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本帖最后由 coolyfoot123 于 2009-12-7 20:07 编辑
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, f3 T k; L3 x) L+ p" ?! i我今天遇到一个问题,请问你知道如何把来自两种不同的load1和load2在一个机器上加工,合成一个load,该如何使用order命令?我每次运行的时候,给出的报告里面资源机器Massm没有load经过?以下是我的程序:7 P; g3 E7 `+ v+ q( m3 D
begin P_in arriving
# A) [* C) R+ K8 t4 M! d, I3 ~) I move into Q_in
' Y9 ?+ u @5 j% b M& T; y use oper for 2 min
$ `1 N$ H8 P( `* j% y* F( o send to oneof(0.95:P_in1,0.05:die)
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begin P_in1 arriving
) ^/ K* [# E q if load type = load1 then! E+ [ ~$ h, g- r( H0 n5 I; v. |
begin( _2 a$ i6 ~, r+ b" o4 T$ k* I1 x
move into Q_m1
( `6 n) x! l' }; y" B use M1 for u 5,1 min
z' l( i, v i* e" A% o9 T9 \ move into Q_out1
$ b K& r/ }# k: }( c( n wait to be ordered on orderlist OL_1
+ _3 V% i% G1 A+ c end0 C/ E. z" J" s% |3 ]* y$ g7 q
if load type = load2 then
5 x2 Y# t1 P$ y begin
; N6 ~4 R6 K7 i move into Q_m2
4 P7 U0 K G3 k$ c7 X( } m# P use M2 for n 8,1 min6 j9 G: j1 _5 z' U0 \. z
move into Q_out2
7 j' o4 r; y, [' S6 l wait to be ordered on orderlist OL_24 J# W1 _ f: B; w( Z$ p
end
- F# L' z$ B5 u, a" Dend
* e* p$ {5 y6 Z9 zbegin P_dunmy arriving1 \& N! G' ` Q; ]
set i = 1/ f1 c2 ?8 x. x8 D
while i > 0 do, }2 [* P2 t4 _" H# _
begin ; L3 a' O8 V; T" Q* F
order 1 loads from OL_1 to die- |1 L! A* ^8 R0 P0 Q/ J
in case order not filled backorder on OL_1
: `% } G# {' s Q order 1 loads from OL_2 to continue# t: E7 f' |: o% v+ S5 t: o7 o
in case order not filled backorder on OL_2
8 S9 P6 A8 S( w; n% s move into Q_13 D: f, d3 X7 @4 S( {; s7 g( I
use Massm for n 5,1 min
! X# m5 x/ z2 X6 A% Z send to die. K, M$ [$ i: N6 i( Z0 }. E0 M
end
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这是我的报告, w H- Q9 q! X9 ~( m
*** AutoMod 11.1 ***+ Z% v* O4 k; A3 c$ ~
Model q
+ M7 H2 c; v7 O+ o0 vStatistics at Absolute Clock = 1:00:00:00.00, Relative Clock = 1:00:00:00.00: |7 ] W! Z7 L; m
CPU time: Absolute: 42.859 sec, Relative: 42.859 sec/ G, |& E) Z' z& e" `
Statistics for Process System "q"
/ r. V: q1 x: F: tProcess Statistics3 F0 Y8 c& Z- R& a$ ?+ l' c) L
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait, V/ W- s: p, t& b
========================================================================================
2 {9 |% t( ?6 r/ ?) hP_in 222 1 0.32 -- 2 0 -- 126.04 --
3 r, s: _% s+ c+ v6 WP_in1 212 210 102.38 -- 210 0 -- 41725.92 --
7 u2 l5 j; o) D6 b0 w0 z2 Y5 b+ @, @) RP_in3 0 0 0.00 -- 0 0 -- 0.00 --4 W5 z4 u' }/ X1 @
P_in4 0 0 0.00 -- 0 0 -- 0.00 -- _7 H4 [/ x! u. N5 C, f6 P
P_dunmy 1 0 0.00 -- 1 0 -- 277.31 --$ I3 @7 Z; f, i
Process Traffic Limit Statistics
