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发表于 2010-5-11 13:19:52
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用list吧
0 ] f2 s% {/ w) z1 spatches-own [wealth rank]
' f) G w, V$ A3 D/ Z; jto setup8 r. j. N6 a: n: ~
ca8 t; Q% f' J3 y4 r# D; Q
ask patches [set wealth random 100 set pcolor green ]
" f0 C0 o% y+ w; w" ^end
8 N8 K3 m7 W9 T, a4 n/ {* O. C* F; P$ A3 p
to go
1 V/ ]& V5 m& M3 r0 v, f$ B0 n, j let mylist1 []
" k" }' X0 s T U set mylist1 sort-by [[wealth] of ?1 < [wealth] of ?2] patches- ?$ X y4 u' S" s9 ?
let mylist2 []
8 ]% R! N0 f& \ set mylist2 n-values count patches [? + 1]1 w) D' |) _, r/ |
+ X+ g& E# v& _
( foreach mylist1 mylist2
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, A+ d7 n% J7 H" [! x( {& Y$ n ask ?1[ set rank ?2]+ h& i+ [* i( P* N
show [rank] of ?1 R ~- w5 C, F3 L
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)3 T; Q) C1 r1 f Y; z
let mylist3 [] Z5 e/ e1 n0 b8 G3 _
5 m* N- k, _* s1 r5 _* ? set mylist3 sort-by [[rank] of ?1 < [rank] of ?2] patches
$ {# R: i9 n+ u- [. F/ s show count patches+ l Y% g, U9 y
show mylist1
0 U6 Q4 j8 i0 g show mylist3
4 w- s8 p. A% ?4 k0 [: |end
k" c2 @* E8 _( y8 a# X& Q1 N1 x& v! g# g% D$ G+ y0 N; }% _
这时的mylist1 和mylist3 应该是一样的 |
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