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发表于 2010-5-11 13:19:52
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用list吧9 f/ I# i$ Z! v1 @
patches-own [wealth rank]& U/ ]9 ^0 C2 y- d
to setup
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, C% h, A1 n/ j/ d: B ask patches [set wealth random 100 set pcolor green ]
, ]2 Q' Z7 r( N2 q" K) ?end
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! ]; }! i7 v. F( p$ {8 ^to go
; [* c9 O9 |! U0 \' J let mylist1 []
X0 J0 g* b8 K9 c8 ]" H set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches: Y& L5 k) G+ ~' w
let mylist2 []- L4 g, r! |2 P3 T
set mylist2 n-values count patches [? + 1]
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, G4 _6 m/ J; a8 t0 f3 s ( foreach mylist1 mylist2- T% P# w+ n5 {: |3 `+ J
[ \6 `# T, r/ m9 C# }- y1 T- t
ask ?1[ set rank ?2]
; u) E, c; J2 m) R6 n0 E show [rank] of ?1
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let mylist3 []
" [1 v3 U8 K: S4 D' W, C9 M" N
+ d% ]$ ?" p' Y2 R* _3 m set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
) H3 a2 z' B" j8 I, E3 _3 D; @ show count patches
7 x3 P; W6 S4 n4 p8 K( I" j% h show mylist1 6 e* @4 o+ L5 e0 M
show mylist3# x) O7 K$ H( m- w+ q6 K! |% j
end9 S% R+ {$ S9 Z, l4 `! h8 N" v
% |# m7 ~, [5 M' J* r; ?
这时的mylist1 和mylist3 应该是一样的 |
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