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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑 8 v& x3 B4 N4 }
7 H0 s$ h8 `8 v. s! o. i
我今天遇到一个问题，请问你知道如何把来自两种不同的load1和load2在一个机器上加工，合成一个load,该如何使用order命令？我每次运行的时候，给出的报告里面资源机器Massm没有load经过？以下是我的程序：5 ^6 _1 h! Y* x( u( D5 v7 J# u3 h
begin P_in arriving9 ~/ O! [1 M8 o! t5 x+ @
move into Q_in0 H0 {. Y% x+ U2 r% n9 o
use oper for 2 min& _9 d; n0 [* ]9 q
send to oneof(0.95:P_in1,0.05:die)( `/ f. X; \) y l! |1 h
end
% v1 b7 F ?! }- L2 ]4 k, Gbegin P_in1 arriving) \0 B z% }; E8 A
if load type = load1 then
/ i9 @9 K1 W7 T begin0 ?5 v+ w% Y6 N- ?6 A- l
move into Q_m1
8 }8 h, h5 R! P: `/ @' H use M1 for u 5,1 min
7 }% v( S9 R/ D8 J! F4 l move into Q_out1
5 W0 R& B, c8 _" @3 d/ ~+ w wait to be ordered on orderlist OL_10 L8 f1 q5 N8 a) L) x& P* w
end' r, N: b0 ?0 F8 k
if load type = load2 then
. D: A9 N% N% w+ b$ U begin9 }5 n* ~. A( l
move into Q_m2
: a9 X/ _( U3 F! R4 t! O use M2 for n 8,1 min
" c, k8 s# r2 L' W: p v move into Q_out2
% g# P$ ~0 W* j2 j5 v+ _ wait to be ordered on orderlist OL_2
/ m" G6 d7 A- [4 x7 i end
& ~9 r4 D1 h% v/ S$ t0 bend
, C3 [' D; R1 U& H0 D6 S; C: q9 Pbegin P_dunmy arriving# d% k0 ? l% v" x! J9 H3 r4 U
set i = 1
9 w& ^ \' N8 R R while i > 0 do% ?+ H4 g( ^4 o F* f& q) b( Y/ ~
begin
! a5 d+ C4 J( U' w3 D order 1 loads from OL_1 to die" j1 @! L0 @7 j/ }3 C) A
in case order not filled backorder on OL_1% S$ F6 J2 f+ t. a ~
order 1 loads from OL_2 to continue
; A9 s- j$ C2 r8 [3 J- w in case order not filled backorder on OL_2& d7 Z) \: r! v. _; y
move into Q_1) A6 q' K7 p, w+ R
use Massm for n 5,1 min
1 ]6 Z) e6 l+ K( N send to die
+ T: Z9 r$ l% Y/ ?1 A* c end
]3 @* e; E; G" G! A+ Nend
- z5 d. f. O9 ^! i这是我的报告
. k4 P7 T) P" l/ G s*** AutoMod 11.1 ***
8 t* P% R! A) S x QModel q
) \# k$ F: ? ~Statistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.004 Y7 X# A- p+ h
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec
' |. k" L2 A0 s1 s) M& r/ l: r% _3 I' p! P, VStatistics for Process System "q": V; m0 l0 E# j& r4 y
Process Statistics! l6 W$ t/ g1 x: N% a7 V
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait8 F1 }% g8 I5 g* X
========================================================================================
1 G. Y Z% u' Y& B& r2 f, HP_in 222 1 0.32 -- 2 0 -- 126.04 --
/ r/ b/ Q& s' H; k+ g4 ^P_in1 212 210 102.38 -- 210 0 -- 41725.92 --
( I% X+ u' i0 L4 q: g* MP_in3 0 0 0.00 -- 0 0 -- 0.00 --* i: v: r; M" l5 E" K5 m, _
P_in4 0 0 0.00 -- 0 0 -- 0.00 --
) z* o" _/ l9 M" d( Y/ z9 B* s1 wP_dunmy 1 0 0.00 -- 1 0 -- 277.31 --% ^; [/ B7 c3 j" B" F7 s( Y: f
Process Traffic Limit Statistics' e7 ?3 G& t8 c+ w; \) x- x* r8 k
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait% b6 L2 C9 K+ @9 \# z: y
========================================================================================5 L5 r: y; s" B" T1 H# I6 |
P_in 222 1 0.32 Infinite 2 0 -- 126.04 --
- z$ w* o2 L. H; wP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --+ t* u A- b/ T E: \' S
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
. m) R' {( |9 J: f b7 ^" f8 R" DP_in4 0 0 0.00 Infinite 0 0 -- 0.00 --
j8 L# G, v% t& g2 HP_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --9 B6 `2 m. e3 ]' ]7 U* g J
Queue Statistics
* |! h- {3 A" S/ o+ f0 v0 J `! ^; EName Total Cur Average Capacity Max Min Util Av_Time Av_Wait* S2 f6 o" w" m/ Z1 j y; G
========================================================================================
# R4 J1 T! M, ^3 M9 I9 O$ oSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
6 d2 r8 e1 w# T- F6 I' d* IQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
2 x* |5 Q8 i0 ]5 N" F7 XQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --
8 [9 ~. s$ e/ I6 G9 HQ_m2 72 0 0.40 Infinite 2 0 -- 485.61 --! ^8 ?8 Q% b2 I) L' v
Q_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --7 ?# z5 A. \' e3 s! m/ i& P9 E
Q_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --
4 e8 @8 [/ M' ?& c3 A- `3 J* bQ_1 1 0 0.00 1 1 0 0.003 277.31 0.007 v7 p- b8 A# O) c0 K
Order List Statistics& L I- n: Q& s9 H3 W4 I0 C8 `$ z
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered
$ R4 \4 s: T# R0 |9 B================================================================================6 Q# M: U* O C4 J% ]
OL_1 139 139 67.23 139 0 41789.43 1
# O& h$ H9 y5 ~) W0 F0 K+ `' sOL_2 71 71 34.26 71 0 41693.20 1
0 H" D% M6 Q* H9 A( ZResource Statistics9 @; K3 u$ Z( x& o V
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State
! N& {# N9 f \1 U+ c1 d S8 `. l====================================================================================================. L+ O( [- h+ o& A+ W9 i
M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
& V; P6 `3 i) l$ d C6 z/ O, {4 xM2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- $ c8 P+ _( P1 `$ ?' o
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- 4 s+ U) l, c" {. Z+ ^ r+ C/ w
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
; x! L+ ?! x3 k6 G9 l; [, LRandom Number Streams% C2 _, X5 t% x) _. w7 \; \
Name Total
9 h) P9 O8 ?0 U9 H- I============================
. B4 Z6 w" G# t% Wstream0 455
5 V" I6 l4 x- F* X# rstream_M1_1 01 l3 `* y7 C+ a) a# |. I, r3 w* K1 ~
stream_M2_1 0, g% g* J, e- u; |7 Z1 }
stream_Massm_1 0
2 t6 q9 X% V' A& g6 |5 |stream_oper_1 0
" ^1 H. g7 d, ~& D5 dstream_load1_1 184) y2 ~! _5 {! {' Y
stream_load2_1 76 H# N, n' v, s! y) y9 P
stream_dummy_1 07 K+ t/ `# \4 k& l U: q
1 }2 M+ x3 {% e
请问我的错误在那里？我用的版本是11.1的学生版 |
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发表于 2009-12-7 19:14:35