; o1 [! T& E6 y# dName Total Cur Average Capacity Max Min Util Av_Time Av_Wait# w0 r9 O/ K+ i0 A/ w
========================================================================================
# h- }7 V4 \5 U/ u, EP_in 222 1 0.32 Infinite 2 0 -- 126.04 --
4 T3 n9 C+ r1 i3 J- q( wP_in1 212 210 102.38 Infinite 210 0 -- 41725.92 --7 u A" A( B7 k1 [
P_in3 0 0 0.00 Infinite 0 0 -- 0.00 --
s+ K- E# C) T* {P_in4 0 0 0.00 Infinite 0 0 -- 0.00 --$ r+ `% J0 f. P& h# |
P_dunmy 1 0 0.00 Infinite 1 0 -- 277.31 --
/ T; W2 N' \3 m* R- T6 sQueue Statistics7 q! }7 L& |* e: q7 a
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait' a6 Y) ~% [2 g( N
========================================================================================
( B* v9 c) g$ C4 r; G vSpace 223 0 0.00 Infinite 1 0 -- 0.00 --
9 ~# Z; I+ J8 l6 {- DQ_in 222 1 0.32 Infinite 2 0 -- 126.04 --
4 B. _# c. g7 i0 c/ u+ Y/ k7 G4 SQ_m1 140 0 0.49 Infinite 2 0 -- 299.88 --4 U# S5 P2 J8 {( K7 l9 @2 P9 P
Q_m2 72 0 0.40 Infinite 2 0 -- 485.61 --
, S" P0 G$ t0 R! t. d# m3 gQ_out1 140 139 67.23 Infinite 139 0 -- 41490.93 --
' G1 X' Z: g2 C1 r m$ m1 O# UQ_out2 72 71 34.26 Infinite 71 0 -- 41114.13 --# X3 u2 W7 M+ N' R1 |. @
Q_1 1 0 0.00 1 1 0 0.003 277.31 0.00& ]1 u* ^$ [/ f4 e3 D: c' [
Order List Statistics# f( w: d3 L H; a3 o/ g
Name Total Cur Average Max Min Av_Time Tot_Back_Ordered8 U. x m6 E4 }: I- E
================================================================================9 X) ^" v1 E6 r# o
OL_1 139 139 67.23 139 0 41789.43 1
, e- k/ P! Y% k7 d1 v$ x$ oOL_2 71 71 34.26 71 0 41693.20 1
! G' J0 b: W s C: KResource Statistics: O6 d8 t P/ r
Name Total Cur Average Capacity Max Min Util Av_Time Av_Wait State ( t" v+ d/ o+ e
====================================================================================================
9 z; o7 |* ?9 K' P9 T' Z2 ]9 `M1 140 0 0.49 1 1 0 0.486 299.67 0.21 Up ----
( u* d+ c, W4 M( P+ L! ]M2 72 0 0.40 1 1 0 0.404 484.99 0.63 Up ---- # |" |1 a. G' l" H
Massm 1 0 0.00 1 1 0 0.003 277.31 0.00 Up ---- % ?$ U0 w4 p1 D
oper 222 1 0.31 1 1 0 0.307 119.62 6.42 Up ----
% \9 ~% J! `8 f- g+ d& N! Y( cRandom Number Streams
6 z# D1 Y; u- {8 pName Total
0 I& @! J: a# r9 a============================
9 n) }4 B- x# sstream0 4550 ~4 S8 G+ Y) W. G" ?( l
stream_M1_1 0& R- z7 ^ I& ]4 H1 S
stream_M2_1 0
, L1 p3 `& E; Istream_Massm_1 04 `7 [! r8 c2 n' l
stream_oper_1 0
6 ~8 b/ N4 a3 ^/ S! h t' Z1 v" dstream_load1_1 184
' {3 W/ O2 H: v [! D$ o5 q7 Wstream_load2_1 76
8 K1 @; O; ^* d tstream_dummy_1 08 M- d& s8 [2 W8 u' {) y. [! t
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请问我的错误在那里?我用的版本是11.1的学生版 |
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