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发表于 2010-5-11 13:19:52
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用list吧4 D6 c+ j# L# I) K6 }
patches-own [wealth rank]0 y+ j1 j/ m. _- J- q0 w4 [' n
to setup# U- ?1 y8 ~2 t+ D1 |
ca
' e! f) r7 @: U, @' u8 m ask patches [set wealth random 100 set pcolor green ]/ P, n/ n" Y6 |1 B1 D
end
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2 [$ P2 x* z+ Q let mylist1 []
2 h5 Y: ^( q; L# W set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches4 o5 f& r' y9 \# J" S
let mylist2 []
$ s# V4 ^9 V$ U* h7 N set mylist2 n-values count patches [? + 1]
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# k$ |2 d1 t% c x ( foreach mylist1 mylist2, `+ T- S' C" O8 ^) k2 p4 i
[
$ A8 I/ P% i% S5 c ask ?1[ set rank ?2]
2 Z/ R3 S8 N! V. D1 X) L' o3 y9 d show [rank] of ?1
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]
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let mylist3 []! f* ?6 R! q# {/ V
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set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
! }9 R& Z4 s1 ^9 y0 ~/ w show count patches
' ]# B$ d9 H: T+ j9 W show mylist1 ' X2 R* a# s' z0 u0 @4 K( v
show mylist3
9 `+ ]8 a. J" L7 e4 \4 P% q) P4 uend1 T7 K& G9 y$ k* ]& C0 A
8 }2 V# k+ B/ h# V) p+ y这时的mylist1 和mylist3 应该是一样的 |
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