in 222 1 0.32 -- 2 0 -- 126.04 --4 {& Z0 R$ \4 Q, X2 z6 \
P_in1 212 210 102.38 -- 210 0 -- 41725.92 --$ v0 l! W1 Q1 ^4 c) A9 Y5 F
P_in3 0 0 0.00 -- 0 0 -- 0.00 --
3 f$ C( Y4 i9 s1 B; J9 s& hP_in4 0 0 0.00 -- 0 0 -- 0.00 --
, X5 h" E$ i0 k0 LP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --
) `( g( U% }4 o6 w5 @ J8 O1 |Process Traffic Limit Statistics
# I" n/ e5 ^3 z! |Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait
! q' b2 y5 s: c- `! ~, g) k========================================================================================) \) {& C& M; `" r( H6 d7 a
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
' P) p( {9 ?! k0 u1 GP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --) @/ a. E" l# w$ Y- c6 W0 e( P
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
6 H/ y* I/ D; W; r5 m" D0 BP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
L- ]$ c* b4 z& l3 N2 S5 V. vP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --$ V3 T/ K7 C# C0 q
Queue Statistics1 i2 Y6 h5 F- ^) c8 N$ F
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait0 @5 {* u# U; O6 M% C! ^* V
========================================================================================
8 {% |- z1 J! ISpace 223 0 0.00 Infinite 1 0 -- 0.00 --
: h& ]1 F* u/ @3 B' y. TQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --& t+ q9 ~8 V" z+ I: Q% W
Q_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
" N4 n! J/ r9 l" `' v% ?9 j2 p$ u y4 aQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --1 X3 c5 x/ N9 m- I/ }
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
6 C8 ~3 M2 y. s# m, D4 x5 pQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
% K. E: U5 I$ G" l1 XQ_1 1 0 0.00 1 1 0 0.003 277.31 0.00
5 \2 Z, h' P: B* l3 uOrder List Statistics
2 b5 t7 ^7 w' l( l. wName Total Cur Average Max Min Av_Time Tot_Back_Ordered
4 y/ U; M; r0 q- U l- {================================================================================% p/ X, Z Q1 c4 F
OL_1 139 139 67.23 139 0 41789.43 1
9 g2 s. A" u2 V3 C3 KOL_2 71 71 34.26 71 0 41693.20 17 \+ @! _' X7 W$ J' v; c n$ h
Resource Statistics: b3 ]. k' h8 J5 x ~
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
( a, b9 ^* k0 ]6 U3 \====================================================================================================7 y2 O2 `( T" u' l. t: k" v
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ---- - U6 ^7 @5 o9 h$ c. N# }
M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ----
1 X2 L& j1 ~5 e# n' gMassm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ----
B4 a# E: R4 ?! X( goper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
. D# ~7 y1 e/ H2 \3 W" M) L: |" [Random Number Streams/ B: r1 t4 j `* p6 x/ n# m% a; c& {: v
Name Total
6 Z6 N1 j4 [# z============================9 ~1 j7 W9 C0 ]0 v" K3 @
stream0 455% n" l" g, P1 n8 w% H
stream_M1_1 0. N1 M: {& e& x4 E2 @8 `# W, h
stream_M2_1 0% }, _- U+ _; N. s! u4 B1 k) b
stream_Massm_1 0; K$ d$ l# _, D' o* P/ ?
stream_oper_1 0+ W3 {0 s3 W/ w5 a; w
stream_load1_1 184
) w* _/ s0 R; b# v' J3 f3 Jstream_load2_1 76* `5 X( k- O: n a2 |" f
stream_dummy_1 0
/ Q6 M% Y4 k! d; Q8 ]8 A6 Q( {) e& N, M" f- q2 ^
请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
