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发表于 2010-5-11 13:19:52
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用list吧4 q9 W0 g l$ @. L+ c% L
patches-own [wealth rank]
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ca
1 c" R: a1 o9 f% A ask patches [set wealth random 100 set pcolor green ]+ d5 N0 ?& Y$ `
end
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to go
* Q5 T" \8 W2 m# R/ s% X2 o( F let mylist1 []
6 H% L0 E1 R$ u, B set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches
& M" q( Y, t# c+ a$ I let mylist2 []* T8 p" ^( @6 J
set mylist2 n-values count patches [? + 1]
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* e/ b, `! G0 d) h2 Z3 M! F! k ( foreach mylist1 mylist2' _" c2 r' Y. M
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ask ?1[ set rank ?2]9 ?% a z. N4 F# R0 \/ ^8 r
show [rank] of ?1
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]
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6 K0 j3 s, r; I; Q, b4 a let mylist3 []
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches* S( A& s2 t4 R8 {1 ~' ~* d
show count patches6 R# }5 N' _4 `' S0 N% L. y. a
show mylist1 8 @; d+ O q7 ]# t( z4 Q" G
show mylist3- N" h" e- }0 o: v* T
end5 n" I$ t+ k' J: x
2 L9 ^& J& q2 Y这时的mylist1 和mylist3 应该是一样的 |
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